same birthday probability calculator

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Birthday Paradox lightoj 1104 Birthday paradox (probability)

DescriptionSometimes some mathematical results is hard to believe. One of the common problems is the birthday paradox. Suppose you is in a party where there is people including you. What's the probability that at least and the party has same birthday? Surprisingly the result is more than 0.5. Now this is the opposite. You are given the number of days in a year.

Lightoj 1104-birthday Paradox (Birthday paradox probability)

Title Link: http://lightoj.com/volume_showproblem.php?problem=1104Test instructions: 365 days a year, in the case of 23 people, two of these 23 people have the same probability of birthday is greater than 0.5;Now on different planets for n days a year, to find X, at least x person to make two people in this x of the birthday of the same

LightOJ1104---birthday Paradox (Birthday paradox (probability)) _ACM contest

"topic source": https://cn.vjudge.net/problem/LightOJ-1104MeaningThe question of the birthday paradox, which describes the logical logic of the paradox, 23 people any two of the same birthday probability is 0.507, the general idea will be ridiculous.And these are calculated by mathematical methods.And the question is, if not on the Earth, that is, the size of a y

Interesting probability algorithm--Birthday paradox

In the algorithm introduction book see a more interesting probability algorithm, here add their own understanding to share under: The last time I just saw the friends of the circle said:" two people in the same dormitory, and the same year, the same day, this fate is really drunk ", I was drunk, looked at the algorithm after the discovery, the house has a person, then you can The probability of 50%

Calculate the same probability of birthday

DescriptionSometimes some mathematical results is hard to believe. One of the common problems is the birthday paradox. Suppose you is in a party where there is people including you. What's the probability that at least and the party has same birthday? Surprisingly the result is more than 0.5. Now this is the opposite. You are given the number of days in a year.

Light OJ 1104 Birthday Paradox (probability problem)

Sometimes some mathematical results is hard to believe. One of the common problems is the birthday paradox. Suppose you is in a party where there is people including you. What's the probability that at least and the party has same birthday? Surprisingly the result is more than 0.5. Now this is the opposite. You are given the number of days in a year. Remember th

LightOJ1104---Birthday Paradox (probability)

Sometimes some mathematical results is hard to believe. One of the common problems is the birthday paradox. Suppose you is in a party where there is people including you. What's the probability that at least and the party has same birthday? Surprisingly the result is more than 0.5. Now this is the opposite. You are given the number of days in a year. Remember tha

Lightoj 1104-birthday Paradox "probability"

Title Link: http://www.lightoj.com/volume_showproblem.php?problem=1104Test instructions: Birthday refutation, ask for the minimum number of people to meet the conditionsCode:#include #include #include #include #include #include #include #include #include #include #include using namespace STD;intTintNintdp[100010];intMain () {Cin>> T; for(intCA =1; CA memset(DP,0,sizeof(DP));Cin>> N;cout"Case"": ";if(n = =1)cout1Else{DoubleAns =1.0;intI for(i =1; I 1.0

Python probability calculator instance analysis

This article mainly introduces the implementation method of the python probability calculator. The example analyzes the Python probability calculation technique and has some reference value, for more information about how to implement the python probability calculator, see t

Python Probability Calculator Example analysis _python

This example describes the Python probability calculator implementation. Share to everyone for your reference. The implementation method is as follows: From random import randrange #randrange form random Module def calc_prob (strengths): "" "A function that receives A arr Ay of two numbers indicating the strength of each party and returns the winner "" "If Strengths[1]>strengths[0]: #Bring the bigger

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