online jailbreak 9 3 5

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Algorithm: 1! + (1!) +3! ) + (1!) +3! +5! + (1! + 3! + 5! + 7! + 9!) + .... + (1!) +3! +5! + ... + m!)

-(void) Touchesbegan: (nonnull nssetAlgorithmic entry[Self func2:9];}Calculate factorial factor (m) = m!-(int) factor: (int) m{int factornum=0;if (m==0|m==1)return 1;else{Factornum=m*[self Factor:m-1];NSLog (@ "%d", factornum);return factornum;}}Calculate Func1 (m) = 1! +3! +5! + ... +m!-(int) func1: (int) m{int sum=0;for (int i=1; iSum +=[self factor:i];}NSLog (

Using regular expressions to implement the Operation Express = ' 1-2* ((60-30 + ( -40/5) * (9-2*5/3 +7/3*99/4*2998 +10 *568/14))-( -4*3)/(16-3*2)) '

#!/usr/bin/env python# Coding:utf-8Import Redef Dealwith (Express): Express.replace ('+-','-') Express.replace ('--','+') returnexpressdef Col_suanshu (exp):if '/' inchexp:a,b= Exp.split ('/') returnStrfloat(a)/float(b))if '*' inchexp:a,b= Exp.split ('*') returnStrfloat(a) *float(b) def get_no_barcate (Express): Express=express.strip ('()') Print ('>>>', Express) whileTrue:ret= Re.search ("-?\d+\.? \d*[*/]-?\d+\.? \d*", Express)ifRet:res=Col_suanshu (Ret.group ()) Express= Ex

[Programming question] calculates the longest descending subsequence of an array, for example, {9, 4, 3, 2}. The longest descending subsequence is {9, 5, 4, 3, 2}

47. Innovation workshop (algorithm ):Returns the longest descending subsequence of an array, for example, {9, 4, 3, 2, 5, 3, 2,4,3, 2} Idea: Dynamic Planning Calculates the longest descending subsequence of the sequence of the current number. Each time you look for the longest child sequence, scan the child sequence o

Output 1/3-3/5 + 5/7-7/9 ...... + 19/21 results

Content on the machine: accumulate data using cyclic statements. Objective: To learn how to use cyclic statements. /** Copyright (c) 2012, Emy of computer science, Yantai University * All rights reserved. * Prepared by: Li Yang * completion date: January 1, November 01, 2012 * version No.: v1.0 * enter the description: none. * Problem description: the result of 1/3-3/5

JS in sum (2) (3) (4) returns 9 and sum (2,3) and SUM (2) (3) both return 5 and require extensibility

There are many online questions about sum (1) (2) (3), SUM (All-in-one) that require the same result 6 and requirements can meet the extension, that is, there are multiple parameters can also meet the requirements of the problem, so I wrote some examples can meet the requirements of these surface questions JS in sum (2) (3) (4) returns

Summarize the recent development of CNN Model (i)----ResNet [1, 2] Wide ResNet [3] resnext [4] densenet [5] dpnet [9] nasnet [ten] senet [one] Capsules [12]

Summarize the recent development of CNN Model (i) from:https://zhuanlan.zhihu.com/p/30746099 Yu June computer vision and deep learning1. PrefaceLong time no update column, recently because of the project to contact the Pytorch, feeling opened the deep learning new world of the door. In his spare time, Pytorch trained the recent CNN model of State-of-the-art in image classification, which is summarized in the article as follows: ResNet [1, 2] Wide ResNet [

1 2 3 4 5 6 7 8 9 = 110, fill in the plus sign or minus sign between the numbers (you can leave it blank, but cannot enter other symbols) to make the equation true.

There are 3 ^ 8 possibilities. Answer: Success: 12 + 34 + 56 + 7-8 + 9 = 110 Success: 12 + 3 + 45 + 67-8-9 = 110 Success: 12-3 + 4-5 + 6 + 7 + 89 = 110 Success: 1 + 2 + 34 + 5 + 67-8 +

Career Success factors: 1 goal, 2 basis points, 3 tips, 4 ideas, 5 points of luck, 6 Requirements, 7 points of learning, 8 points of communication, 9 points of habits, 10 points of self-confidence, 11 traps, 12 points of effort

: before the age of 35, you must train your speech skills. Many successful people are first of all excellent speakers. Chapter 9: 9 habits The power of habits is amazing. The habits you developed before the age of 35 determine the size of your success.1. Good habits of positive thinking.2. develop a good habit of efficient work-learn to like and get used to your office; be cautious in your life, but b

Features that can be divisible by 2, 3, 4, 5, 6, 7, 8, and 9

from the remaining number, if the difference is a multiple of 7, The original number can be divisible by 7. If the difference is too big or it is difficult to see whether it is a multiple of 7, we need to continue the process of "tail truncation, doubling, subtraction, and verification" until we can clearly determine whether it is possible. For example, the process of judging whether 133 is a multiple of 7 is as follows: 13-3 × 2 = 7, so 133 is a mul

Career Success factors: 1 goals, 2 basis points, 3 skills, 4 ideas, 5 points of luck, 6 requirements, 7 points of study, 8 points of communication, 9 habits, 10 points of confidence, 11 traps, 12 points of effort "excerpt"

positive thinking.2. Develop a good habit of working efficiently--learn to like and get used to your office; Life can be informal, but work must be cautious; Learn to listen and not interrupt others to speak.3. Develop a good habit of exercising your body.4. Good habits of a wide range of hobbies.5. Good habit of quick action. The Tenth chapter: very confident1. Self-confidence is the spiritual pillar of

The characteristics of the number of "fun arithmetic" that can be divisible by 2, 3, 5, 7, 9, 11, 13

number is 383, the difference between the two numbers is: 383-357=26,26 can be divisible by 13, therefore, 383357 must be divisible by 13.This method also applies to judging whether a number can be divisible by 7 or 11. such as: 283679 of the last three digits is 679, the last three digits of the previous number is composed of 283,679-283=396,396 can be divisible by 11, therefore, 283679 must be divisible by 11. Still take the original number as an example, the difference between the last three

Output a m * n matrix in the following regular order: line1: 1 6 7 line2: 2 5 8 line3: 3 4 9

Output an M * n matrix arranged according to the following rules.1 6 72 5 83 4 9 Analysis: The key is to find out the matrix rules. on the Internet, the analysis is as follows: Set behavior I, column J 1 2 M 2 m + 1 4 M 4 m + 1 6 m .. 2 m + M-1 2 m + 2 4s-1 4 m + 2 6s-1 .. 3 ........ ........ M m + 1 2 m + M 3 m +

Check the operating system version: Must be redhat-3, SuSE-9, SuSE-10, redhat-4, redhat-5, redhat-6, UnitedLinux-1.0, Asianux-1, As____linux

[Root@mypc disk1]#./runinstaller Starting Oracle Universal Installer ...Checking Setup requirements ...Check operating system version: Must be redhat-3, SuSE-9, SuSE-10, redhat-4, redhat-5, redhat-6, UnitedLinux-1.0, Asianux-1, Asianux-2, Asianux-3, E Nterprise-4, enterprise-5

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