rock paper scissors python code

build a Python function rpsls(name) that takes as input the string name , which is one of the ,,, "paper" "scissors" "lizard" , or "Spock" . The function then simulates playing a round of rock-paper-scissors-lizard-spock by g

could change his/her gesture. At the last, who would survive?InputThere is multiple test cases. The first line of input was an integer T ≈1000 indicating the number of test cases.Each test case contains three strings-- b g x . All strings consist of letters and their lengths never exceed 20. The gesture x is always one "rock" of, and "paper" "scissors" .OutputIf

contains three strings --BGX. All strings consist of letters and their lengths never exceed 20. The gestureXIs always one"Rock","Paper"And"Scissors". Output If there is a tie, output"Nobody will keep ve". Otherwise, output"YWill keep ve"WhereYIs the name of the winner. Sample Input 1 akihisa Hideyoshi rock Sa

Problem DescriptionRock, Paper, Scissors is a-a-player game, where each player simultaneously chooses one of the three items after counting to three. The game typically lasts a pre-determined number of rounds. The player wins the most rounds wins the game. Given the number of rounds the players would compete, it's your job to determine which player wins after those rounds has been played.The rules for what

Problem description Rock, Paper, Scissors is a two player game, where each player simultaneously chooses one of the three items after counting to three. the game typically lasts a pre-determined number of rounds. the player who wins the most rounds wins the game. given the number of rounds the players will compete, it is your job to determine which player wins af

(ret,0,sizeof(ret)); for(intI=0; ii) {intmask0=0, mask1=0; for(intj=0;j5; ++j) mask0=mask0*3+A[i][j]; for(intj=5;jTen; ++j) mask1=mask1*3+A[i][j]; for(intj=0; j5;++j) { for(intk=0; Kk) {intt=Lose[j][mask0][k]; ++F[j][t][mask1]; } } } for(intI=0; ii) { intmask0=0, mask1=0; for(intj=0;j5; ++j) mask0=mask0*3+A[i][j]; for(intj=5;jTen; ++j) mask1=mask1*3+A[i][j]; for(ints0=0; s05;++S0) for(ints1=0; s15;++S1) { for(intk=0; Kk) { intt=Win[s1][mask1][k];

/*author:2486memory:0 kbtime:31 mslanguage:gnu g++ 4.9.2result:acceptedpublic:no yes*///for the presence of a certain few interval segments, you can use the prefix and tag, Makes reaching find near O (n) #include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Rock-paper-scissors

This article mainly introduces python applets: scissors, stones, and instance code. it has some reference value, interested friends can refer to this article for details about the python applet: scissors, stones, and instance code

I have written an article based on JS Stone scissors Cloth Program "JavaScript to achieve the stone scissors cloth game source sharing", today and based on Python wrote an example, where the edge of the algorithm is a little special but a moment also unexpected a good algorithm law. Code: Copy