ordinal day

int y, d, M;int m1 = to, M2 = 31, M3 = To, M4 =, M5 = To, M6 =, M7 = to, M8 = to, M9 =, M10 =, M11 =--M12Console.WriteLine ("Please enter the Year");y = Convert.ToInt32 (Console.ReadLine ());If (y% 400 = = 0 | | (y% 4 = = 0 && y% 100! = 0)){m2 = 29;}

The Python new code is as follows:year = Int (input (' Please enter years: '))momth = Int (input (' Please enter month: '))day = Int (input (' Please enter Number '))if (year% 4 = = 0 and year%! = 0) or (year% 400 ==0):if momth = = 1:Print (day)Elif

Defines a struct variable (including year, month, and day) that requires the input of the year, month, and day, which is the day ordinal of the year./** Copyright (c) 2014, Yantai University School of Computer * All right reserved.* Shao * file:

1, write the program, the user presses "YYYY-MM-DD" format to enter a date, the program after the output of the day is the days of the week, and calculated is the first day of the year. The following code is attached: Calculated week using the:

"python exercise 004" Enter a certain day of the year, judging the day is the first of the year?----------------------------------------------This problem actually wrote 28 lines of code! It also does not include validation of the input data (only

Http://www.cnblogs.com/vamei/archive/2012/07/19/2600135.htmlPython small topic for quick tutorial Job answerWrite a program to determine if 2008 is a leap year.Write a program that calculates October 1, 2008 is the day of the year? (January 1, 2008

This index value in addition to the instant Noodles data recording and searching, but also plays the role of date information, the amount of information is considerable. So how do you restore the index value to date information that is

3. Judgment date is the day of the yearParameter return value resolution:Parameters:Y:int, year;M:int, MonthD:int, datereturn value:Sum: The day of the year in which the incoming date is;Function parsing:leapyear(y); Judge y is not a leap year,

Three ways to iterate through the list of numbers and values: Recently learn the language of Python, feel its work efficiency has a great improvement, special on Valentine's Day wrote this blog, the following nonsense say, direct sticker code

#include #include /* enter month and date, the day of the year that the output is dated. Year greater than 1900*/int monthdays[12] = {N, a, A, a, a, a, a, a, a, a, a, a};int isgoodyear (int year); int Isgoodmont H (int month), int isgoodday (int