python textbook with exercises

-Air:desktop user$ pythonPython 2.7.11 (v2.7.11:6d1b6a68f775, Dec 5 2015, 12:54:16) [GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwinType "help", "copyright", "credits" or "license" for more information.>>> import os>>> import sys>>> import no25>>> s = "There are many books.">>> sen = no25.break_words(s)Traceback (most recent call last): File "Error 2: A typo in the calling function causes the Python hint name to be undefined.>>> no25.print_firs

4-1.Python object. What are the three attributes related to all Python objects? Please briefly describe it.[Answer]All Python objects have three features: identity, type, and value.Identity: each object has a unique identity. The identity of any object can be obtained using the built-in function id. This value can be considered as the memory address of the object

#coding =utf-8Import reS= "" "[email protected], [email protected], [email protected][Email protected], [email protected][Email protected] "" "Content=re.sub (r "\[email protected]\w+.com", "[email protected]", s)Print SPrint "_______________________________________"Print contentC:\python27\scripts>python task_test.py[Email protected], [email protected], [email protected][Email protected], [email protected][Email protected]____________________________

Python Basics Exercises 11. Two ways to execute Python scriptsAnswer: command line execution, editor execution2, briefly describe the relationship between bits and bytesA : Byte byte bit: bit, 1 bytes = 8 bits3. brief description of the relationship between ASCII, Unicode, Utf-8,GBKFor:ASCII is the first United States to use the standard Information Interchange c

Python Exercises (v)The sum of the factorial of 1 to 5 is obtained, that is, the factorial of 1, the factorial of 2, the factorial of 3, the factorial of 4, the factorial of 5, and finally add up and sum.Factorial of 1:1*1=1Factorial of 2:1*2=2Factorial of 3:1*2*3=6Factorial of 4:1*2*3*4=24Factorial of 5:1*2*3*4*5=120The final sum should be 153Program implementation Code:n = 5sum = 1count = 0for i in range

-coordinate. Copy the previous grid values, write the code to print out the image ... Oo. Oo... Ooooooo. Ooooooo ... Ooooo ..... Ooo....... O.... Tip: You need to use loop nesting loops, print out grid[0][0], then grid[1][0], then grid[2][0], and so on, until Grid[8][0]. This completes the first line, so the next line is printed. The program will then print out grid[0][1], then grid[1][1], then grid[2][1], and so on. The program finally prints out grid[8][5]. Also, if you do not want to autom

Learning, are from the book to find some of the programming of small exercises.1, write a program, he takes the radius of the sphere (floating point) as input, and output the sphere diameter, circumference length, surface area, volume.defBall (): whileTrue:Try: P= 3.14R= Float (Input ("Please enter sphere radius:")) ifR 0:Print("the sphere radius of the input cannot be less than 0! ") Else: Print("the diameter of t

The problem with Python exercises is as follows:Description: There are four numbers, respectively: 1, 2, 3, 4Question: How many three digits can be composed of different and non-repeating numbers? What's the number? for in range (1,5): is in range (1,5): for in Range (1,5): ifand and shi!=ge: Print (bai,shi,ge) Else: ContinuePython mathemati

Tag: the sum () function provided by Python can accept a list and sum please write a prod () function to accept a list and use the reduce () to calculate the product:1 #Python提供的sum () function can accept a list and sum, write a prod () function, you can accept a list and use reduce () to calculate the product:Code:2 3 from Functools import reduce 4 Li = [1,2,3,4,5,7] 5 print (sum (LI)) 6 7 def prod (x, y):

located?M. Gets a subsequence that does not contain the last character. such as: Oldboy to obtain the oldbo; Root gets the roo21. Can a string iterate over an object? Can I use a for loop for each element?As long as the For loop is an iterative object22, please use the code to achieve:A. Using underscores to stitch each element of a list into a string, Li = "Alexericrain"B. Use an underscore to stitch each element of the list into a string, Li = [' Alex ', ' Eric ', ' Rain '] (optional)v = "_".

= input (' Profit: ')# if money.isdigit () = = True:# if INT (money) # Print ("Bonus:%s"% (int (money) *10/100))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-100000) *7.5/100) +100000*10/100))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-200000) * 5/100)))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-400000) * 3/100)))# elif Int (money) # Print ("Bonus:%s"% (((int (money)-600000) * 1.5/100)))# Else:# Print ("Bonus:%s"% (((int (money)-600000) * 1/100)))# break# Else:#

Python exercises One1, a brief description of the difference between the compilation and interpretation of the language, and separately listed which languages you know are compiled, which are interpreted type?For:Concept:Compiled language: A ready-to-run program that compiles all the good source programs into binary code. Then, you can run the program directly.Interpreted language: Translate a good source p

Write a script to determine whether the 80 port of the machine is open, if you do not open anything, if the discovery of the port does not exist, then restart the httpd service, the concurrent mail notify you yourself. Once the script is written, it can be executed every minute, and a dead loop script can be written, and 30s is detected once.#!/usr/bin/env python#!coding=utf-8Import OSImport timeImport SysImport SmtplibFrom Email.mime.text import Mime

Python syntax exercises-for loop #! /Usr/bin/env python #-*-coding: utf8-*-age = 26 for I in range (3 ): intput = int (input ("Please guess my age:") if intput The above is the content of the for loop in the Python syntax exercise. for more information, see The PHP Chinese website (www.php1.cn )!

"python exercise 027" to sort 10 numbers---------------------------------------------There is nothing to say, use Str.split (") to get the input 10 numbers, and then use the Lst.sort () to complete the sorting. The code is as follows:s = input (' Please enter 10 digits separated by a space: ') n = [int (x) for x in S.split (")]n.sort () print (n)The output results are as follows: Please enter 10 digits separated by a space: 3 23 4 64 6 17 80 212

"python exercise 009" prints out all the "daffodils", the so-called "daffodils number" refers to a three-digit number, whose numbers are cubic and equal to the number itself. For example: 153 is a "narcissus number", because the 153=1 three times the square +5 of the three +3 Times Square.----------------------------------------------------------------------This problem is also sent to the sub-problem, as long as can be any three digits of the hundred

meters high landing, a total of 296.875 meters, and then rebounded to 0.78125 meters.The 8th time from 0.78125 meters high landing, a total of 298.4375 meters, and then rebounded to 0.390625 meters.The 9th time from 0.390625 meters high landing, a total of 299.21875 meters, and then rebounded to 0.1953125 meters.The 10th time from 0.1953125 meters high landing, a total of 299.609375 meters, and then rebounded to 0.09765625 meters. That is: the 10th time Landing, a total of 299.609375 meter

"python exercise 023" there are 5 people sitting together and asking how old is the five? He said he was 2 years older than the 4th one. Asked the age of 4th, he said he was 2 years older than the 3rd man. Asked the third person, and said that the 2nd People's Congress two years old. Ask the 2nd person, who says two years older than the first one. Finally asked the first person, he said is 10 years old. How old is the fifth one?-----------------------

Python core programming-exercises-Chapter 2, Chapter 2 PS: PDF online address: http://bcmi.sjtu.edu.cn /~ Zhaohai/ptm2012/data/Python-kernel.programming.v2.pdf 2-1 variables, print and string formatting operators. Start the interactive interpreter, assign values (strings, values, and so on) to some variables, and display their values by entering the variable name

# Editor: Shanlong l = [2, 3, 4, 5, 6,7 for in# get a new list L1, each element in the new list is the square of the value of each element in L /c6>printforif i > Max]# filter out values greater than 40 in L1 and sum print(sum (L1))Above, there's nothing to say#edited by: ShanlongShares = { 'IBM': 36.6, 'Lenovo': 27.3, 'Huawei': 40.3, 'Oldboy': 3.2, 'Ocean': 20.1}#question one: A list of stock names with a stock price greater than 30L = [i forIinchSharesifFloat (shares[i]) >30]