outlook osu

Label: ACM Osu! Problem descriptionosu! Is a very popular music game. Basically, it is a game about clicking. Some points will appear on the screen at some time, and you have to click them at a correct time. Now, you want to write an algorithm to estimate how diffecult a game is. To simplify the things, in a game consisting of n points, point I will occur at time TI at Place (XI, Yi), And You shoshould click it exactly at TI at (XI, yi ). that mea

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5078 Osu! Time Limit: 2000/1000 MS (Java/others) memory limit: 262144/262144 K (Java/Others)Total submission (s): 180 accepted submission (s): 114Special Judge Problem descriptionosu! Is a very popular music game. Basically, it is a game about clicking. Some points will appear on the screen at some time, and you have to click them at a correct time. Now, you want to write an algorithm

HDU 5003 Osu! Question Link Just sign in and sort the questions and calculate the answers once. Code: #include HDU 5003 Osu! (Anshan Network Competition g)

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5003 Problem descriptionosu! Is a famous music game that attracts a lot of people. In Osu !, There is a performance scoring system, which evaluates your performance. each song you have played will have a score. and the system will sort all you scores in descending order. after that, the I-th song scored AI will add 0.95 ^ (I-1) * Ai to your total score. Now you are given the task to writ

case, the first line contains an integer N (2 ≤ n ≤1000) denoting the number of the points in the game. then n lines follow, the I-th line consisting of 3 space-separated integers, Ti (0 ≤ Ti Outputfor each test case, output the answer in one line. Your answer will be considered correct if and only if its absolute or relative error is less than 1e-9. Sample Input 252 1 93 7 25 9 06 6 37 6 01011 35 6723 2 2929 58 2230 67 6936 56 9362 42 1167 73 2968 19 2172 37 8482 24 98 Sample output 9.2195444

Descriptionosu is a popular leisure software. We can simplify and adapt the rules of OSU to the following: A total of n operations, each operation only success and failure of the points, the success of the corresponding 1, the failure corresponds to the 0,n operation corresponds to 1 length of 01 strings of N. In this string continuous x 1 can contribute to the score of x^3, this x 1 cannot be included in the other continuous 1 (that is, a very long s

Title Link: Hdu 5078 osu!Surface:osu!Time limit:2000/1000 MS (java/others) Memory limit:262144/262144 K (java/others)Total submission (s): 1058 Accepted Submission (s): 550Special Judge Problem descriptionosu! is a very popular music game. Basically, it's a game about clicking. Some points would appear on the screens at Some time, and you had to click them at a correct time. Now, your want to write a algorithm to estimate how diffecult a gam

Water .. #include HDU 5003 Osu! Question 2014 ACM/ICPC Asia Regional Anshan online

Title Link: http://hihocoder.com/problemset/problem/1258To see the number of combosIdea: water to see how many 1 and s are good1#include 2#include string.h>3#include 4 using namespacestd;5 Charstr[Ten];6 Const intmaxn=10000;7 intMain () {8 intN;9 //freopen ("C:\\users\\acm\\desktop\\2015beijing\\in.txt", "R", stdin);Ten while(SCANF ("%d", n)! =EOF) { One intCnt=0, X; A for(intI=1; i){ -scanf"%s", str); - if(str[0]=='S') cnt++; the Else { -sca

1, test instructions: A sequence, a continuous period of 1 pairs of points have 3 Contribution, then ask the desired score2, Analysis: A bare expectation DP, then new to add a 1, the contribution to the answer for x 3 ?(x?1 ) 3 =3 x 2 +3x+1 Direct violence calculates the desired square and expectation, and every time the DP is updated it's fine.#include #include #include #include using namespace STD;#define M 1000010inline intRead () {Charch = getchar (

Problem Descriptionosu! is a famous music game this attracts a lot of people. In osu!, there is a performance scoring system, which evaluates your performance. Each song you has played would has a score. And the system would sort all your scores in descending order. After that, the I-th song scored AI would add 0.95^ (i-1) *ai to your total score. Now is given the task to write a calculator for this system. InputThe first line contains an integer T, d

BZOJ 4318: OSU !, Bzoj4318osuDescriptionosu is a casual software popular with the masses. We can simplify and adapt osu rules to the following: there are a total of n operations, each operation can only be successful or failed, the success corresponds to 1, the Failure Corresponds to 0, n operations correspond to 1 01 string with a length of n. The continuous X 1 in this string can contribute the X ^ 3 scor

DescriptionOSU is a popular leisure software. we can simplify and adapt the OSU rules to the following:there are n operations, each operation only success and failure, the success of the corresponding 1, the failure corresponds to the 0,n operation corresponds to 1 length of 01 strings of N. In this string continuous x 1 can contribute to the score of X^3, which x 1 can not be included in the other successive 1 (that is, a very long string of 1, as ex

Label: style HTTP Io OS ar SP Div C on Osu is a community-focused music game independently developed and run by Australian Dean Herbert (peppy. The game method is simple, that is1. Circle ): Circle)50. No X is displayed, and the lifecycle is reduced. The 300 and 100 values of the last serial number in the circle are displayed as exciting 300 and drinking 100. 2. Slider. 3. turntable: Press and hold the button to quickly rotate around the center. Bo

Test instructions: Given n elements, some have a value, if it is S then is a single, the other is a, the number of increments starting from 1 is how much.Analysis: Then S is separate, to statistics, since it is starting from 1 increments, then the number of statistics 1 can be.The code is as follows:#pragma COMMENT (linker, "/stack:1024000000,1024000000") #include LA 7270 osu! Master (statistics)

https://www.zybuluo.com/ysner/note/1300315 Problem surfaceThere is a total of \ (n\) operations, each operation only success and failure of the points, the success of the corresponding \ (1\), the failure of the corresponding \ (0\),\ (n\) operation corresponds to \ (1\) A \ (01\) string of length \ (n\) .In this string continuous \ (x\) ( 1\) can contribute to the score of \ (x^3\) , this \ (x\) \ (1\) cannot be other consecutive \ ( 1\) is included.Now give \ (n\), as well as the success rate

operation: why l1[cur]= (l1[1-cur]+1) *a1? In fact, this should be the case: the probability of the current A1 can hit, the resulting expected suffix length (l1[1-cur]+1) *a1① currently has (1-A1) probability can not hit, the resulting expected suffix length 0* (1-a1) ②①+②→l1[cur]= (l1[1-cur) +1) *a1f is the general recursive addition, the current hit probability will not affect f[i-1], and the current probability of the impact of the factors only expected to increase the amount of1#include 2#i

+Temp2. S1; - -Matrix T1=TEMP1. S2,t2=Temp2. S2; -A.s2= (Matrix) {t1.a*t2.a,t1.a*t2.b+t1.b,t1.c*t2.a+t2.c,t1.c*t2.b+t1.d+t2.d}; A + returnA; the } - $Node Query (Const intLConst intRConst intNumConst intSConst intt) the { the if(St) the returnTree[num]; the - intmid=l+ (r-l) >>1); in the if(TreturnQuery (l,mid,num1, s,t); the if(S>mid)returnQuery (mid+1,r,num1|1, s,t); About returnCalc (Query (l,mid,num1, s,t), Query (mid+1,r,num1|1, S,t), mid); the } the th

HDU5003 Osu! (Question G of the Anshan division Network Competition in 2014), hdu5003osu 1. Question Description: Click to open the link 2. Problem-Solving ideas: This question is a simple sorting question, which can be calculated based on the meaning of the question. 3. Code: #define _CRT_SECURE_NO_WARNINGS#include Copyright Disclaimer: This article is an original article by the blogger and cannot be reproduced without the permission of the blogg

CF235 Let #39; s Play Osu! [Dp + probability] Question: For n positions, the probability pi of O occurrence at each position on 1-n is given. The scoring rules are as follows. x consecutive OSS records are x ^ 2 points, and the sum is calculated. For example, xxoooxooxx scores are as follows: Expected score VcD4KPHA + y7y/vNK7z8KjrM7Sw8fE3LHIvc/authorization + signature + CjxwPsTHw7Q8L3A + cjxwpjxpbwcgc3jjjpq = "http://www.2cto.com/uploadfile/