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Array pointers and the addressing of two-dimensional arrays

as the preceding type description.Then go back to the previous example, X is a two-dimensional array of definitions, p is an array pointer to an array of length 4, one to the first line of X (the line of x is an int array of length 4) and the next for loop, then the p+1 value, plus K (actually 1) and then the value, and add it to the variable N. The loop performs a total of 2 times, taking the first element (i.e. x[0][1],x[1][1]) of line 1th and line 2nd (corresponding to the first subscript 0

Trojan-free assembly flower instruction skills

. Mov a and B send the value of B to a, and regard it as a value assignment statement in programming, that is, B is assigned to a. Then the value of a is B. Nop does not work, that is, nothing is done. Retn retrieves the return address from the stack and jumps to the address for execution. Here are some arithmetic operation commands: ADD Addition Sub Subtraction Inc plus 1 Dec minus 1 Finally, the jump command: Jmp unconditional jump Je or jz jump if equal Skip if not equal to jne or jnz Skip if

GDB disassembly and debugging in LINUX

To simplify the problem, analyze the compilation code generated by the simplest c code:# Vi test1.c Int main (){Return 0;} Compile the program to generate a binary file:# Gcc test1.c-o test1# File test1Test1: ELF 32-bit LSB executable 80386 Version 1, dynamically linked, not stripped Test1 is an executable file in the ELF format of 32-bit Little Endian. It is dynamically linked and the symbol table is not removed. This is a typical executable file format on the Unix/Linux platform. With mdb dis

"Hackers do not kill attack" Reading notes 12-pointers and arrays

add eax,0x8; Pptr+2 003cc57c; In C language, the operation of pointers is 003cc57c based on pointer type; An int pointer plus 1 means that the address it points to is moved backward in length to a 003cc57c; The distance of the int size, which is 4 bytes. If it's a word type, move backwards by 2 bytes. 003cc57f Push eax003cc580 mov ecx,[local.7]003cc583 add ecx,0x4; Pptr+1 003cc586 push ecx003cc587 mov edx,[local.7]003cc58a push edx; pptr+0 003cc58b push 9-44.00420c6c; ASCII "%x%x%x\r\n" 0

Implementation of an operating system note (6)--Process

We can encapsulate everything that a single task uses in a LDT, which is the embryonic form of multitasking.The types of segments used by multitasking are shown below, and the method of using LDT to isolate each application task is one of the key protection requirements: Process schematic: We need a data structure to record the state of a process, the process information is written to the data structure when the process is to be suspended, and the information is read again when the process resta

Debug principle-Reverse peid-to determine VC

:00438C26|. EBX Push00438C27|. A-push EBP00438C28|. all-in-push ESI00438C29|. $ push EDI; Here is the padding of an array00438C2a|. B0 al,0x72 mov; "R"00438C2c|. 884424 2F mov byte ptr ss:[esp+0x2f],al00438C30|. 884424 mov byte ptr ss:[esp+0x31],al00438C34|. 884424 mov byte ptr ss:[esp+0x34],al00438C38|. 884424. mov byte ptr ss:[

The multi-state detailed _c language in C + + from the view of compilation

In C + +, when a class contains a virtual function, the class has polymorphism. An important function of the constructor is to initialize the vptr pointer, which is a critical step to ensure polymorphism. Constructor initializes the vptr pointer The following is the C + + Source: Class X { private: int i; Public: X (int ii) { i = II } virtual void set (int II) {//virtual function i = II; } }; int main () { x x (1); } The following is the corresponding main

C function call stack (1)

based on the operand size to generate assembly code. At the Assembly language level, this set of General registers is referenced with % e (ATT syntax) or directly starting with e (Intel syntax), such as mov $5, % eax or mov eax, 5: Assign the value of "Number 5" to register % eax. In x86 processors, the EIP (Instruction Pointer) is the Instruction register pointing to the Instruction address (offset in the code segment) waiting for execution under the processor ), the EIP value of each Assembly

Vulnerability mining practices

courseware has pointed out: sending a username that exceeds 480 bytes to the server can trigger the vulnerability (that is, using the command USER longString \ r \ n). After overflow, the content in ESP contains part of longString. Verification and analysis are required.2.2 analyze the stack structure of war-ftp v1.65, that is, the exact location of EIP, ESP, and ebp in the analysis stack.2.3 construct exp

(11) Generic Programming/Function Templates/class templates

point where it is called-compile the *///template code after the call, and tell the compiler that it starts the generic programming//typename tells the compiler that the type name is T compiler you see type T don't mess up the error .... T is type, type is parameterized just templateThe g++-s 1.cpp generates 1.SAnalysis 1.s. File "1.cpp". Lcomm __zstl8__ioinit, 1, 1.def ___main;. SCL 2;. Type 32;. Endef.section.rdata, "Dr" Lc2:.ascii "hello....\0" LC3:. ASCII "Pause\0". Text. Globl _main. def _

On the Linux platform, you can use GDB for disassembly and debugging.

Address: http://www.cppblog.com/liu1061/articles/53762.html If you are on a Linux platform, you can use GDB for disassembly and debugging. (Transfer) 2. The simplest CCodeAnalysis To simplify the problem, analyze the compilation code generated by the simplest C code:# Vi test1.cInt main (){Return 0;}CompileProgramTo generate binary files:# GCC test1.c-O test1# File test1Test1: Elf 32-bit LSB executable 80386 version 1, dynamically linked, not stripped Test1 is an executable file in the EL

The simplest example of a stack overflow attack (2) [by progsoft]

Next we will take the release version as an example to illustrate the anatomy. The key code for the EXE disassembly is as follows: Function showcomputername:00401030: 8B 4C 24 04 mov ECx, dword ptr [esp + 4] 00401034: 83 EC 0C sub ESP, 0ch 00401037: 8d 44 24 00 Lea eax, [esp] 0040103b: 50 push eax 0040103c: 51 push ECx 0040103d: E8 be FF call 00401000 00401042: 8

Comprehensive analysis of "self-written operating system" chapter sixth-Interrupt processing program

to get es0 and esp0 from the TSS. After entering the RING0 (interrupt handler), we need to save the state information of process A to the PCB (Process Control block), so we point the TSS esp0 to the process table before the interrupt handler occurs. So in the restart function, we see: Restart: mov ESP, [P_proc_ready] ; Assigns the first address of the process table to ESP Lldt [

BSS segment, data segment, code snippet for target file under Linux

c28b4424 1801c28b 44241c01 d0890424. d$ .... d$.....$ 0050 e8fcffff ff8b4424 18c9c3 ... d$ ... Contents of section. Data: 0000 54000000 00000000 55000000 T .... U ... Contents of section. Rodata: 0000 68656c6c 6f20776f 726c6421 0025640a Hello world!. %d. 0010 00323232 323200.22222. Disassembly of section. Text: 00000000 0:55 Push%EBP 1:89 e5 mov%esp,%ebp 3:83 EC Sub $0x18,%esp

Talking about how the computer works and the simple disassembly operation under Linux __linux

and other hardware. How to drive these hardware is done by software. Programming is done on the basis of the operating system through the operation of the Code and then compiled by the compiler to execute. In Linux we have a disassembly to test how C code is converted into assembly code. We do this on the lab floor, the C code is a simple three function (a main function and two called functions): Disassembly with GCC under Linux: Gcc-s-O main.s main.c-m32 You can get the assembly-level code f

Understanding how to exploit the Buffer Overflow Vulnerability

debugger has captured corrupted data and paused the application. If you look at the EIP (Extended Instruction Pointer) register, you will see the fuzzer buffer sending overwrite register within 41 seconds, and the fuzzer buffer will also flood into ESP (Extended Stack pointer) register (00AEFC2C ). Our primary goal is to control the EIP register again through the instruction code executed by the CPU and set it to our selected value. Vulnerability Mi

Win32 compilation [18]: Push and pop

Because the "stack" is used from high to low, the newly pushed data has a lower position. The pointer in ESP will always point to this new location, so the address data in ESP is dynamic. Push each time, esp = ESP-X; pop each time, esp =

View C ++ from the perspective of assembly (class inheritance)

functions during memory construction and analysis? Copy to clipboardprint? 74: manager m; 00401268 lea ecx, [ebp-4] 0040126B call @ ILT + 60 (manager: manager) (00401041) 75 :} 00401270 lea ecx, [ebp-4] 00401273 call @ ILT + 0 (manager ::~ Manager) (00401005) 00401278 pop edi 00401279 pop esi 004020.a pop ebx 004010000b add esp, 44 h 0040da-e cmp ebp, esp 00401280 call _ chkesp (00408760) 00401285 mov

Linux kernel Analysis (ii)--analyzing process switching principles from a simple Linux kernel __linux

switching the most important is the broker's storehouses Switch and EIP (that is, program counters) the correct jump, mymain.c in the function My_start_kernel is the first code to execute, so from this function to start analysis. The My_start_kernel function first established 4 processes and initialization, such as the allocation stack, note that at the time of the first set up only No. 0 process status is runuable, the rest are unrunnable. There is the PCB structure of the THREAP.SP, each proc

Read the article "WindowsNT Buffer Overflow's from start to finish"

(make sure your application being built in debug mode or your results will be different). 11 doesn't work so we keep increasing it. 18 finally causes a crash. This crash isn't anything special yet. We've just totally screwed up the stack and it shows. Lets add six more a's, for a total of 24. Run the program and watch the dialog popup explaining to us that instruction at 0x61616161 had referenced memory at 0x61616161. You do know that the hex value for the ascii character a is 0x61 right? If you

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