modulus multiplication

★ Intro in the previous two, Comba multiplication was introduced, and finally it was mentioned that when the size of the input was large, the computational time required increased sharply because the time complexity of the Comba multiplication was

1. Defects of large number modulus exponentiation: the introduction of fast power modulus algorithm is proposed from the limitation of the naïve algorithm of large number of decimal modulus, in the naïve method we calculate a number such as 5^1003%31

First, insert the assembly1#include 2 3 voidMain () {4 intnum=Ten;5num=num+5;6 //Insert assembly Language7 _asm{8MOV eax,num;//EAX is a memory that moves the value of num to EAX9add eax,5 //eax value +5TenMOV num,eax//EAX value assigned

On the website has not found a detailed description and explanation of the fast power algorithm, here, I give a full explanation of the fast power algorithm, with the C language, the readers of different languages have to change bits, after all,

Sumdiv Time limit:1000 ms   Memory limit:30000 K Total submissions:16109   Accepted:3992 DescriptionConsider two natural numbers a and B. Let s be the sum of all natural divisors of a ^ B. Determine s modulo 9901 (

The fast power algorithm can be said to be a kind of ACM competition is necessary, and is also a very basic type of algorithm, given that I have been learning more fragmented, so today with this post summed upFast multiplication usually has two

As the name implies, it is a fast calculation of the number of times the power. Its time complexity is O (log₂n), and the Simplicity of O (N) compared to the efficiency has been greatly improved. The following is to introduce the B to a binary. The

If X exists in numbers A and C and A * x = 1 (mod C), X is called the multiplication inverse element of A to C.What is the role of reverse element? Let's take a look at the following example:12/4 mod 7 =? Obviously, the result is 3.For the number

DescriptionAsk for ∑∑ ((n mod i) * (M mod j)) where 1　　InputThe first line is two numbers n,m.OutputAn integer representing the value of the answer mod 19940417Sample Input3 4Sample Output1Sample DescriptionThe answer is (3 mod 1) * (4 mod 2) + (3

title :The King of electrical tones The following:Finding the first n Xiangxiang multiplication and modulus of a sequence Ideas :①, the multiplication of this problem is a long long , can be solved by the idea of fast power (according