mumps programming language tutorial

/******************************************************************** @file main.cpp@date 2017-05-28 22:02:55@au Thor Zoro_tiger@brief Problem 1041:c Language Programming Tutorial (third Edition) after class exercise 9.8http://www.dotcpp.com/oj/problem1041.html********************************************************************/#include#include#defineTEST#undefTE

/******************************************************************** @file main.cpp@date 2017-05-28 22:10:10@au Thor Zoro_tiger@brief Problem 1042:c Language Programming Tutorial (third Edition) After class exercise 9.10http://www.dotcpp.com/oj/problem1042.html********************************************************************/#include#include#defineTEST#undefT

/******************************************************************** @file main.cpp@date 2017-5-26 09:36:10@aut Hor Zoro_tiger@brief Problem 1031:c Language Programming Tutorial (third Edition) after class exercise 8.5http://www.dotcpp.com/oj/problem1031.html********************************************************************/#include#include#includestring>#incl

/******************************************************************** @file main.cpp@date 2017-5-25 09:45:52@aut Hor Zoro_tiger@brief Problem 1030:c Language Programming Tutorial (third Edition) after class exercise 8.4http://www.dotcpp.com/oj/problem1030.html********************************************************************/#include#include#defineTEST#undefTES

I plan to graduate school: The University of Beijing University of Technology-computerCourse Number 985: Textbook for C language programming case tutorials and Min data structure that bookNow begin to review the C language, plan to write the following part of the code to write the title onceNot regularly with the new one week later======================== the sec

1353:c Language Programming Tutorial (third Edition) After class exercise 10.4 time limit:1 Sec Memory limit:128 MBsubmit:296 solved:219[Submit] [Status] [BBS] Description have n integers, so that the previous number of sequential moves backward m position, the last m number into the first number of M, see figure. Write a function: To achieve the above f

/******************************************************************** @file main.cpp@date 2017-05-07@author Zor O_tiger@brief Problem 1006:c Language Programming Tutorial (third Edition) after class exercise 5.4http://www.dotcpp.com/oj/problem1006.html********************************************************************///! Header file#include #include//! Macro De

/******************************************************************** @file main.cpp@date 2017-5-11@author Zoro _tiger@brief Problem 1016:c Language Programming Tutorial (third Edition) after class exercise 6.6http://www.dotcpp.com/oj/problem1016.html********************************************************************/#include#include#defineTEST#undefTESTintMaini

/******************************************************************** @file main.cpp@date 2017-06-01 12:17:46@au Thor Zoro_tiger@brief Problem 1047:c Language Programming Tutorial (third Edition) After class exercise 10.5http://www.dotcpp.com/oj/problem1047.html********************************************************************/#include#defineTEST#undefTESTintMa

/******************************************************************** @file main.cpp@date 2017-05-29 12:55:07@au Thor Zoro_tiger@brief Problem 1043:c Language Programming Tutorial (third Edition) After class exercise 10.1http://www.dotcpp.com/oj/problem1043.html********************************************************************/#include#include#include#defineTES

/******************************************************************** @file main.cpp@date 2017-5-26 09:45:32@aut Hor Zoro_tiger@brief Problem 1032:c Language Programming Tutorial (third Edition) after class exercise 8.6http://www.dotcpp.com/oj/problem1032.html********************************************************************/#include#include#includestring>#incl

].birthday.month, S[i].birthday.day, - s[i].department, s[i].major); WuPutchar ('\ n'); - } About } $ - voidSearchInfo (Studentinfo s[], date date) - { - inti; A for(i =0; i ){ + if(s[i].birthday.month>date.month) { theprintf"\n%4d%16s%2d/%2d", S[i].num,s[i].name, S[i].birthday.month, - s[i].birthday.day); $ Continue; the } the if(S[i].birthday.month = = Date.month s[i].birthday.day>date.day) { theprintf"\n%4d%16s%2d/%2d", S[i].num, S[i].name, S

parameter. Call to function The basic format of the function call statement is: The The parameters in the Example: 1 intdataarray[ -];2 intN;3 DoubleAve;4 5 //Custom Functions6 DoubleAverageintValue[],intnum) {7 intI, sum =0;8 for(i =0; i ){9Sum + =Value[i];Ten returnsum*1.0/num; One } A } - - //function Call theAve = Average (DataArray, n);Application examples of custom functions Output multiplication Ta

Title DescriptionFor the sum of the following three digits, the sum of 2 decimal 1~a and the reciprocal of the square and 1~c of the 1~b are reserved.InputA b COutput1+2+...+a + 1^2+2^2+...+b^2 + 1/1+1/2+...+1/cSample input100 50 10Sample output47977.93TipsNote the output format, do not output extra space!Source#includemain(){int i,a,b,c;float s=0;scanf("%d%d%d",a,b,c);for(i=1;is+=i;for(i=1;is+=i*i;for(i=1;is+=1.0/i;printf("%.2f\n",s);}1016:c Language

Problem DescriptionThis day the teacher gave small Hao a very simple topic relaxed: Enter a score, let you find their simplest score. InputThe first line includes a T, which represents the number of groups of test data.The next line of T lines includes a fraction. (The numerator denominator is within the int range)OutputFor each test sample, the output line has its simplest fraction.Sample Input32/63/111/36Sample Output1/33/111/36My Code:1#include 2ProcessintAintb/*greatest common divisor, so th

Problem DescriptionBeg sn=2+22+222+...+22 ... A value of 222 (with N 2). For example: 2+22+222+2222+22222 (n=5), n is entered by the keyboard.InputNOutputAndSample Input5Sample Output24690My Code:1#include 2 voidMain ()3 {4 intN,a=2, t,sum=0, I;5scanf"%d",n);6t=A;7 for(i=1; i)8 {9sum=sum+T;Tent=t*Ten+A; One } Aprintf"%d", sum); -}Other code:1#include 2 3 using namespacestd;4 5 intMain ()6 {7 Longsum=0;8 intt=2;9 intN;TenCin>>N; One for(intI=0; ii) A { -Sum + =T;

Problem DescriptionThe teacher gave a title to Xiao Hao: give you two integers x and n ( -10now that little Howe is in a quandary, please help him solve the problem. InputEnter two integers x and n per line.Outputfor each set of test data, the output line evaluates. Sample Input1 12 2Sample Output16HINT1#include 2 3 4 Long LongSumintXintN)5 {6 Long Longs=0;7 inti,j;8 Long LongS1;9 for(i=1; i)Ten { Ones1=1; A for(j=1; j) - { -s1*=x; the } -s+=S1; - } -

Problem DescriptionThe output Yang Hui the first n rows of the triangle.InputEnter a number n (n OutputThe output Yang Hui the first n rows of the triangle. (Note that there is no extra space at the end of the line, the number is output in%3d format)Sample Input34Sample Output 1 1 1 1 2 1 1 1 1 1 2 1 1 3 3 1HINTNote that there are multiple sets of inputs. Output a blank line after each set of test data.while (scanf ("%d", n)! = EOF){......}1#include 2 i

Problem Descriptionn individuals in a circle, numbered from 1 to n sequentially. From the person numbered 1 starts 1 to K, where the number of people who count K out of the circle, the output of the last left a person's original numbers.InputFirst enter a T, which indicates that there is a T group of data (1Then there are t-lines, each with 2 positive integers n and K. (1OutputFor each set of test data, output a number that represents the number of the last person left.Sample Input310 37 15 4Sam

Problem DescriptionEnter n (nInputExample of multi-group test sample. The first row of each group has an integer n indicating that there are n strings. Next there are n rows, one string per line.OutputOutput a sequential string, with each line outputting a string.Sample Input3abaaabcabSample OutputAababacab1#include 2#include string.h>3 voidSortChar* str[],intsize)4 {5 inti,j;6 Char*tmp;7 for(i=0; i1; i++)8 {9 for(j=i+1; j)Ten { One if(strcmp (str[i]