notepad alphabetical order

Native SQL notation:SELECT *From br_esf_village_buildingWHERE 1ORDER by CONVERT (' Buildingname 'USING GBK)COLLATE Gbk_chinese_ci ASCThe notation of the TP framework:$data = $this->where ($where)->field ($field)->order (' CONVERT (' buildingname ' USING gbk) COLLATE Gbk_chinese_ CI ASC ')->select ();This article is from the "php/[email protected]" blog, be sure to keep this source http://liang3391.blog.51cto.com/178205/1871232MySQL first

Some netizens posted this issue on 51js today. I thought it was to sort the content in alphabetical order, because I have read an article in the forward order. ArticleI thought it would be difficult to sort the data in reverse order. After checking the information, the problem was quickly solved.

Some netizens posted this question on 51js today. I thought it was to sort the content in alphabetical order. Because I have read a forward-ordered article before, I think it should be difficult to reverse-order it, after checking the information, the problem was quickly solved. [Ctrl + A select all Note: If you need to introduce external Js, You need to refresh

PHP Face question Description: Example: My name is Fanglor = "ym Eman si Orlgnaf Answers to the PHP interview questions: Copy the Code code as follows: function Restr ($STR){$str 1 = Explode ("', $str);$str 2 = ";$temp = ";for ($i =0; $i {$str 2. = $temp. Strrev ($str 1[$i]);$temp = ";}return $STR 2;} Test code: Copy the Code code as follows: $str = "My name is Fanglor";echo Restr ($STR); Printing results: Ym Eman Si Rolgnaf The above describes the PHP code in

Oracle alphabetical order with Chinese pinyin first letter functionAccording to the Chinese pinyin first alphabetical order, obtains the Chinese Pinyin first letter functionThe first letter, stroke and radical sort function "Nlssort" are introduced according to Chinese characters:1), First letterSELECT * from T_table

Chinese character, we simply subtract 19968 from the Unicode code of the kanji (that is, the char is cast to int) and use this number as an index to find the letters stored in the char array.So, with this char array as the base, everything becomes very simple:Char pinyinfirstletter (unsignedshort Hanzi){int index = Hanzi-hanzi_start;if (index >= 0 index {Returnfirstletterarray[index];}Else{return Hanzi;}}As for the sort, we can put the sort of Chinese (for simplicity, we assume that these sorts

The question test instructions clear, that is, given a set of letters of the size of the relationship to determine whether they can form a unique topological sequence. is a typical topological sort, but there are three types of output formats:1. The letter sequence is ordered and output sequentially;2. The sequence does not determine whether it is orderly;3. There is a contradiction between the sequence alphabetical

Previously, a requirement was made to sort by the pinyin of the person's name, then NLS_SORT sorted in the background through the parameters of Oracle, and then returned the results to the front end. Now want to see if the front-end pairs of strings in alphabetical order what should be done? To find the information, the method is recorded as follows.[‘张三‘,‘李四‘,‘王五‘].sort((a,=>a.localeCompare(b,‘zh-Hans-CN‘,

For example, give a specific alphabetical order, "a", "O", "E", "U", "Y", "I", please sort the 7 strings of ' Aiye ', ' oeu ', ' ayo ', ' Eoyiu ', ' yuo ', ' You ', ' Iao ' in the given alphabetical order. My idea is to give those 6 letters equivalent to 0-5, and then replace the letters in the 7 strings with the numb

Complete with pointer array: Several strings are output in alphabetical order # include The "C language" is done with an array of pointers: output several strings in alphabetical order

For example, give a specific alphabetical order, "a", "O", "E", "U", "Y", "I", please sort the 7 strings of ' Aiye ', ' oeu ', ' ayo ', ' Eoyiu ', ' yuo ', ' You ', ' Iao ' in the given alphabetical order. My idea is to give those 6 letters equivalent to 0-5, and then replace the letters in the 7 strings with the numb

Map has its own sort function, but it needs to rewrite the sorting method, the code is as Follows: packagecoreJava.com.shindo.corejava.map;Importjava.util.ArrayList;Importjava.util.Collections;Importjava.util.Comparator;Importjava.util.HashMap;Importjava.util.List;Importjava.util.Map;Importjava.util.Map.Entry; public classMapsort {/*** * @Title: sortmap * @Description: sort the data in the collection alphabetically by key*/ publiclistFinalmapMap) { FinallistNewarraylist(map.entryset (

Java Object instanceof keyword exercise: judge whether the set of the same person is sorted by age. If the same age is sorted by name in alphabetical order, Comparator, Package com. swift; public class Same_Person_Test {public static void main (String [] args) {/** Object determines whether the Object is the same Person */Person per1 = new Person ("zhangsan", 30 ); person per2 = new Person ("lisi", 27); Per

, here is the option to use Chinacomparatorcomparator=collator.getinstance ( Java.util.Locale.CHINA);string[]arrstrings={ "AA", "AA", "11", "Side dish", "Mirror flower 8 Water Month 90", "www.noreplace.com", "flower is not right", "mirror flower 7 Water Month 90", "little silly" };// causes the specified array of objects to be sorted according to the order produced by the specified comparer. arrays.sort (Arrstrings,comparator);for (inti=0;i The above

Recently interested in recursive comparisons, so began to record some of the learning process of recursive use method1. The full permutation function (arrange) has two parameters one is a string that needs to be fully arranged (assuming the default is in dictionary order) and the other is the accumulated prefix such as:The first time by default is 'The second time, after the For loop, represents 1, 2, 3, and is the prefix parameter for the next sub-re

Sort () Localecompare () sort () uses the sort () function to sort the array objects used, the collation installs the character encoding order, such as: (cannot be directly compared to Chinese) var arr = new Array (6); Arr[0] = "arr[1" = "1" arr[2] = "8" arr[3] = "+" arr[4] = "" "Arr[5" = "1" Arr.sort (), return:1,1,1000,23,25,8, sort by first value sort has one parameter to set collation, Arr.sort (sortnumber), parameter is method name, sort metho

var obj = {name: "Zhangsan", Age:8, Ace:5, NBME: "Lisi"};//the object to sortfunction Objkeysort (obj) {//Sort var newkey = Object.keys (obj). sort ();Use the Keys method of the object's built-in class to get the property names of the objects to sort, and then use the Sort method on the array prototype to sort the obtained property names, Newkey is an array var newObj = {};//Creates a new object for storing sorted key-value pairs for (var i = 0; i Newobj[newkey[i]] = obj[newkey[

C language: Bubble Sorting: sorts several strings in alphabetical order (from small to large) and outputs them # Include # Include Void sort (char * a []); void print (char * a []); int main () {char * a [] = {"ceo", "define ", "basic", "abc", "empty"}; printf ("the original sequence is \ n"); print (a); sort (); printf ("\ n: \ n"); print (a); printf ("\ n"); return 0 ;} void sort (char * a

/* C language: enter a string of n characters on the keyboard, and then output the n characters in alphabetical order */ # Include # Include Main (){ Char * STR;Char * P1, * P2; Printf ("input a string:/N ");Scanf ("% s", STR ); P1 = STR;/* First */P2 = p1 + 1;/* Second */; While (* P1! = '/0 '){While (* P2! = '/0 '){Char TMP;TMP = * P1; If (* P1> * P2)/* If You Want To output from large to small characte

G65sc802 and g65sc816 instruction sets (in alphabetical order) 　 Hdw1978 provided (Thanks very much for the second contribution made by hdw1978. -- Compilation studio) --------------------------------------------------------------------------------- // The following commands, without special instructions, always use the memory value and the accumulators value (two-operand command), memory or accumulators