powershell learning exercises

): Numlist.append (str (i )) Sqrtnum = Int (MATH.SQRT (i)) for J in range (2, Sqrtnum + 1): Findtimes + = 1 if i% J = 0:nu Mlist.pop () Break print (",". Join (Numlist), end= ",") print ("%d"% len (numlist), end= ",") Print ("Total Compared%d "% findtimes" Answer5 () class Answer6: "" "" "" "" "" "" "" "Def __init__ (self):" "Constructor" " "Self.sumcount = 0 self.findtimes = 0 Self.startnum = 102 Self.endnum = + print (" Output Six ", end=": ") def __iter__ (self):" "" Iterator: Return: "" Retu

;public uptask (socket socket) {this.socket = socket;} public void Run () {int count = 1;try {String IP = socket.getinetaddress (). gethostaddress (); System.out.println ("IP:" +ip+ ".... connect"); InputStream in = Socket.getinputstream (); File dir = new file ("c:\\copypic111111111"); Dir.exists ())) {Dir.mkdirs ();} File File = new file (dir,ip+ ". jpg");//if already exists while (file.exists ()) {file = new file (dir,ip+ "(" + (count++) + "). jpg"); FileOutputStream fos = new FileOutputStre

': theUserphone = input ('Please enter contact Phone:') +Addressbook[name] =Userphone A Print(AddressBook) the Continue + Else: - Continue $ Else: $Userphone = input ('Please enter contact Phone:') -addressbook[name]=Userphone - Print('Contact added successfully! ') the Print(AddressBook) - ContinueWuyi ifitem = = 3:#Delete a contact the ifNameinchAddressBook: - delAddr

= [] R = Range (1, 5) for a in r:for B in R:for C in R: If a! = B and a! = C and b! = C:d.append ("%d%d%d"% (a, B, c)) print (d, end= ",") print ("%d"% Len (d)) Answer3 () def answer4 (): "" "in the list use the for and if operations to iterate the data" "" Print ("Answer four", end= ":") arr = [1, 2, 3, 4] NewList = ["%d%d%d"% (I, j, K) for I in Arr. J in arr. K in arr if I! = J and I! = k and J! = K] Print (NewList, End= ",") print ("%d"% len (newlist)) answer4 () def answer5 ():

-Air:desktop user$ pythonPython 2.7.11 (v2.7.11:6d1b6a68f775, Dec 5 2015, 12:54:16) [GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwinType "help", "copyright", "credits" or "license" for more information.>>> import os>>> import sys>>> import no25>>> s = "There are many books.">>> sen = no25.break_words(s)Traceback (most recent call last): File "Error 2: A typo in the calling function causes the Python hint name to be undefined.>>> no25.print_first_and_last(sentence)Traceback (most recent ca

,//stream can manipulate the file object Pro.store (FW, "after Change");} Iv. Practice Get the number of uses of an application, more than 3 times, give information about the number of times the usage has been registered, and do not run the program again Analysis: This requirement requires a counter, each time the program starts counter into memory, number of times +1, exit program, counter close, store to file. Because the confidence to be clear, there should be a name and numbe

|awk-f "[(/]" ' nr==4 'Access: (0644/-rw-r--r--) Uid: (0/root) Gid: (0/root)[[email protected] ~]# stat/etc/hosts |awk-f "[(/]" ' Nr==4{print $} '0644#方法2-sed[Email protected] ~]# stat/etc/hosts |sed-n ' 4p 'Access: (0644/-rw-r--r--) Uid: (0/root) Gid: (0/root)[Email protected] ~]# stat/etc/hosts |sed-n ' 4p ' |sed-r ' s#^.*\ (0.*/# #g 'root\)[[email protected] ~]# stat/etc/hosts |sed-n ' 4p ' |sed-r ' s#^.*\ (0 (. *)/-# #g 'rw-r--r--) Uid: (0/root) Gid: (0/root)[[email protected] ~]# stat/etc/

First, the user in the process of using the app, will produce a variety of events. The events in iOS can be divided into 3 major types:Second, the responder object Only objects that inherit Uiresponder in iOS can accept and handle events, which are called "responder objects" UIApplication, Uiviewcontroller, and UIView inherit from Uiresponder, so they are all responder objects and can accept and handle events Uiresponder internally provides the following methods to handle events Th

PrivateCustomerdao CD =NewCustomerdaoimpl (); PrivateLinkmandao LMD =NewLinkmandaoimpl (); Public voidSave (Linkman lm) {//Open Transactionhibernateutils.getcurrentsession (). BeginTransaction (); Try { //1 obtaining Customer objects based on customer IDLong cust_id =lm.getcust_id (); Customer C=Cd.getbyid (cust_id); //2 Put the customer into Linkman to express the relationshipLm.setcustomer (c); //3 Save LinkmanLmd.save (LM); } Catch(Exception e) {e.printstacktrace (); //rolling

){ThrowNew Fushuexception ("You passed a negative number");//Report an exception and pass a custom string}Double s=math.pi*r*Rreturn S;} // method for averaging public static double avg (double...arr) {double sum=0; for (double I:arr) {if (Ithrow new fushuexception ("parameter is negative" i; } return sum/arr.length;}} Custom Fushuexecption class:Package com.oracle.Demo01; custom class exception, inherited from Run exception extendsSuper(MES);}} 3. Detection age can not be negative an

) CUDA memory variablesdifferent Memory and variable types, as follows:1. Declare the host variable, request allocation space, and initialize2. Declaring device variables, requesting allocation space3. cudamemcpy assigns the assigned host variable to the device variable4. Call Cuda kernel, parallel run thread5. Device return results to host6. Release device variable memory========================================Exercise1:Input:float Array [0, 1, 2, ... 63]Output:float Array [0^2, 1^2, 2^2, ...

? Programming# while True:# money = input (' Profit: ')# if money.isdigit () = = True:# if INT (money) # Print ("Bonus:%s"% (int (money) *10/100))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-100000) *7.5/100) +100000*10/100))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-200000) * 5/100)))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-400000) * 3/100)))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-600000) * 1.5/100)))# Else:# Print ("Bonus:%s"% (((int (money)-6

The logical combination in the previous section is called a Boolean logical expression. Boolean logic is used in many places of a program. It is the foundation of computer computing. Learning about it is just like learning music to understand scales. Read the following question, write the answer, and verify the answer in the python parser.True and TrueFalse and True1 = 1 and 2 = 1"Test" = "test"1 = 1 or 2!

After registering deep learning on Cousera, you can download the after-class exercise.1. After entering the programming environment, click File-open in the upper left corner to enter the file management mode2. Click on the Red Circle folder to enter the root directory3. In the top right corner of the root directory, new one IPYNB4. Open the new IPYNB, enter and do the following, you can compress the files in the root directory into a zip format, downl

/*1. Define a function to print the rectangle.2. Define a function that prints the function of the 99 multiplication table.*/Class FunctionTest {public static void Main (string[] args){Draw (5,6);Printhr ();Draw (7,9);Printhr ();Print99 ();}/*Define a function that prints the 99 multiplication table function*/public static void Print99 (){for (int x=1;x{for (int y=1;y{System.out.print (y+ "*" +x+ "=" +y*x+ "\ t");}System.out.println ();}}/*Defines a feature that is used to print rectangles.Ideas

1. Find the maximum value in three numbers 2. Enter three numbers to print out the middle value (i.e. the second largest value) in two waysTip: First, the maximum minimum is first, and the second, only the conditional operator is used Method 1 float x = 0.0; Float y = 0.0; float z = 0.0; float max = 0.0;//define max float min = 0.0;//define minimum float mid = 0.0;//Define intermediate value printf ("Please input three number:\n") ; scanf ("%f%f%f", x, y, z); max = x >

Com.lzw;public Abstract class UseCase1 {abstract void testabstract (); UseCase1 () {//(1) First executes the parent constructor method System.out.println ("Before Testabstract ()"); Testabstract ();//If an abstract method is called, the method that the subclass overrides is called. This calls the Testabstract () method of the Atest class System.out.println ("After Testabstarcat ()");} public static void Main (String args[]) {new atest ();}} Class Atest extends Usecase1{private int i=1;//(2) cau

(); at intindex = 0; - /** - * Cause of error: not considering the increase in the number of cards, only 13 cards from beginning to finish - */ - for(String var:number) { - for(String color:strings) { inString string =Color.concat (VAR); - map.put (Index, string); to Newlist.add (index); +index++; - } the } *Map.put (Index, "Xiao Wang"); $ Newlist.add (index);Panax Notoginsengindex++; -Map.put (Index, "King")); the Newlist.add (i

JAVA learning lesson 40th (Common Object API)-Map set exercises, apimap 1. LinkedHashMap set Import java. util. hashMap; import java. util. iterator; import java. util. linkedHashMap; import java. util. map; public class Main {public static void main (String [] args) {HashMap Exercise: Number of occurrences of letters Import java. util. iterator; import java. util. map; import java. util. treeMap;/* "as

The topic is simple.Title Description Description Did, the simple A-B and the question. But what if the required input is not a and B, but the entire addition expression?Find a way to calculate the result of an addition expression.Enter a description input Description Enter an addition expression, such as 1+2=.outputs description output Description Calculate the correct result for an input expressionsample input to sample1+2=Sample output Sample outputs3data size Hint The complete input expr