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some problems in data precision. If the data accuracy requirement is not high, you can use it.
alert((0.1 + 0.2).toFixed(1));
The second method is to write the calculation method by yourself. The following is a user-defined addition function. Using this method for addition will avoid the above problem.
// UDF addNum (num1, num2) {var sq1, sq2, m; try {sq1 = num1.toString (). split (". ") [1]. length;} catch (e) {sq1 = 0;} try {sq2 = num2.toString (). split (". ") [1]. length;} catch (e) {sq2 =
Tags: no character format nbsp sysdate start Ceil Special examplesAbout several Oracle functions that handle the number of decimal places ()1. Rounding of several decimalsSelect Round (1.2345, 3) from dual;Results: 1.2352. Reserved two decimal places, onlySelect Trunc (1.234
This article mainly introduces the Java method to keep the double type two decimal places, please refer to the use of itCopy CodeThe code is as follows:Mport Java.text.DecimalFormat;DecimalFormat df = new DecimalFormat ("##### #0.00");Double D1 = 3.23456Double d2 = 0.0;Double d3 = 2.0;Df.format (D1);Df.format (D2);Df.format (D3);The 3 results were:Copy CodeThe co
Method 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemNum=3;float totalPrice=price*itemNum;float num=(float)(Math.round(totalPrice*100)/100);//如果要求精确4位就*10000然后/10000Method 2: Return with DecimalFormat in string format. The class is fully encapsulated in decimal. Like the% number, thousand bits, decimal precision.
Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float Totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*100)/100); If the exact 4-bit is required *10000 then/10000Method 2: Return with
Turn from:Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*100)/100); /If the exact 4-bit is required *10000 then/10000Method 2: R
This article mainly introduces jquery's number after determining two decimal places and automatically deleting two decimal places. If you need a friend, you can refer to jquery's number after determining two decimal places and aut
PHP has two decimal places, and php has two decimal places.
Recently, I am making statistics on this part. There are many data sources related to numbers,
Three functions are used to retain the last N digits after decimal places
Problem description: When using EF's dbcontext to save the decimal type data to the database, the default is to save only the first 2 decimal places after the decimal point, the remaining 0 ; For example, save 101.182352152322, the actual data stored in the database is 101.180000000000;Workaround: When creating the pro
places. However, I think this method has some problems in data precision. If the data accuracy requirement is not high, you can use it.
alert((0.1 + 0.2).toFixed(1));
The second method is to write the calculation method by yourself. The following is a user-defined addition function. Using this method for addition will avoid the above problem.
// UDF addNum (num1, num2) {var sq1, sq2, m; try {sq1 = num1.toString (). split (". ") [1]. length;} catch
There are several ways to do this:var test=11111.111;Alert (test.tofixed (2));float data rounded to 2 decimal places;function To2bits (FLT) {if (parsefloat (flt) = = FLT)Return Math.Round (FLT * 100)/100;to 4 decimal places, return Math.Round (FLT * 10000)/10000;Elsereturn 0;}ASP retains two
In js, the most common method for getting the decimal point and the two decimal points is the rounding function. I have previously introduced this common function in js, which is useful here, next let's take a look at some methods to sum up the two digits after the float decimal point.
Use Javascript to get the first two digits of the float
I have been engaged in ASP. NET in C # development for almost a year. Today I know that the truncation method is not used when the number of decimal places is retained in C.The project uses the truncation method to get the last two digits of the decimal point, so the following method is written:1 /// 2 // truncate a small value by the specified number of
C # decimal retains the specified decimal places,
When decimal retains the specified decimal digits, the. NET method is rounding.
If the project encounters a apportioned amount, the amount in the last line = total amount-sum of the apportioned amount.
This may result in a ne
1. The dumbest way ... [I'll do what I do ...]function Get (){var s = 22.127456 + "";var str = s.substring (0,s.indexof (".") + 3);alert (str);}2. Regular expression effect is good3. He is more clever ...4. Friends who will use new things .... But we need ie5.5+ to support it.from:http://xinlingwuyu.javaeye.com/blog/175931JS retains 2 decimal places after the
Share an interesting test with everyone:
0.1+0.2 = = 0.3//falseSuddenly depressed, OK! The original 0.1+0.2 into: 0.30000000000000004One more 2.4/0.8 =>2.9999999999999996 no way to change it, all of them are converted to integers (2.4 * 100)/(0.8 * 100)10.22 now to subtract 0.11 results and a lot of decimal 10.110000000000001, and then I used the ToFixed method to filter decimals, but I do not know the same as before the conversion to an integer afte
Calculate the circumference rate by using the Newton series, 15 decimal places after the decimal point, Newton's circumference Rate
In the 18th century, mathematicians developed a number of Infinite Series for calculating the circumference rate. Among them, Newton studied the following series:
This Infinite Series is used to calculate the circumference rate to 1
Today, I suddenly thought of the problem of saving decimal places in SQL. I found some practical reference on the Internet, which is very helpful for beginners. If you need it, I can refer to it.
Today, I suddenly thought of the problem of saving decimal places in SQL. I found some practical reference on the Internet,
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