C # math. Round () Achieves Chinese rounding
Math. Round () in C # does not use the "Rounding" method. In fact, in VB, VBScript, C #, J #, T-SQL in the round function are using banker's rounding (Banker algorithm), namely:Four Homes, six in five
The simple floating-point number types in Java float and double are not capable of operation. It's not just Java, it's also a problem in many other programming languages.What will we see if we compile and run the following program?public class Test {
In dealing with some of the data, we want to be able to use the "rounding" method, but C # uses the "four six into 50% pairs" method, such as the following example, is the "four six into 50% pairs" results obtained:Double D1 = Math.Round (1.25, 1);//
The Math object is different from the above object. It can be said to be a common mathematics class, which has many mathematical methods used for various mathematical operations, but Math objects do not need to be constructed, you can directly use
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
double
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
Code
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
Double d1 =
What are the 8 rounding modes for BigDecimal in Java? The following Changsha Obertek Software Institute and everyone together to learn it:Java.math.BigDecimalImmutable, arbitrary-precision, signed decimal number. The BigDecimal consists of an
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
double d1 =
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