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According to the prompt "compile OpenOffice (3) under Ubuntu", enter:./Bootstrap Enter: source LinuxX86Env.Set.sh Or source LinuxX86-64Env.Set.sh Then you can make it !! I am using the sudo make command directly here! Compilation errors: ####### Error 1:Copy libgcc_s.so.1 to ../unxlngi6.pro/lib/Bin/CP: cannot stat 'libgcc _ S. so.

Press "Enter" button to enter the Raid editing window, in the editing window can set the mode of RAID, it is important to note that many RAID cards for the user-provided mode is used in the storage mode expression, wherein "Stripe" Bar storage is RAID 0 mode; " Mirror "represents RAID 1, while" Mirror/stripe "represents the raid0+1 mode. The user can switch the

As the question, I am engaged in a little mixed, who can be careful to talk about: 1, composer psr-0 and psr-4 In the difference; 2, psr-0 specifications and psr-4 specifications of the difference; 3. composer and php-fig. For example, I am a bit confused. Who can tell me ca

Title, I'm a little confused, who can say it carefully: 1, the difference between psr-0 and psr-4 in composer; 2, the difference between the psr-0 norm and the psr-4 norm; 3, composer and Php-fig, who indulge who. Reply content: Title, I'm a little confused, who can say

$arr= [1, 2,-4, 4, 10,-23, 4,-5, 1]; $max _sum= 0; $sum=0; $new= []; $i= 1; Echo' ; foreach($arr as $key=$value ){ if($sum){

# Include Int main (void){Int A [100] [200]; Printf ("% d \ n", A [0] [1], A [0] [0], A [0] [1]- A [0] [0]);Printf ("% x % d \ n", A

"Code"""" all elements greater than 0 are converted to 1 """ = Np.array ([[1, 2, 3, 4]])print(" pre-conversion:")Print (np_arr)print(" after conversion:")print"Result"before conversion:[[1 2 3 4]] after conversion: [[

51nod 1090 3 count and 0 amp; 51nod 1267 4 count and 0 (marked as binary) Question meaning: The sum of 3 is 0: An unordered array with the length of N is given. The elements in the array are integers, positive and negative values include 0, and they are not equal to each o

Input 1: Output 0; input 0: Output 1 I had an interview that day. I encountered such a problem: input 0, output 1, and input 1, and output 0

two number and stored in the array B, to sort a (the original array) and B array, to determine a[i=0]+b[j= (n (n-1))]=0?, if three number 22 and equal to 0, then to the result array, (guaranteed output results are not duplicated), The final output result set. See the code, write a bit messy, hope forgive me!AC Code:Fo

To get this topic, we will first think of using loops to complete.But not every operator is a "+" sign.Therefore, we are here to use (-1) of the I-side to do "+" "-" number control.The loop variable i is then treated as the denominator.Here we have the idea of the loop body is basically OK.It is important to note that the calculation results here are expressed in decimals, so it is not possible to define variables with int integers.The code is as foll

http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1393The method is fascinating. Also looked at other people's thinking to come out.First consider turning 0 all into-1. Then a prefix is counted and expressed in sum[i].Then the substring starting from the starting point is valid as long as the value of Sum[i] equals 0.If the substring starting point is