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Requirements: Remove duplicate elements from the ArrayList collectionImport Java.util.*;class arraylisttest{ Public Static void Main(string[] args) {ArrayList Al =NewArrayList (); Al.add ("1"); Al.add ("2"); Al.add ("1"); Al.add ("2"); Al.add ("1"); Al.add ("3"); Al.add ("4"); Al.add ("1"); SOP (AL); ArrayList Newal = Singleelement (AL); SOP (Newal); System. out. println ("Hello world!");//The next call in the loop in the iteratio

descriptions followed by a pair of zeroes each edge description would con Sist of a pair of integers; The first integer identifies the node from which the edge begins, and the second integer identifies the node to which the Edge is directed. Node numbers is always greater than zero.OutputThe For all test case display the line ' case K is a tree. ' or the line ' case K ' is not a tree. ', where k corresponds to the Te St Case number (they is sequentially numbered starting with 1).Sample Input6 8

This is a mountain hkust classmate gave me a question, ask me the idea, for mathematical modeling, I do not have much understanding, so can only use computer program method to answer.This is the specific question:This problem comes from the K-mer index problem of DNA sequences.given a DNA sequence, this series contains only 4 letter ATCG, such asS ="Ctgtactgtat". Given an integer valuek, fromSstart at the first position, take a continuouska short stri

\NuGet.Config C:\Users\Administrator\AppData\Roaming\NuGet\ Nuget.configfeeds used: https://dotnet.myget.org/f/dotnet-core/api/v3/Index.json https: //api.nuget.org/v3/index.json3. Enter the command to start dotnet Run and start the program.d:\asp.net> for dnxcore,version=v5.0compilation succeeded. 0 Warning (s) 000:00:03.2201958HelloWorld!4, that's how it works, it's easy to get started.// Program file Public class program {

InvestigationTime limit: 1 Sec memory limit: MBSubmitted: 10 Solution:Submitted State [Discussion Version]Title Description Ezio As an assassin, investigative intelligence is an essential part, such as the target of recent activities such as the arrangement of information is very useful.Ezio now has a survey list of n individuals, each with a number, numbered between 1 and M, the number of which is recorded by this person is related to which information, Ezio now to investigate 1 to m all intell

This paper is divided into two parts: Analysis of $5$ (total $50$), algebraic $5$ (total $50$). Exam Time: $120$ minutes1. ($ $) to which real numbers $\al$, series $\dps{\vsm{n}\sex{\frac{1}{n}-\sin \frac{1}{n}}^\al}$ converge?2. ($6 ' $) Set $y $ is $[0,1]$ on the $C ^1$ smooth real function, satisfies the equation $$\bex y ' (x) +y ' (x)-y (x) =0,\quad x\in (0,1), \eex$$ and $y (0) =y (1) =0$. Trial: $y (x) =0,\ x\in [0,1]$.3. ($ $) Set $f $ is a bounded continuous real function on $\bbr^2$,

the elimination of a few letters and then there are two letters adjacent to continue to erase.Ideas:　　Ditto.The code is implemented as follows:　　1#include Set>2#include 3#include 4#include 5#include 6#include 7#include 8#include string>9#include Ten#include One#include A#include -#include - using namespacestd; the -typedefLong Longll; -typedef PAIRPLL; -typedef PAIRint>Pli; +typedef pairint, ll>pil;; -typedef pairint,int>PII; +typedef unsignedLo

/plugins/output/config:html_file>>>set verbose True w3af/plugins/output/config:html_file>>>backthe configuration has been saved.w3af/plugins>>>BACKW3AF>>> startSuccessfully swept out 8 URLs and different injections points.Sweep with Sqlmap." http://www.testfire.net/bank/login.aspx " " Uid=adminpassw=abtnsubmit=login "Detect some information from the background databaseEasily login in http://www.testfire.net/bank/login.aspx by constructing admin '--input.But how do you get the information in the

Windy defines a windy number.A positive integer with a difference of at least 2 2 without a leading 0 and an adjacent two digits 2"> is called the windy number. Windy want to know, in A ">a A and B " > b B, including A ">a A and B " > b B, how many windy are there in total? InputContains two integers,A">aa B"> bB. Meet 1#x2264;A#x2264;B#x2264;2000000000"> 1≤A≤B≤20000000001≤a≤b≤2000000000.O

Msmset1 /* sets the first count bytes of the memory area in buffer to character C and returns a pointer to buffer */ 2 #include string.h>3externvoid *meeset (void * Buffer,int c,int count);Gets1 /* Gets the string function read from the standard input device. Can be read indefinitely without judging the upper limit to return to the end of the read, so the programmer should ensure that buffer space is large enough so that no overflow occurs while the read operation is performed. */2 #include 3ch

0,17,16,20,19. There is breeds of cows; The first Moos at a volume of 5, and the other at a volume of 7.There is 2 cows of breed #1 and 1 cow of breed #2 in Fiel D 2, and there isAnother cow of breed #1 in field 4."Analysis" by test instructions know, each area of the sound size in addition to itself only by the previous region, minus the impact of the previous area, only the sound of their own production, the minimum number of cattle, is a complete

To give you a grid with a height of n and a width of M, to figure out how many rectangles there are in this grid.Here we can see this:For rows: If it is M-unit length, the rectangle with length 1 has m, and the rectangle of length 2 has m-1 ... The length of M is only 1, so the total rectangle is 1+2+...+m= (1+m) *M/2For columns: peers can.So, the total number of rectangles = row * column. The general formula N (m,n) = (1+m) * (1+n) *M*N/4 is obtained

Dou refers to the southeast, the dimension is Li Xia Zhong, all things have grown up. Li Xia Zhong, star creators in the Huaqing Vision Beijing headquarters also completed half a month of study and life. Faded from the beginning of the strange and awkward, now they have gradually become familiar with each other, to learn to work together to fight the comrades, life mutual help small partners. With the gradual harmony of the class, it is time to hold the first class meeting since the admission!Ma

of thes E-options are more advantAgeous for him. This year, Max pays for the insurance CRubles. If He does not register the accident and then the next year he'll payC+DRubles, then.C+ 2DRubles, and so on, each following year the cost of insurance would riseNBSP; d rubles. If He registers the accident, then ForNBSP; k years, starting from the next one, Max'll has to pay for InsuranceNBSP; p percent more. So the next year he'll pay (NBSP; c +NBSP; d ) · (1 +NBSP; p /100) rubles, then (

Binary sort tree Non-recursive insert code1#include 2#include 3#include string.h>4#include malloc.h>5typedefstructnode6 {7 intVal;8 structnode*Lchild;9 structnode*Rchild;Ten}node,*Pnode; One A - intCreattree (Pnode *root,intArr[],intlen); - intInserttree (Pnode *root,intelem); the intPrinttree (Pnode root,intlen); - voidinorder (Pnode root); - - + - + intMainintargcChar*argv[]) A { at intArr[] = {5,8,7,9,4,Ten,1}; - intLen =s

ID Origin Title 10/29 Problem A Codeforces 443B Kolya and Tandem Repeat 1/1 Problem B Codeforces 442A Borya and Hanabi 9/29 Problem C Codeforces 442B Andrey and problem 3/17 Problem D Codeforces 442C Artem and Array 14/18 Problem E Codeforces 369A Valera and Plates 12/28 Problem F

ID Origin Title 10/52 Problem A Spoj amr10a Playground Problem B Spoj amr10b Regex Edit Distance Problem C Spoj amr11c Robbing Gringotts 1/14 Problem D Spoj amr10d Soccer Teams 0/3 Problem E Spoj amr10e Stocks Prediction 17/19 Problem F Spoj amr10f Cookies Piles

the product of the general process of the birth of Internet products (Part I)15th Lesson The vision of the product of the general process of the birth of Internet products ( Part I)the 16th lesson why the general process of the birth of Internet products to do competitive product analysisThe 17th class of the Internet product birth of the general process of competitive product analysis commonly used methods18th Lesson 4 Reasons to write a requirement

ID Origin Title 0/5 Problem A HDU 4116 Fruit Ninja 3/10 Problem B HDU 4127 flood-it! Problem C HDU 4130 Shadow 33/61 Problem D HDU 4161 Iterated difference 15/35 Problem E HDU 4162 Shape number 32/39 Problem F HDU 4165 Pills 2/25 Problem G HD

; i) {gets (_a); intK =0; while(_a[k]! ='-') k++; _a[k-1] =' /'; _s= (string) _a; _t= (string) (_a + k +4); PRVE[MAP[_T]]|= (1map[_s]); }}intdp[(1 -)+5];voidDP () { for(ints=0; s1) { int_num =0; for(intI=0; i) {_num+ = ((s >> i) 1); } for(intI=0; i) { intSS = S | (1i); if((S >> I 1) !=0) || ((S prve[i]) = Prve[i]))Continue; if(_num = =0 Prve[i] = =0) {DP[SS]=W[i]; Continue; } Dp[ss]= Max (Dp[ss], Dp[s] + (_num +1) *W[i]);