round up to nearest hundred

Title Description:Yuanmai Fifth century, the ancient Chinese mathematician Zhang Chujian in the Book of "The Hundred Chicken Problem": the chicken Weng A value of five, chicken mother a valuable three, chickens three valuable one.Hundred money buys hundred chicken, asks the chicken Weng, the chicken mother, chickens each geometry?Ideas:This question is very simple, suppose the chicken Weng I only, chicken m

//Hundred Chicken Hundred money//the number of cocks for(a =0; a) { //the number of hens for(intb=0; b) { //the number of chicks for(intC=0;c) { //conditions if(a+b+c==100 5*a+3*b+c/3==100) {System.out.println ("Rooster =" +a+ "hen =" +

This is the classic "Hundred Horse Hundred Bear" problem, there are 100 horses, pack 100 of goods, The big horse carry 3, the horse carry 2, two small horse carry 1, ask have big, medium, pony each several horses?Package liu0912;public class Baima {public static void Main (string[] args) {int A,b,c;int i=0;for (a=0;a{for (b=0;b{for (c=0;cif (a+b+c==1003*a+2*b+0.5*c==100c%2==0){System.out.println ("Da Ma:" +

"Huawei OJ" "Algorithm Total chapter" "Huawei OJ" "047-hundred money buy Hundred chicken Problem" "Project Download" topic description公元前五世纪，我国古代数学家张丘建在《算经》一书中提出了“百鸡问题”：鸡翁一值钱五，鸡母一值钱三，鸡雏三值钱一。百钱买百鸡，问鸡翁、鸡母、鸡雏各几何？ 详细描述： 接口说明 原型： int getResult()Enter a description无Output descriptionlist 鸡翁、鸡母、鸡雏组合的列表Input example1Output example0 25 754 18 788 11 8112 4 84Algorithm implementationImportJava.util.Scanner;/** * Aut

//Hundred Horse Hundred//the number of large horses for(a =0; a) { //The number of the horses for(intb=0; b) { //the number of ponies for(intc=0;c) { //conditions if(a+b+c==100 3*a+2*b+c/2==100) {System.out.println ("Big horse =" +a+ "i

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//hundred chicken Hundred Money, the Rooster 2 text Money One, the hen 1 money one, the chicken half article money one//A total of 100 money, how to gather enough 100 chickens in the case just spent 100 of money intCount =0;intBian =0; for(intGong =0; Gong -; gong++ ) { for(intMu =0; Mu -; mu++ ) { for(intXiao =0; Xiao $; xiao++) {

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Hundred money to buy hundred chicken problem is a very classical problem of indefinite equation, the topic is simple: Rooster 5 Money A, hen 3 money A, chicken 3 only a penny,Buy 100 chickens with 100 cents, among them cocks, hens, chickens all must have, ask the rooster, hen, chicken to buy how many only just to make up 100 text money.Analysis: It is estimated that pupils can now manually calculate the pro

bucks can sell up to 20 cocks and require all kinds of chickens to have //So the number of cocks is less than 20 for (int i = 1; i int Gongjicount = i; Number of cocks int mujicount = (200-14 * i)/8;//hen number int xiaojicount = (6 * i)/8;//number of chickens //criteria if (Mujicount > 0 xiaojicount > 0 gongjicount + mujicount + xiaojicount = 100) { c19/>system.out.printf ("Rooster%d, hen%d value, chick%d \ n", Gongjicount, Mujicount, Xiaojicount);}}}

Basic algorithm question-hundred dollar buy hundred chickenTitle: Rooster 5 Text Money One, hen 3 text money A, chicken 3 only a penny, with 100 text money to buy 100 chickens, the rooster, hen, chicken all must have, ask rooster, hen, chicken to buy how many only just to fill 100 of money.Let's start by analyzing:Set the rooster for x only, hen for y only, chick for z only, availablex+y+z=1005x+3y+z/3=100s

How to buy 100 chickens with 100 bucks? Known Rooster 5 pieces One, hen 3 pieces One, chick a piece of money 3 only:A For loop nesting is required, and by optimizing the code, you can speed up the operation.DOCTYPE HTML>HTMLLang= "en">Head> MetaCharSet= "UTF-8"> title>hundred dollars to buy hundred chickenstitle>Head>Body>P>How to buy 100 chickens with 100 pieces, the rooster is known to be 5 pieces A

Problem: Given the coordinates of n points on a plane, find the two nearest points. Solution one. Brute force method (the difference between 22 to find out) time complexity O (n*n) Solution Time Complexity O (N*LOGN) for solving 2:1-D cases Solution III: The idea of divide and conquer, used in general situation The thought is as follows: (1) dividing n points on the plane into two parts left and right according to the coordinate of horizontal direc

/* Title: Rooster One, worth five, hen one, worth three, chicken three, worth one. Hundred money buys hundred chicken, asks the rooster, the hen, the chicken each geometry? */$g: The number of cocks to buy$m: The number of hens to buy$x, number of chickens to buyHow many times $count =0;//statistics calculatedfor ($g =0; $g {for ($m =0; $m {$x =100-$g-$m;if (5* $g +3* $m + $x/3==100 $x%3==0){echo "Can buy

Chinese ancient mathematician Zhang Chujian in "The Book of calculation" of the mathematical Problem: the chicken Weng A value of five, chicken mother a valuable three, chickens three valuable one. Hundred money buys hundred chicken, asks the chicken Weng, the chicken mother, chickens each geometry?How is the go language implemented?Method Onepackage mainimport "fmt"func main() { var n int // i 为鸡翁、j为

Python uses less than one hundred lines of code to implement a small siri, one hundred lines of siri Preface If you want to easily understand the core of feature computing, it is recommended to first look at my previous listening to the song music article, portal: http://www.bkjia.com/article/97305.htm This article mainly implements a simple command Word Recognition Program. The core of the algorithm is aud

js-hundred money Buy hundred chicken case-for cycle production

The question is this:Rooster 5 Text Money One, hen 3 text money A, chicken three only 1 money, how to buy, 100 article just buy 100? First set rooster x only, hen y only, chick Z only Column-Relational: x+y+z=100,5x+3y+z/3=100 concluded: 0 Good! What a beautiful job! All the information you have extracted is complete! Then turn it into a Python language!You must know: Computer computing power is much faster than people, people calculate once, maybe the computer has been cal

Question: Rooster A 5 Yuan, hen a 3 yuan, chicken three only 1 yuan, ask 100 yuan how many chickens can buy?Using System;namespace consoleapplication1{ class program { static void Main (string[] args) { int z, i=0; for (int x = 0; x C # Fun Program---hundred chicken hundred dollars

public class Test04 {public static void Main (string[] args) {int x,y,z;//x represents the number of cocks, Y is the number of hens, and Z represents the number of chickens.for (x=1;xfor (y=1;yif (x*5+y*3z=3* (100-(x*5+y*3))///Get rid of the money that buys the rooster, the hen is the money that buys the chicken,The number of chickens bought is equal to the money of the chickens multiplied by 3if (x+y+z==100) {//The number of all chickens must be equal to 100.System.out.print ("The number of coc