php get domain from url

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Introduction: This is Php.Program: Virtual Domain Name Service DIY detailed page, describes and PHP, related knowledge, skills, experience, and some PHP source code. Class = 'pingjiaf' frameborder = '0' src = 'HTTP: //

Editor's note: friends who have used NetEase's my.yeah.net domain name to switch to the service must be interested in its powerful functions? Once you have applied for your own virtual domain name, such as coolfish.yeah.net, visitors can use this

Php obtains the summary of root domain names, and php obtains the summary of domain names. Php obtains the summary of root domain names. php obtains the summary of domain names. examples in this article summarize the methods for php to obtain root

The following code can get the domain name from the URL Example: http://bkjia.com/live/q.html Get bkjia.com The following is the referenced content:function Get_domain ($url) {$pattern = "/[\w-]+\. (COM|NET|ORG|GOV|CC|BIZ|INFO|CN) (\.

echo server[' server_name '];//get the source URL, that is, click to the previous page of this page URL echo server["Http_referer"]; server[' Request_uri '];//gets the suffix of the current domain name server[' Http_host '];//get

The PHP regular expression retrieves the domain name from the url. The following code obtains the domain name from the URL, for example, liehuo.netliveq.html. the following liehuo.net references: functionget_domain ($ url) {$ pattern [w-] +. (com |

How to solve JS cross-domain problemJS cross-domain problem is one of the most common problems that web developers encounter. The so-called JS cross-domain problem, refers to the page under one domain through the JS access to another different

This morning to help students see a angularjs problem, mainly in the request for Cross-domain access, the request was blocked. Here's the code she gave me: title name: {{data.goodsna Me}} Price: {{data.price|currency: "￥"}}

Global array echo $_server["Http_host"]; The bbs.it-home.org will be output. Copy CodeLocal tests will output localhost.Method 2, using the Parse_url function; ";p Rint_r ($arr); echo"";? >The output is an array with