php date interval 1 month

Use the function date () to implement the displayed in the format: year-month-day hours: minutes: secRelated Time parameters:A-"AM" or "PM"A-"AM" or "PM"D-A few days, two digits, if less than two digits before the 0; such as: "01" to "31"D-Days of

When I used to solve this problem with ASP is quite simple, the ASP has the corresponding function DateDiff can give two days period interval How many months, how many days and how many seconds. When I searched through the PHP manual I found that

This article contains the following elements: 1, get the current date and time-how many ways do we have? 2, change the date display mode-date and time display form 3, the conversion of the current date is a Unix timestamp value 4. Change Date A.

PHP date query function code Date_default_timezone_set ('prc'); // Default time zone Echo "today:", date ("Y-m-d", time ()),""; Echo "today:", date ("Y-m-d", strtotime ("18 Jun 2008 ")),""; Echo

The direct subtraction of functions is not correct, you need to do this: * * Get the current date and time In Unix, time is represented by the number of seconds that have elapsed since 0 o'clock January 1, 1970, which is called the Unix timestamp (

Local Test Cases: # there can be no spaces on either side of the equal sign, before the error has been out here yesterday= ' date-d last-day +%y-%m-%d ' echo $yesterday curday= ' Date +%y-%m-%d ' echo $curday echo "Now time: ' Date ' +%y%m%d%T '"

This article contains the following content:1. Get the current date and time-how many ways do we have?2, change the way the date is displayed-the date and time of the display form3. Convert the current date to a Unix timestamp value4. Change the

Date_default_timezone_set (' PRC '); Default time zone echo "Today:", Date ("Y-m-d", Time ()), ""; echo "Today:", Date ("Y-m-d", Strtotime ("June 2008")), ""; echo "Yesterday:", Date ("Y-m-d", Strtotime ("-1 Day")), ""; echo

How to calculate the period-over-period ratio of an SQL statement! The number of resumes in this month minus the number of resumes in the previous month () [number of resumes in this month]-[number of resumes in the previous month] = [number of

"Number of resumes in the month"-"resumes last month" = "Number of years" () How is the SQL statement written? SELECT date_format (m_adddate, '%m ') as Month,count (m_id) as Zong,date_format (m_adddate, '%Y ') as year from Job_myreceive where Date_