scout rfp

Basic knowledge points: 1. What is scout? Scout (codenamed monocle) is a tool for SwF performance analysis. It records and analyzes CPU and memory in detail. We must inevitably ask what is different from the analyzer in Flash builder? First, scout analysis is very detailed and comprehensive, and second, scout can not

POJ 3744 Scout yyf I matrix rapid Power Optimization-probability dpClick Open Link Scout YYF I Time Limit:1000 MS Memory Limit:65536 K Total Submissions:5416 Accepted:1491 DescriptionYYF is a couragous scout. now he is on a dangerous mission which is to penetra

Release date: 2011-12-14Updated on: 2011-12-15 Affected Systems:Ibm aix 7.xIbm aix 6.xIbm aix 5.xDescription:--------------------------------------------------------------------------------Cve id: CVE-2011-1384 AIX is an open standard UNIX operating system that provides you with an enterprise information technology infrastructure. Ibm aix has two implementation vulnerabilities that can be exploited by malicious local users to operate certain data and perform certain operations with elevated p

Tags: des style blog color Io OS AR for strongScout yyf I Time limit:1000 ms Memory limit:65536 K Total submissions:5020 Accepted:1355 DescriptionYyf is a couragous scout. now he is on a dangerous mission which is to penetrate into the enemy's base. after overcoming a series difficulties, yyf is now at the start of enemy's famous "Mine Road ". this is a very long road, on which there are numbers of mines. at first

Scout YYF I Topic Connection:http://poj.org/problem?id=3744Test instructionsThere is a person to go to a place called "Mine Road", the route is a straight line, starting point in 1, the road has n mines, coordinates between [1, 100000000], this person each time have P (0.25≤p≤0.75) probability forward step, and have 1-p probability forward two steps, The probability that this cargo is safe to reach "mine road" through the minefield.ExercisesBy us

DescriptionYyf isA couragous Scout. Now he isOn a dangerous mission which isTo penetrate into the enemy's base. After overcoming a series difficulties, YYF are now at the start of enemy'S famous"Mine Road". This isA veryLongRoad, on which there is numbers of mines. At first, YYF isAt step one. For each step after that, Yyf'll walk one step with a probability of p, or the jump in step with a probality of1-P. Here isThe task, given the mine, please calc

Static voidMain21 Scout (string[] args) { //A reconnaissance team received an urgent task requiring as many persons as possible in A, B, C, D, E and F six players, subject to the following restrictions://Scout A and B at least one of the two men; A+b>=1//A and D cannot go together; A+d//A, E and F three shall send two men; a+e+f = = 2//B and C neither go nor go; B+c!=1//C and D Two of people go t

Poj 3744 Scout yyf I (matrix optimization probability), pojyyf Http://poj.org/problem? Id = 3744 There are n mines. The starting position of a person is 1. The probability of each step is p. The probability of two steps is 1-p, and the position of n mines is given, ask the probability of successful exit from the minefield. In high school, it should be a simple step-by-step multiplication to calculate the probability. That is, the probability that ea

;=1; - } - returnsum.a[0][0]; - } - intMain () { - intNDoublep; in while(SCANF ("%d", n)! =EOF) { -scanf"%LF",p); to for(intI=1; i) +scanf"%d",a[i]); -Sort (A +1, A +1+n); the BOOLflag=a[1]==1?true:false; * for(intI=2; i) $ if(a[i]==a[i-1]+1) flag=true;Panax Notoginseng Doubleans; - if(a[1]==1) flag=true; the if(flag) ans=0; + Else{ A Matrix F; thef.a[0][0]=p,f.a[0][1]=1-p; +f.a[1][0]=1, f.a[1][1]=0; -ans=1;in

http://poj.org/problem?id=3744 (Topic link)Test instructionsGive N Thunder, respectively in A[1]...a[n], take one step probability for P, walk two steps probability for 1-p, a start in position 1th, ask the probability of safe to reach the end.SolutionIt is obvious that dp:f[i]=p*f[i-1]+ (1-p) *f[i-2]. Consider the a[i] position of thunder, then the probability of safe passage is to reach f[a[i]+1] The probability is: f[a[i]-1]* (1-p).Because A[i] is very large, so we want to segment with a matr

Celestial Bodies "てんたい" Celestial bodies. Stars, planets, nebulae To Peel く"めをむく" (by anger or surprise) and stare at the eyes. しかめる frown, showing an unpleasant or painful mood Solid "こしゅう?こしつ" Stubborn. Stubborn insistence Trouble "なんぎ" difficult; ぼそぼそ Dry Representations "しるし" precursor, indication Mistaken felt "さっかく" illusion; wrong idea; misunderstanding, wrong thinking Drunken mad "すいきょう" curious; ぐりぐり with a hard object to turn Slew Zhe "へんてつ" is surprisingl

http://poj.org/problem?id=3744Matrix Fast Power:DP-based recursiveIn the case of dp[i] = P*dp[i-1] + (1-p) *dp[i-2]Since x is very large and up to 100 million, the complexity of this is 100 million.So here you can use the matrix idea[Dp[i] dp[i-1]] = [dp[i-1] dp[i-2] | P 1-p|| 1 0 |Recursion to getN-1[Dp[n] dp[n-1]] = [dp[1] dp[2]] |p 1-p|| 0 |Note that I have separated the matrix and determinant here!!!(because forget the line generation, tangled for four or five days-always thought the last st

; k++) Ret.mat[i][j]+=a.mat[i][k]*B.mat[k][j]; } returnret;} Mat Pow_m (Mat A,intN) {MAT ret; memset (Ret.mat,0,sizeof(Ret.mat)); for(intI=0;i2; i++) ret.mat[i][i]=1; Mat Temp=A; while(n) {if(n1) ret=Mul (ret,temp); Temp=Mul (temp,temp); N>>=1; } returnret;}DoubleQ_mul (intk) {Mat A; a.mat[0][0]=p, a.mat[0][1]=1.0-P, a.mat[1][0]=1.0, a.mat[1][1]=0; MAT ret=pow_m (a,k); return(f2*ret.mat[1][0]+f1*ret.mat[1][1])*(1.0-p);}intMain () {intN; while(cin>>n>>p) {memset (place,0,sizeof(pla

Poj 3774 Scout yyf I (probability DP of matrix optimization)Question: n lei, in a [1]... a [n], where the probability of one step is p and the probability of two steps is 1-p. At the beginning, the probability of Security reaching the end point is asked. Ideas: Divide the entire process into stages for processing: 1 ~ A [1] A [1] + 1 ~ A [2] ............ A [n-1] + 1 ~ A [n] Then, you only need to find the probability of stepping on the thunder each ti

POJ 3744 Scout yyf I (probability DP + rapid matrix power) Address: POJ 3744 A linear probability DP recursive formula. Dp [I] = p * dp [I-1] + (1-p) * dp [I-2]. However, the I value is too large. Therefore, it can be divided into n times, and the pure recursive process of each intermediate process is optimized by the matrix Rapid power. It is easy to think of the Rapid power of a matrix. The Code is as follows: #include #include #include

Scout yyf I Time limit:1000 ms Memory limit:65536 K Total submissions:3723 Accepted:928 Description Yyf is a couragous scout. now he is on a dangerous mission which is to penetrate into the enemy's base. after overcoming a series difficulties, yyf is now at the start of enemy's famous "Mine Road ". this is a very long road, on which there are numbers of

"; inattention. く"くじく", twist, twist, bruise, twist, sprain, squat To moistened together う"やりあう" to do, argue, argue. Earpick "ひきでもの" (when the host rewards the guest) giveaway, souvenir くるめく"めくるめく" dizziness; dazzling. Blood う"ちまよう" (horror, anger, grief, etc.) crazy, unable to self-control Jane Han "とんちんかん" (speaking and doing things) inconsistent before and after contradictions; stupid things. オブラートoblaat; rice paper, glutinous rice paper. Paper head for the package of drugs and

Tags: des style color Io OS AR for strong sp Time limit:1000 ms Memory limit:65536 K Total submissions:5062 Accepted:1370 DescriptionYyf is a couragous scout. now he is on a dangerous mission which is to penetrate into the enemy's base. after overcoming a series difficulties, yyf is now at the start of enemy's famous "Mine Road ". this is a very long road, on which there are numbers of mines. at first, yyf is at s

Scout YYF I Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 9564 Accepted: 2799 Description Yyf is a couragous scout. Now he's on a dangerous mission which are to penetrate into the enemy ' s base. After overcoming a series difficulties, YYF are now at the start of enemy ' s famous "Mine Road". This was a very long road, on which there is numbe

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