# openoffice 4 1 4

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### An array of integers and the largest contiguous subarray, for example: [1, 2,-4, 4, 10,-3, 4,-5, 1] The largest contiguous subarray is [4, 10,-3, 4] (to be stated and programmed)

\$arr= [1, 2,-4, 4, 10,-23, 4,-5, 1]; \$max _sum= 0; \$sum=0; \$new= []; \$i= 1; Echo' ; foreach(\$arr as \$key=\$value ){ if(\$sum){ unset(\$new[\$i]); \$i++; \$sum=\$value; }Else{ \$sum+=\$value; } \$new[\$i][] =\$valu

### Compile OpenOffice (4) in Ubuntu)

According to the prompt "compile OpenOffice (3) under Ubuntu", enter:./Bootstrap Enter: source LinuxX86Env.Set.sh Or source LinuxX86-64Env.Set.sh Then you can make it !! I am using the sudo make command directly here! Compilation errors: ####### Error 1:Copy libgcc_s.so.1 to ../unxlngi6.pro/lib/Bin/CP: cannot stat 'libgcc _ S. so.

### C language computing 1/1-1/2 + 1/3-1/4 + 1/5-... + 1/99-1/100

C language computing 1/1-1/2 + 1/3-1/4 + 1/5-... + 1/99-1/100Calculate

### Implemented in C: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value.

To get this topic, we will first think of using loops to complete.But not every operator is a "+" sign.Therefore, we are here to use (-1) of the I-side to do "+" "-" number control.The loop variable i is then treated as the denominator.Here we have the idea of the loop body is basically OK.It is important to note that the calculation results here are expressed in decimals, so it is not possible to define variables with int integers.The code is as foll

### The "C language" calculates the value of 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100.

Note: When calculating 1 to use a double type that is 1.0 . Odd even numbers are calculated separately and then merged. #include Label control +1,-1 with flag. #include Use the Function Pow Pow ( -1,i+1) equivalent ( -

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### Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

#include Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

### Use the for and while loops to calculate the value of e [e = 1 + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! +... + 1/n!], While

Use the for and while loops to calculate the value of e [e = 1 + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! +... +

### C language: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

#include Be careful to define its type, divide it into two parts, and define it as "I" to see if the denominator is an odd or even number, and the sum is summed. C language: Calculate 1/1-1/2+1/3-1/4+

### Read "c ++ primer" thin (4-1 c and c ++ arrays), "cprimer" 4-1

Read "c ++ primer" thin (4-1 c and c ++ arrays), "cprimer" 4-1 Supervise reading, summarize the essence, extract notes, and inspire others. If you have any questions, leave a message to correct them. Arrays and pointers of c and c ++ belong to low-level Composite data types, such as arrays of c ++, similar to vector co

### Compile a function. When n is an even number, call the function to calculate 1/2 + 1/4 +... + 1/n. When n is an odd number, call the function 1/1 + 1/3 +... + 1/n ., Even number

Compile a function. When n is an even number, call the function to calculate 1/2 + 1/4 +... + 1/n. When n is an odd number, call the function 1/1 + 1/3 +... +

### Java divides the memory into 4 parts 1. Code area 1, Stack area 3, heap 4, static zone

1, the stack area (stacksegment)-Automatically allocated by the compiler release, stored function parameters value, local variable value, etc., the system automatically releases the JVM memory resources after the execution of the method is completed.2. Heap area (heapsegment)-typically released by programmers, storing objects and arrays created by new, the JVM does not periodically view this object, and if no reference points to the object, it is recy

### MOOC-android engineers-1-4 exercises, Android-1-4

MOOC-android engineers-1-4 exercises, Android-1-4 Source http://www.imooc.com/ceping/1474 Run a Java program Test. class on the console. Which of the following statements is true () AJava Test. class BJavac Test. class CJava Test DJavac Test Answer: CKnow

### Common regular expressions-supplement the regular expression of 1 phone number (mobile phone number, 3-4 area code, 7-8 live video number, 1-4 extension code)

Regular Expression of phone number (mobile phone number, 3-4 area code, 7-8 live video number, 1-4 extension code) (\ D {11}) | ^ (\ d {7, 8}) | (\ d {4} | \ d {3})-(\ d {7, 8 }) | (\ d {4} | \ d {3})-(\ d {7, 8 }) -(\ d {4} | \ d

### JQuery Learning (4-1) and jquery learning 4-1

JQuery Learning (4-1) and jquery learning 4-1 Set the form control, mainly including 'verifymail', 'judge whether the input is empty ', and 'set tabindex attribute' \$ (Document ). ready (function () {/* modal windows */\$ ('a. modal '). click (function () {var modalID = \$ (this ). attr ('rel '); // get the name of the

### 2018-1-44 weeks 3 lessons VIM 2

numbers: ↑ Last used command: Nohl highlighted words, not highlighting hints: x save exit, change file is similar to Wq; File Open is not operational, change mtime: 1,100s/dnsmasq/aminglinux/g from line 1th to line 100, s means start substitution, replace DNSMASQ with aminglinux,g to replace all1, \$s/\/etc\/hosts\//aminglinux/g replace/etc/hosts/with Aminglinux, escape with \ or 1, \$s #/etc/hosts/#aminglinux/g or @ symbol delimitedSet NU Display line

### C language: calculate the value of Polynomial 1-1/2 + 1/3-1/4 +... + 1/99-1/100, three types of cyclic implementation

C language: calculate the value of Polynomial 1-1/2 + 1/3-1/4 +... + 1/99-1/100, three types of cyclic implementation Method 1: for Loop Im

### Formula for calculating pi pai: Pai = 4* (1-1/3+1/5-1/7 ...)

There are many formulas for calculating pi pai in history, in which Gregory and Leibniz found the following formula: Pai = 4* (1-1/3+1/5-1/7 ...) The formula is simple and graceful, but in a bad way, it converges too slowly. If we rounded to keep its two decimal digits,

### Thunder programming questions: programming: Find a number in addition to 2 + 1 In addition to 3 + 2 in addition to 4 + 3 in addition to 5 + 4 in addition to 6 + 5 in addition to 7 + 0

Package com; public class test {public static void main (string [] ARGs) {system. out. println (getsteps1 (); system. out. println (">>>>>>>>>>>>>>>>>>>>>>>>>>>>"); system. out. println (test. getsteps (); system. out. println (">>>>>>>>>>>>>>>>>>>>>>>>>>>> ");} public static int getsteps () {// use the minimum public multiple to reduce the number of traversal times. Int I = 1; int step = 2; Boolean maxstep = false; while (true) {system. Out. Print ("

### Question 8: f = 1! -1/2! + 1/3! -1/4! +... + 1/n! (N is a large number. If n is too large, it will overflow)

/*************************************** ************************Accumulated (C language)AUTHOR: liuyongshuiDATE :************************************************ ***********************//*Question 8: f = 1! -1/2! + 1/3! -1/4! +... + 1

### There are 4 threads A, B, C, D, respectively printing 1, 2, 3, 4, please start them at the same time, but required to output the results in 1234 order

1. There are 4 Threads a,B,C,D, print separately 1,2,3,4, please start them at the same time, but require to follow The sequential output of the 1234. public class TestABCThread3 {Private Object lock = new Object ();private int count;public static void Main (string[] args) {TESTABCTHREAD3 ABC = new TESTABCTHREAD3 ();New Thread (Abc.new Run ("C", 3)). Start ();New Thread (Abc.new Run ("D",

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