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An array of integers and the largest contiguous subarray, for example: [1, 2,-4, 4, 10,-3, 4,-5, 1] The largest contiguous subarray is [4, 10,-3, 4] (to be stated and programmed)

$arr= [1, 2,-4, 4, 10,-23, 4,-5, 1]; $max _sum= 0; $sum=0; $new= []; $i= 1; Echo' ; foreach($arr as $key=$value ){ if($sum){ unset($new[$i]); $i++; $sum=$value; }Else{ $sum+=$value; } $new[$i][] =$valu

C language computing 1/1-1/2 + 1/3-1/4 + 1/5-... + 1/99-1/100

C language computing 1/1-1/2 + 1/3-1/4 + 1/5-... + 1/99-1/100Calculate

Implemented in C: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value.

To get this topic, we will first think of using loops to complete.But not every operator is a "+" sign.Therefore, we are here to use (-1) of the I-side to do "+" "-" number control.The loop variable i is then treated as the denominator.Here we have the idea of the loop body is basically OK.It is important to note that the calculation results here are expressed in decimals, so it is not possible to define variables with int integers.The code is as foll

The "C language" calculates the value of 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100.

Note: When calculating 1 to use a double type that is 1.0 . Odd even numbers are calculated separately and then merged. #include Label control +1,-1 with flag. #include Use the Function Pow Pow ( -1,i+1) equivalent ( -

Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

#include Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

Use the for and while loops to calculate the value of e [e = 1 + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! +... + 1/n!], While

Use the for and while loops to calculate the value of e [e = 1 + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! +... +

C language: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value

#include Be careful to define its type, divide it into two parts, and define it as "I" to see if the denominator is an odd or even number, and the sum is summed. C language: Calculate 1/1-1/2+1/3-1/4+

Formula for calculating pi pai: Pai = 4* (1-1/3+1/5-1/7 ...)

There are many formulas for calculating pi pai in history, in which Gregory and Leibniz found the following formula: Pai = 4* (1-1/3+1/5-1/7 ...) The formula is simple and graceful, but in a bad way, it converges too slowly. If we rounded to keep its two decimal digits,

Compile a function. When n is an even number, call the function to calculate 1/2 + 1/4 +... + 1/n. When n is an odd number, call the function 1/1 + 1/3 +... + 1/n ., Even number

Compile a function. When n is an even number, call the function to calculate 1/2 + 1/4 +... + 1/n. When n is an odd number, call the function 1/1 + 1/3 +... +

C language: calculate the value of Polynomial 1-1/2 + 1/3-1/4 +... + 1/99-1/100, three types of cyclic implementation

C language: calculate the value of Polynomial 1-1/2 + 1/3-1/4 +... + 1/99-1/100, three types of cyclic implementation Method 1: for Loop Im

Question 8: f = 1! -1/2! + 1/3! -1/4! +... + 1/n! (N is a large number. If n is too large, it will overflow)

/*************************************** ************************Accumulated (C language)AUTHOR: liuyongshuiDATE :************************************************ ***********************//*Question 8: f = 1! -1/2! + 1/3! -1/4! +... + 1

2018-1-4 4 weeks 3 lessons VIM 2

numbers: ↑ Last used command: Nohl highlighted words, not highlighting hints: x save exit, change file is similar to Wq; File Open is not operational, change mtime: 1,100s/dnsmasq/aminglinux/g from line 1th to line 100, s means start substitution, replace DNSMASQ with aminglinux,g to replace all1, $s/\/etc\/hosts\//aminglinux/g replace/etc/hosts/with Aminglinux, escape with \ or 1, $s #/etc/hosts/#aminglinux/g or @ symbol delimitedSet NU Display line

Read "c ++ primer" thin (4-1 c and c ++ arrays), "cprimer" 4-1

Read "c ++ primer" thin (4-1 c and c ++ arrays), "cprimer" 4-1 Supervise reading, summarize the essence, extract notes, and inspire others. If you have any questions, leave a message to correct them. Arrays and pointers of c and c ++ belong to low-level Composite data types, such as arrays of c ++, similar to vector co

Java divides the memory into 4 parts 1. Code area 1, Stack area 3, heap 4, static zone

1, the stack area (stacksegment)-Automatically allocated by the compiler release, stored function parameters value, local variable value, etc., the system automatically releases the JVM memory resources after the execution of the method is completed.2. Heap area (heapsegment)-typically released by programmers, storing objects and arrays created by new, the JVM does not periodically view this object, and if no reference points to the object, it is recy

MOOC-android engineers-1-4 exercises, Android-1-4

MOOC-android engineers-1-4 exercises, Android-1-4 Source http://www.imooc.com/ceping/1474 Run a Java program Test. class on the console. Which of the following statements is true () AJava Test. class BJavac Test. class CJava Test DJavac Test Answer: CKnow

"C language" with Π/41-1/3 + 1/5-1/7 + ... The formula finds the approximate value of π until the absolute value of an item is found to be less than 10^6.

With Π/41-1/3 + 1/5-1/7 + ... The formula finds the approximate value of π until the absolute value of an item is found to be less than 10^6. #include "C language" with Π/41-

"C language" with Π/41-1/3 + 1/5-1/7 + ... The formula asks for the approximate value of π until the absolute value of an item is found to be less than 10^6. __c language

With Π/41-1/3 + 1/5-1/7 + ... The formula asks for the approximate value of π until the absolute value of an item is found to be less than 10^6. #include

Common regular expressions-supplement the regular expression of 1 phone number (mobile phone number, 3-4 area code, 7-8 live video number, 1-4 extension code)

Regular Expression of phone number (mobile phone number, 3-4 area code, 7-8 live video number, 1-4 extension code) (\ D {11}) | ^ (\ d {7, 8}) | (\ d {4} | \ d {3})-(\ d {7, 8 }) | (\ d {4} | \ d {3})-(\ d {7, 8 }) -(\ d {4} | \ d

JavaScript DOM Programming Art (2nd edition) Study Note 1 (chapter 1~4)

=document.getelementbyid (' id name '); Returns the element node, where each element node is an object, so the data type returned is an objectThe tag and class methods can iterate through a set of elements with a for loop4, gets and sets the element's attributes , which belong to the element node objectGets the property name of the attribute getattribute, a parameter that needs to be obtained.Set the property SetAttribute, two parameters, need to modify the property name, the modified value.Note

4 threads were designed, of which two threads increased by 1 for J each time, while the other two threads reduced by 1 for J at a time. Write the program.

public class ThreadTest {private int J;+1Private synchronized void Add () {j + +;System.out.println (Thread.CurrentThread (). GetName () + "add:" +j);}-1Private synchronized void sub () {j--;System.out.println (Thread.CurrentThread (). GetName () + "sub:" +j);}Add threadClass Add implements runnable{public void Run () {for (int i=0;iAdd ();}}}Subtract threadsClass Sub implements runnable{public void Run () {for (int i=0;iSub ();}}}public static void Main (string[] args) {ThreadTest threadtest=ne

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