First, the C1 and C2 VLAN are set on the switch R5
r5>en
R5#conf T
R5 (config) #vlan 10
R5 (Config-vlan) #vlan 20
R5 (Config-vlan) #inter FA1/1
R5 (config-if) #switchport Access V
, figure 1 sets a retention station for each command, while some processors use a retention station to control all pipelines.
Reverse dependency
Unordered execution can complete other tasks within the waiting time to improve efficiency, but it may also cause problems. For example, the following program.
LD R1, [a]; then reads the memory variable A into the register r1 (loaded)
Add R2, R1, R5; then R1 and
Lab requirements:Set up the topology, import the pre-configuration, and troubleshoot the following errors.1. R4 cannot learn the host entries mounted on R5;2. The OSPF neighbor between R6 and R7 cannot start;3. R4 cannot form OSPF neighbors with R2 and R3;4. R7 cannot form an IPsec neighbor with R8 or R9;5. The host on R5 cannot be pinged to the host on R9;6. Ensure that the packets sent from the host on R5
assembly file or a segment does not mean that the execution is complete first.Head. s to execute head-s3c2410.s, or pay attention to the link segment, apparently head. sIn a short time, another segment is started. Text.. TextADR r0, lc0Ldmia r0, {R1, R2, R3, R4, R5, R6, IP, SP}Subs r0, R0, R1 @ calculate the Delta offsetAnd our head-s3c2410.s?. Section ". Start", # alloc, # execinstr_ S3c2410_start:Bic R2, PC, # 0x1fAdd R3, R2, #0X4000 @ 16 KB is qui
, etc ). multiple tags are shown in. the MTU is extended due to the introduction of tags. the label length is 4 bytes. According to CISCO's suggestion, the system MTU is set to 1524. If the label is encapsulated over Ethernet, the 24-byte label can carry the insertion of 6 labels, generally, the six labels are suitable for almost all applications. A topological environment composed of the following six routers is an experimental diagram of this part.R1 (IPS1) and R2 (Border1) are EBGP neighbors,
Cough... Some of the code that I wrote recently is a Review ...
But ... I don't know what kind of a ...
The ps:php version is 5.4 so don't tangle [] what's up ... This is the array.
1$rule = [' pid=etfscreenerformsubmit=1etfpage=1cn=cnuscf=go=ta=er=er1 Ry=r1=r3=r5=tac=1erc=1ryc=1r5c=1 ', ' pid=etfscreenerformsubmit=1 Etfpage=1cn=cnuscf=go=ta=er=er2ry=r1=r3=r5=tac=1erc=1 ryc=1r5c=1 ', ' pid=etfscreenerforms
R3
R3 (config) # int ser 0/1 // interface connected to the county-level Router
R3 (config-if) # ip add 192.168.5.1 255.255.255.0
R3 (config-if) # no shut
R3 (config-if) # ip add 192.168.5.2 255.255.255.0
R3 (config-if) # int ser 0/0 // interface connected to internal Ethernet
R3 (config-if) # ip add 192.168.3.1 255.255.255.0
R3 (config-if) # no shut
R4
Router # config t
Router (config) # line con 0
Router (config-line) # logg sy
Router (config-line) # no exec-timeout
Router (config
Cough... some recently written code has CodeReview... but... I don't know which one can pass... PS: the PHP version is 5.4, so don't worry about [] what it is... this is array {code ...} cough... some recently written Code has Code Review...
But... I don't know which one can pass...
PS: PHP version 5.4, so don't worry about [] What is... This is array
// 1$rule = ['pid=etfscreenerformsubmit=1etfpage=1cn=cnUScf=go=ta=er=er1ry=r1=r3=r5=tac=1erc=1ryc=1r
Perform the following experiment in the previous IGP.
Lab requirements:
1. EBGP: R3---R2 R4---R3 R2---R1
2, IBGP: R2---R4 R4---R5 R2---R5
3. All BGP neighbor relationships are established using LO0 for update source (except for R2-R1 ). Use X. X. X.
X as the router-id
4. R3 announcement lo20: 200.200.1.0/24. R5 should select R2.
5.
, the compiler thinks that the result of *q at this time should be the last *p value, will optimize the process of taking the number from the *p, the value of the *p stored in the register directly to *q (POWRPC assembly):Li R5, 2 STW R5, 0 (R3) STW R5, 0 (R4) //write R5 to *qHowever, if you add the volatile
,[pc, #0]. We know that the PC value is the currently executing instruction +8, i.e. the PC value is h->jump[2] = the value of the custom function. OK, that's the equivalent of a jump to execute a custom function. Here's a look at the thumb assembly instructions: if((unsignedLong int) Hook_thumb%4==0) Log ("warning Hook is not thumb 0x%lx\n", (unsignedLong) hook_thumb) H->thumb =1; Log ("THUMB using 0x%lx\n", (unsignedLong) hook_thumb) H->patch = (unsignedint) Hook_thumb; H->orig =addr; H->jumpt
sufficient disks and controllers. You can use the NotesBench benchmark data of the hardware vendor as a guide.
(2) Allocating I/O through physical disks
Generally, physical and logical disk structures are system resources that people often ignore and are the most frequently overloaded. The best way to improve performance on many Domino servers is to allocate I/O through different physical disks.Ideally, put the following I/O-related documents on different physical disks:1) webpage documents on
, there are also bgp vpnv4 neighbors. run the show ip bgp vpnv4 all summary command to view the information. here, the VPNV4 neighbor relationship has been established, and the RT/RD can be carried to the peer end. (private group attributes cannot be passed, so you need to specify a command to enable the transfer ). for RT, on the PE device, both the export and import must correspond to the following: ||||||||| after vrf is configured, the vrf address family is automatically generated in BGP. \/
fields fill the default values, can be understood to delete duplicate key record, new insert a record, An operation that deletes the original record and then inserts . 1.3 But do not know the auto_increment of the primary key has no effect, next test:mysql> INSERT INTO T1 (b,c) Select ' R4 ', ' R5 '; Query OK, 1 row affected (0.05 sec) records:1 duplicates:0 warnings:0 mysql> select * from T1; +---+----+----+ | A | B | C | +---+----+----+ | 1 | C3 |
The experiment requires that the maximum minimum value be removed after sorting, and then the remainder is averaged.Sorting can be sorted with previous bubbles, and the key question is averaging. Because ARM does not have division, how should the average be asked?The simplest way is to subtract, use dividend to subtract the number, see how many times it can be reduced.However, to round up, because the registers are integers, the remainder is compared to half of the divisor, and if it is greater
installation disc to the optical drive, mount it to a directory, and copy all the content of the disc to the/media/cdrom directory.
[Root @ oracle ~] # Mount/dev/cdrom/mnt/iso
[Root @ oracle iso] # cp-r */media/cdrom/
3) modify the rhel-debuginfo.repo file under the/etc/yum. repos. d/directory, edit bashurl to write your own CD path
[Root @ oracle yum. repos. d] # cp rhel-debuginfo.repo rhel-debuginfo.repo.bak
[Root @ oracle yum. repos. d] # vi rhel-debuginfo.repo
+ offsetIn addition, LDR and STR variants LDRD and STRD can also operate the double word (doubleword), that is, one-time operation of two registers, the basic format is as follows: Op{cond} rt,rt2, [Rn {, #offset}]The usage is similar to the prototype, as follows:
STRD
R4,R5, [R9,#offset] ; *(R9 + offset) = R4;*(R9 + offset + 4) = R5
Ldrd
R4,
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