PKU 1160 Post Office Quad inequality optimization Classic DPPost OfficeThe classical dynamic programming problem is mainly embodied in the design of the state and the optimization of the quadrilateral inequalities .Test instructions is: give you n
Given a number D, randomly select an approximate sum of D, then divide d by this rounding, form a new D, continue this step, until d=1,We ask for the number of times we want to change D to 1.Set D1,D2...DJ is the d of the line that is divided by the
Test instructions: BC DIV1 1003 (Chinese side)Analysis: Do not consider multiplying the result by 1e6 first. Set Dp[i] The maximum damage exponent that can be obtained for the state of the former I lattice.Then we can enumerate each bomb, the
As the original text has been introduced very well, now is only a few translations and a small supplement.
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Copy Code code as follows:
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Format: 9999.99 (range is 0-9999.99) (dynamically modify Alt
Since the original article has already been quite well introduced, it is only some translation and a small supplement.
Example
CopyCode The Code is as follows:
demo
Format: 9999.99 (range: 0-9999.99) (dynamically modify the alt attribute):
Description
Alexander Charles McMillan loves to gamble, and during his last trip to the casino he ran into ss a new game. It is played on a linear sequence of squares as shown below.
A chip is initially placed on the start square. the player then
DescriptionAlexander Charles McMillan loves to gamble, and during him last trips to the casino he ran across a new game. It is played on a linear sequence of squares as shown below.
A chip is initially placed on the Start square. The player
Topics from NOIP2007TG3If I'm in the examination room, I'm already having a break.Today all day of the time to vote on this question, the harvest is not small.First question.Title Description Description "Problem description"Handsome often play with
http://acm.hdu.edu.cn/showproblem.php?pid=4317
Test instructions
There are n heap of stones, each pile of stones have a certain number of stones, now you can add any number of stones in the heap, so that the initiator will be defeated.
Ideas:
The
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