pentest lab

number.#include #defineN 100intMain () {inta[ -]={0},i,j,m=0; for(i=0;i -; i++) {A[i]=i+1; } for(i=0;i -; i++) { if(a[i]%3==0|| a[i]%7==0) {A[i]=0; Continue; } Else{printf ("%5d", A[i]); M++; }} printf ("there are altogether%d", m);} Second, the experiment summary (the problem encountered in the experiment and the solution method)1. Remember to assign an initial value.2.continue ends only one statement, and break jumps out of the loop.3. Notice the function's one by one co

) ................Experience of experimental experiences.........Second, the predecessor workScan the two-dimensional code on the book, combined with the video preview eighth Chapter 8.4 and Nineth chapter of the structure of the content.Third, additional questions (3): Complete the textbook P92 programming design question 6th to the 10th questionAdditional questions are chosen to do the topic, if you think your previous grades are not ideal, want to make up for the students can consciously comp

negative numbers is%f", f,g); return 0;} 7. Output 1000 of all primes, 10 per line, and the final output of the total number of primes. (aligned per column)#include intMain () {inti,n,z=0, flag=0; for(i=2; i +; i++) { for(n=2, flag=0; n1; n++) { if(i%n==0) {flag=1; Break; } } if(flag!=1) {printf ("%d", i); Z++; if(z%Ten==0) {printf ("\ n"); }}} printf ("There's a total of%d primes .", z); return 0;}8. Print the following graphic#include intMain () {i

memory FFF00H~FFFFFH, please find this production date and try to change itSummarize:We modified the production date of the ROM with the e command, but the date remains the same because ROM read-only memory cannot modify the value of the memory.(4) Fill in the data in the memory unit starting with b8100h, such as:-e b810:0000 01 01 02 02 03 03 04 04Change the value:After changing the address:Summarize:Input different data in memory, the phenomenon is different, after changing the address, the s

04Please fill in the different data first, observe the phenomenon, and then change the address to observe the phenomenon.After filling in the data, a color pattern appears in the upper right corner of the screen.After filling in different data, the pattern changed.When you change the address, the same pattern appears in other places on the screen.Summary and experienceThrough this experiment, I realized the different of the assembly language and other high-level languages more intuitively, and

Lab 0 understanding and familiarity with the operating systemI. Purpose and Requirements1. Purpose of the experiment(1) Master the definition and concept of the operating system;(2) Understand the development history of various types of operating systems;2 . Experimental requirementsUse Web search to learn about various types of computer operating systems and organize them into a single document.Ii. contents of the experimentUnderstanding and Masterin

Virtual Storage:Virtual disk files: VHDX filesDynamic expansion: Commonly used, experimental useDifferential disk: Quickly deploy multiple virtual machines, create a system base disk, and quickly create multiple VMS using the base diskThe system's base disk must be a "package state" with no system SID status Base系统创建最佳实践 手动创建一个动态大小的虚拟磁盘 创建虚拟机时，使用该磁盘文件为虚拟机磁盘 安装系统，封装系统 拷贝该

displayed card output to the display, There is the result that we see.Five, summary and experienceCompilation of Knowledge:Through this experiment, it deepened my proficiency in the use of various instructions in assembly language, and the specific experimental operation also made me aware of the actual working state of 8086CPU. For example: The address of the CS:IP represents the execution direction of the instruction, change the direction of the field Cs:ip before executing the corresponding

Lab 0 understanding and familiarity with the operating systemI. Purpose and Requirements1. Purpose of the experiment(1) Master the definition and concept of the operating system;(2) Understand the development history of various types of operating systems;2 . Experimental requirementsUse Web search to learn about various types of computer operating systems and organize them into a single document.Ii. contents of the experimentUnderstanding and Masterin

1. English in the picturePictures can have many ways to open, to crack the problem, you need to download the picture.For pictures, we can use the image editing software, to do various dimming, color and other operations.We can also open using 2 binary or 16 binary file open mode. The diagram uses the 16 binary mode to open, can detect the RAR file type tag, so we can use it to open the RAR method.Knowledge Point: The different open way of the file, the csdn of the identification of the various f

: man GdBFile exchange between Ubuntu and Linux-0.11 Mount Linux-0.11./Mount-HDCMOUNT-HDC is a shell script:1 #!/bin/sh2 export oslab_path=$ (dirname 'which $0') 3 Mount -t minix-o loop,offset=1024x768 $OSLAB _path/hdc-0.11Line 1th indicates the shell used by the scriptThe 2nd line will call this script directory set to Oslab directoryLine 3rd according to the manual manual of Mount,-T Minix indicates the file system type to mount is Minix-o[ption] can have 3 parameters (refer to Losetup's manua

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patternHow to add a domain name in cm:650) this.width=650; "title=" clip_image012 "style=" border-top:0px;border-right:0px;background-image:none; border-bottom:0px;padding-top:0px;padding-left:0px;margin:0px;border-left:0px;padding-right:0px; "border=" 0 "alt = "clip_image012" src= "http://s3.51cto.com/wyfs02/M01/84/57/wKiom1eNzFWDlvJoAACudKY1EGE607.jpg" height= "297"/>Sip Trunk Security Profile Configuration===>sip TrunkSIP profile configuration===> SIP end pointCCM Trace650) this.width=650; "

=sum=0;for (i=m;iif (prime (i)!=0){C + +;Sum=sum+i;}printf ("c=%d,sum=%d\n", c,sum);BreakCase 4:SCANF ("%d%d", z,digit);C=countdigit (Z,digit);printf ("Number%d of digit%d:%d\n", z,digit,c);BreakCase 5:SCANF ("%d%d", m,n);printf ("result:\n");for (i=m;iif (Is (i)!=0)printf ("%d\n", I);Break}}while (choice!=0);return 0;}int sign (int x){if (xelse if (x>0) return 1;else return 0;}int even (int n){int x;if (n%2==0)X=1;Elsex=0;return x;}int prime (int m){int i;if (m==1)return 0;for (i=2;iif (m%i==0)

ports. Assign an IP address to VLAN Ten and enable it. Refer to the addressing Table. Configure the default gateway according to the addressing Table. Configure VLANs on S2. On S2, create VLAN 10. Assign Student as the VLAN name. Create VLAN 20. Assign Faculty-admin as the VLAN name. Configure F0/1 as a trunk port. Assign ports F0/11 and F0/18 to VLAN and configure both F0/11 and F0/18 as access ports. Assign an IP address to VLAN Ten and enable it. Refer t

Water problem, but the topic content is difficult to read, add up again can. Optimal Parking Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7579 Accepted: 4555 DescriptionWhen shopping on Long Street, Michael usually parks his car at some random location, and then walks to the stores he needs . Can you help Michael choose a place to park which minimises the distance he needs to walk on his shopping round? Long Street is

the courseware, mainly because the data set here is too small and there are only five data points. C ++ lab Considering that the above regression is essentially a least square problem. If we solve the least squares Ax = B from the perspective of linear algebra, here we will use eigen to do the experiment, which corresponds to the above two examples of 1 yuan and multivariate linear regression respectively. Always 1. for the exam area, if

. Search If we switch to the design view at this time, we will see that the design view is the same as the page we did in Experiment 1. Exercise 2: Create an atlas announcement block to call the web service. In this part of the experiment, create an atlas announcement block tag, you will be able to call the same web service as

Address: http://blogs.msdn.com/ B /tess/archive/2008/03/25/net-debugging-demos-lab-7-memory-leak.aspx Procedure: 1. pressure generation: tinyget-SRV: localhost-Uri:/buggybits/news. aspx-threads: 500-loop: 200 2. capture an hang dump and check the GC heap size ,! Eeheap-Gc, as follows: GC heap size 0x1899f44c (412742732), about 400 m, and the entire dump file is 550 m. 3. Check the overall status of GC heap :! The output of dumpheap-stat is a

MD5 value is exactly the same, indicating that the attachment file Fly.rar has been restored by the network package. haha ~ ~ ~ Back to Topprocessing a restored data attachment Unzip rar ..... I thought I was done here, and I didn't think the decompression package failed. To continue the analysis, first the above MD5 value is exactly the same, indicating that the package is not corrupted possible Search the Internet, the result is that the compression package has a pseudo-