rock paper scissors python

build a Python function rpsls(name) that takes as input the string name , which is one of the ,,, "paper" "scissors" "lizard" , or "Spock" . The function then simulates playing a round of rock-paper-scissors-lizard-spock by g

Problem DescriptionRock, Paper, Scissors is a-a-player game, where each player simultaneously chooses one of the three items after counting to three. The game typically lasts a pre-determined number of rounds. The player wins the most rounds wins the game. Given the number of rounds the players would compete, it's your job to determine which player wins after those rounds has been played.The rules for what

Problem description Rock, Paper, Scissors is a two player game, where each player simultaneously chooses one of the three items after counting to three. the game typically lasts a pre-determined number of rounds. the player who wins the most rounds wins the game. given the number of rounds the players will compete, it is your job to determine which player wins af

Title Link: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3610Surface: Yet another story of Rock-paper-scissors Time limit: 2 Seconds Memory Limit: 65536 KB akihisa and Hideyoshi were lovers. They were sentenced to death by the FFF inquisition. Ryou, the leader of the FFF Inquisition, promised that

Original question: Description Akihisa and Hideyoshi were lovers. they were sentenced to death by the fff inquisition. ryou, the leader of the fff inquisition, promised that the winner of rock-paper-scissors wocould be immune from the punishment. being lovers, akihisa and Hideyoshi decided to die together with their fists clenched, which indicated rocks in th

(ret,0,sizeof(ret)); for(intI=0; ii) {intmask0=0, mask1=0; for(intj=0;j5; ++j) mask0=mask0*3+A[i][j]; for(intj=5;jTen; ++j) mask1=mask1*3+A[i][j]; for(intj=0; j5;++j) { for(intk=0; Kk) {intt=Lose[j][mask0][k]; ++F[j][t][mask1]; } } } for(intI=0; ii) { intmask0=0, mask1=0; for(intj=0;j5; ++j) mask0=mask0*3+A[i][j]; for(intj=5;jTen; ++j) mask1=mask1*3+A[i][j]; for(ints0=0; s05;++S0) for(ints1=0; s15;++S1) { for(intk=0; Kk) { intt=Win[s1][mask1][k];

/*author:2486memory:0 kbtime:31 mslanguage:gnu g++ 4.9.2result:acceptedpublic:no yes*///for the presence of a certain few interval segments, you can use the prefix and tag, Makes reaching find near O (n) #include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Rock-paper-scissors

', ' Ore Gon ': ' Salem ', ' Pennsylvania ': ' Harrisburg ', ' RhoDe island ': ' Providence ', ' South Carolina ': ' Columbia ', ' South Dakota ': ' Pierre ', ' Tennessee ': ' Nashville ', ' Texas ': ' Austin ', ' Utah ': ' Salt Lake city ', ' Vermont ': ' Montpelier ', ' Virginia ': ' Richmond ', ' Washington ': ' Olympia ', ' WestVirginia ': ' Charleston ', ' Wisconsin ': ' Madison ', ' Wyoming ': ' Cheyenne '}Quiz paper file, it needs to have a un