runtime racing

horse to consume your fastest horse!1#include 2#include 3#include 4#include 5 using namespacestd;6 7 Const intM = 1e3 +Ten;8 intA[m],b[m];9 BOOLcmpintXintY) {returnX>y;}Ten One intMain () A { - intN; - while(~SCANF ("%d", n) N) the { - for(intI=1; I"%d", A +i); - for(intI=1; I"%d", B +i); -Sort (A +1, a+n+1, CMP); +Sort (b +1, b+n+1, CMP); - intSa=1. S =1, ea=n,eb=n,ans=0; +a[0]=a[n+1]=b[0]=b[n+1]=0; A while(n--) at { - if(a[s

possible.Your secret agents has determined the skill of the every member of the opposing team, and of course you know the skill of Eve RY member of your own team. Information to decide which opposing player would play against each of the your players in order to maximize Y Our score. Assume that the player with the higher skill in a game would always win, and if the players has the same skill then they w Ill draw.You'll be given the skills of your players and of the opposing players, you have t

Links: http://hihocoder.com/problemset/problem/1224Deep Search to find the maximum depth, from the maximum depth of the leaves back to the root of each vertex through the deep search for maximum depth#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. Hihocoder 1224: Racing

Topic Connection: PortalTest instructionsGive you a tree, and then add an edge, plus this side can not make the tree into a ring, seeking to add edge after the longest path from the root node.Analysis:If you can add edge then these two chains must be a node of the longest chain and the second chain, and then DFS processing all the nodes of the depth, and then again DFS to find all the points of the longest chain length and the length of the second chain, and then enumerate the nodes can be.The c

();} while(ch>='0'ch'9') {x=x*Ten+ch-'0'; ch=GetChar ();} returnx*F;}//**************************************************************************************Vectorint>E[MAXN];intFA[MAXN];intDEP[MAXN];intKEY[MAXN];voidDfsintXintDeep ) {Dep[x]=Deep ; for(intI=0; I) { intv=E[x][i]; if(Key[v])Continue; FA[V]=x; DFS (V,deep+1); }}intMain () {intn=read (); for(intI=1; i) { intA=read (), b=read (); E[a].push_back (b); } DFS (1,1); intmx=0, BJ; for(intI=1; i) { if(d

Thinking very ingenious a greedy topic, the overall principle is not win you I will try to drag your good horse into the water.Title Address: Click to open the link#include Nanyang Tian Bogey Horse racing

Lufylegend engine is one of the simpler engines in the canvas game, it does not need to configure the environment, similar to the introduction of jquery package, reference to the corresponding JS file can beLufylegend Official website: http://www.lufylegend.com/First look at the gameGame design is rough, logic is also very simple, is to control the red car by clicking around to avoid the opposite of the car, if there is a collision, the game is over, and the game will be faster and faster.Game D

Tian Ji's horse racing is a classic greedy, but it's hard to think of it. Every time you use the fastest and fastest, the slowest and the slowest to compare and judge 1) if Tian shortest is slower than Wang shortest, he will lose the game using the slowest comparison with Wang shortest. Otherwise, winning is of course the most cost-effective choice. 2) if Tian is slower than Wang, he will lose the game with the slowest comparison with Wang. Thes

(USART1, usart_flag_txe) = = RESET); Μè′y ￠?í?áê? } while (1) {while (Usart_getflagstatus (USART1, usart_flag_rxne) = = RESET); Μè′ypc?úμ?êy? Yμ?à′i = Usart_receivedata (USART1); ? óê?êy? Y if (i== ' 9 ') i= ' 0 '-1; if (i== ' z ') i= ' a '-1; if (i== ' Z ') i= ' A '-1; Usart_senddata (usart1,i+1); ￠?íò??? Êy? Y while (Usart_getflagstatus (USART1, usart_flag_txe) = = RESET);//μè′y ￠?í?áê? }}*//**/intMainvoid) {usart

First, STM32F103C8 pin distributionSecond, the LED common Yin, common yang connection methodThis should be the connection of the seven-segment digital tube.The current limiting resistor is selected as 470, and the multism is also required to be plugged in, otherwise flashing occurs. or change the properties directly.Third, remove the mechanical vibration of the button 1, the characteristics of the keyThe keyboard is composed of several independent keys, the press and release of the key is achiev

pathfinding.So I want to add an auto-pathfinding car with a more realistic turning tyre.That is, as the speed of the car accelerates, the tires turn faster, the speed slows down, and the tires turn slower.So we need to convert from speed to the current number of degrees per second:The current car speed is N/s,Tyre radius is r mThe car speed is N/(2 * R * π)Car tires per second N/(2*r*π) * 360°The code is as follows: void FixedUpdate() { _angularSpeed = (_thisCarNavMesh.velocity.mag

Android:layout_width= "Match_parent" android:layout_height= "48DP" Android:ellipsize= "Marquee" Android:focusable= "true" Android:singleline= "true" Android:textcolor= "#912CEE" Android:textsize= "18SP" Android:focusableintouchmode= "true" android:marqueerepeatlimit= "Marquee_forever" Android:scrollhorizontally= "true" Android:text= "International Online Report: The president's visit to the United Kingdom was the first state visit to the United Kingdom on the occasi

Hentai Parkour 3D (Endless Run 3D) released Hentai Parkour 3D is a very classic parkour mobile game, the game has a unique running cool gameplay, cool running cool features and exquisite game screen design. Interested partners come and join the endless Parkour 3D hand Tour Try it! This is a good game yo! Game Introduction"Endless Parkour 3D" is a background set of sci-fi obstacles in outer space run Cool Hand tour, game with the first person view running cool play, the interpretation of the thri

Poj 2287 Tian Ji -- The Horse RacingPoj 2287 Tian Ji -- The Horse RacingQuestion:Tianji horse racingIf three horses are changed to 1000, Qi Wang still sets his horse to compete in the order of superiority to inferiority. Tian Ji can select his horse racing in any order. If you win a game, Tian Ji will get 200 silver coins. If you lose one game, Tian Ji will lose 200 silver coins.How much money can Tian Ji win at most?Ideas:Greedy;If Marco is the best

With the emergence of micro-services, the management of services is extremely important. All know that microservices are "split", the bloated single-block application, split into a number of lightweight services, each service can be in a short period of time to reconstruct, iterate, delivery. With the increase in the number of micro-services, due to quantitative quality, resulting in a new problem one of which is the management of services. With the growth of micro-services in the business, it i

First, the team situation briefwrite in front: team positioning, we are a group of 5 people, but the overall basic programming ability is not too good, the team's self-evaluation is not high, so the initial project target is relatively low, if the project is still in the process of completion, in consideration of project development. team Name: Old driverMembers:Captain: DongqiangqiangTeam 1: GaoqingyangTeam 2: affiliatingTeam 3: DingTeam 4: Zhang Zhenxin (real thigh)Team Training: driver in pos

/* Main topic: Tian Bogey and King horse racing, Tian bogey every win a game can win 200 yuan, lose 200, draw no profit or loss. Eg:3---On behalf of each person has a few horses, the----Tian bogey horse----------The King's horse greedy strategy: first, when Tian bogey fastest King ponies the fastest horse, with Tian bogey fastest horse win the King's fastest horse. Second, when Tian bogey the fastest ponies king of the fastest horse slow, with Tian bo

The Description10 Galaxy Racing competition is about to start again. As one of the biggest events in the Galaxy, the winner of this project is undoubtedly the dream of many people, and the one from Jason's Alpha star. The race is made up of N planets and M two-way interstellar routes, each of which has a different gravitational value. The competition asked the riders to start with a celestial body that had no route between the N planets, and to visit

Topic 2: Racing time limit:20000msSingle Point time limit:1000msMemory Limit:256MBDescribeGensokyo has a racetrack. There are n locations in the racetrack. There is also a one-way road between locations.These roads make the racetrack a structure of an outward tree. In other words, the road connects the n sites into a tree with a root. And all the edges are from the father pointing to the child.Because the fragrance likes to stimulate, every time she g

[Summary] How many secrets does Microsoft have for Excel racing games? (1) Word2000: Fox and lazy dog This is early. Use the English input method in a blank Word2000 (or later) = Rand (200,99) Then press Enter. What do you see? The "The quick brown fox jumps over the lazy dog." (word2003 is the Chinese translation of this sentence)Don't scare you! (2) who are Hu Wanjin? 1. open Word (97 or above)2. input the Chinese character "Hu" in the word"