rational numbers calculator

Some of the following functions are covered in Mathematica: RealDigitsRepresentation of decimals in the form of individual digits and their decimal exponent (but missing sign bits) FromDigitsRealDigitsrestores this number from the result, but is expressed as a rational number form (unable to recover missing symbol bit information) SignTaking into account the loss of symbols, you need to get the symbols through the Sign function and mu

Title Description DescriptionThe rational number in any [0,1] p/q (p, q are natural numbers) must be decomposed into 1/r1+1/r2+1/r3+...+1/rk, and R1The program requires finding the maximum decomposition of the p/q. input/output format input/output Input Format:Keyboard input P, q,1≤p≤q≤50output Format:From small to large in the output of each denominator in the decomposition, a line output a number input an

/* Name: scientific calculator (four arithmetic operations of floating-point numbers with parentheses can be implemented) Copyright: Author: Date: 15-09-14 Description: reads a computing expression from a file, converts the computing expression to an inverse polish expression, computes the value of the inverse polish expression, and finally outputs the answer. */ # Include # Include # Include # Include

hard, don't be lazy");//}Console.ReadLine ();3, one-yuan two-time equationax*x+bx+c=0;4, Standard weightConsole.Write ("Please enter gender");String S=console.readline ();Console.Write ("Please enter weight (kg)");Double t=convert.todouble (Console.ReadLine ());Console.Write ("Please enter height (cm)");Double g=convert.todouble (Console.ReadLine ());if (s== "male")//{Double n=t-g+100;if (n>=-3n//{Console.Write ("You are the standard weight");//}else if (n>3)//{Console.Write ("You need to lose

/** * Seek the powers of a number * x^y,y is a positive integer.The calculator can only calculate two number multiplication, cannot calculate n number multiplication at one time.* Know: 2^5= (2^2) ^2*2; 2^6= (2^2) ^3= ((4) ^2); 2^8= (2^2) ^4= (4^2) ^2= 16^2 * Get the rule: x^y= (x^2) ^ (Y/2), define A=X^2,B=Y/2, then get shape such as: x^y= a^b; * y assumes an odd number, then the decomposition of the last multiplied by a (as above 2^6 decompos