C # Eliminate the Sawtooth when generating the verification code image,Introduction
A mobile phone number can be converted to an image based on the generated image. The content is also very simple. You can use your mobile phone number to generate a png image. It is to make the background transparent so that it can be called elsewhere. The Code g. TextRenderingHint = TextRenderingHint. AntiAlias;
Generating Images
1. serticate
2. Non-
Believe that many people have used the use of border to achieve the small triangle arrow, Baidu, this kind of article a lot of, here I still wordy point to the common methods of display:. Triangle_border_up { width:0; height:0; border-width:0 30px 30px; border-style:solid; border-color:transparent transparent #333; /* Transparent transparent gray */ margin:40px auto; Position:relative;}Or:. Border_bottom { width:0; height:0;
Let's give you a detailed explanation of the method for creating non-Sawtooth clear text.Tutorial sharing:Leverage the "rasterized" anti-Sawtooth capabilitySpecific settings: Effect-raster... (do not use the raster under the object, so the text cannot be edited again !)All right, the above information is the detailed method for creating non-Sawtooth
Description: Adjust Firemonkey Android display text with "jagged" effectFor: Firemonkey Android PlatformModification Method:Please make the source FMX. FontGlyphs.Android.pas Copy to your project directory and make changes.// find this line. Fpaint.setantialias (True);//anti-aliasing // change to the following Fpaint.setantialias (False); SerrateEffect:Upper (anti-aliasing) Fpaint.setantialias (True);Bottom (Sawtooth) Fpaint.setantialias (False);Adjus
Author: gogocome Source: Blue ideal
Generally, when a transparent GIF image is stored, the image is directly stored without any appearance, shadow, or external light, unless the opaque area of the image is a regular rectangle.
Online design: the trick in this article is to use Photoshop to save images with the "Miscellaneous" option, we can "define the color and mix the transparent pixels" to solve the problem of the Sawtooth edge of the transparent
Zoj 3814 sawtooth puzzle
Question Link
A wide range of searches are recorded, and 9 puzzles are compressed into one state and then searched, which means the simulation process is troublesome.
Code:
#include
Zoj 3814 sawtooth puzzle)
Windows7 Earlier versions began, there is always the problem of playing video files with Sawtooth. Even watching online video files, such as popular, Uusee and thunder to see, there are similar problems. At first, many users thought it was RealPlayer, Storm audio and video, Thunder and other players and Windows7 compatible with the bad, but later, users found that other audio and video player problems still exist.
In general, the Windows7 playback of
ZOJ 3814 Sawtooth Puzzle status compression search
Since there are only four statuses in a box, the total number of statuses is only 4 ^ 9, and bfs can be solved.
The trouble lies in simulation.
The method of saving my status is to regard the initial status as 000000000. If it is rotated once clockwise, + 1, 3 + 1 = 0.
During the bfs process, you need to set a dfs calculation to which boxes will be affected by rotating the current box.
Note that there
Input212Sample OutputCase #1:2Case #2:19Source2014 ACM/ICPC Asia Regional Shanghai Online Problem Solving:Each m four edge, each edge at most with the original edge intersection, forming a n-1 intersection, is not related to Euler theorem?? Then the team-mates magically moved out F (n) =f (n-1) +4*4* (n-1) +1; then came out 8*n^2-7*n+1 ...Well, the point is that he used the formula directly with the C + + large number template T. So, I used the Java large number of classes handed a pitch, 1900m
* n/2 + 1-N * 9 = N * (8 * N-7) + 1
Because N is a maximum of 10 ^ 12 ,__ int64 (long) is 9*10 ^ 18, N * n will overflow data. If there is no computing time complexity at the beginning, a common big number operation is used, and the result times out. Later, the senior engineer said that the big data was optimized,
Is to divide a large number into two parts, respectively, with _ int64.
To prevent the overflow of the two-digit multiplication data, the right half of my number is nine digits. For e
Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5047
Problem descriptionthink about a plane:
● One straight line can divide a plane into two regions.
● Two lines can divide a plane into at most four regions.
● Three lines can divide a plane into at most seven regions.
● And so on...
Now we have some figure constructed with two parallel rays in the same direction, joined by two straight segments. it looks like a character "M ". you are given n such "M" S. what is the maximum num
Question: Find n 'M'-type broken lines to divide a plane into the largest number of faces!Idea: we all know that n straight lines divide a plane into a maximum number of planes: An = An-1 + n + 1That is, F (n) = (N * n + 2)/2What about a line of 'M' type? It has four lines, but the plane is divided due to the relationship between the three vertices.The number is reduced by 9! So there is a recursive formula F (n) = (M * m + 2)/2-9 * n; M = 4 * n Finally, F (n) = (8 * n + 1) * (n-1) + 2)Since n
Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5047
Solution Report: Ask a "M" type to divide the plane of a rectangle into a maximum of several blocks.
The input has n "M". Now the formula is 8 * n ^ 2-7 * n + 1, but the range of N is 10 ^ 12, as long as the square is within the range of long, what should we do with a large number?
I 've tried it all. It's strange that it will time out. I don't think it will happen according to estimation. Maybe it's because the intermediate res
Hdu 5047 Sawtooth combined mathematical precision, hdusawtooth
Question link: Click the open link
Question: omitted
Train of Thought: transfer the card .. I don't want to talk much about it. I mainly want to record the fast reading and writing of java to prevent such bad questions from coming into being next time.
Cpp version:
#include
Java version:
import java.util.*;import java.io.*;import java.math.*;public class test {public static void main
ZOJ 3814 Sawtooth Puzzle status compression search, zoj3814
Since there are only four statuses in a box, the total number of statuses is only 4 ^ 9, and bfs can be solved.
The trouble lies in simulation.
The method of saving my status is to regard the initial status as 000000000. If it is rotated once clockwise, + 1, 3 + 1 = 0.
During the bfs process, you need to set a dfs calculation to which boxes will be affected by rotating the current box.
Note t
Last two articlesArticleNeither of the methods described can be the best way to implement the anti-sawtooth font. Let's see how the master did it.
Fr é d é Ric Lavigne, author of the famous skin L F and webmaster of www.javootoo.com, a great repository of look and feels for swing, didn't think so and found an elegant and clever way to get the same result
Okay, for simplicity, jar package
Http://download.csdn.net/detail/laizhenhai88/5094403
As lon
Since there are only four statuses in a box, the total number of statuses is only 4 ^ 9, and BFS can be solved.
The trouble lies in simulation.
The method of saving my status is to regard the initial status as 000000000. If it is rotated once clockwise, + 1, 3 + 1 = 0.
During the BFS process, you need to set a DFS calculation to which boxes will be affected by rotating the current box.
Note that there are more than one target status, because some boxes remain unchanged after rotation, we must ca
The Win7 system plays the video movie to appear Sawtooth, mosaic, blur how to do?
1, click "Start-Control Panel-system-Advanced system settings;"
2. In the Pop-up System Properties dialog box, switch to the Advanced tab and click Settings in the Performance area.
3, in the pop-up "Visual Effects" tab, click "Custom", will "enable desktop combination" before the check to remove;
4, after the modification, save the settings to e
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