sketchup exercises

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The implementation of Shell grammar exercises simple Calculator

Tag:expression calculator calculator #!/bin/bash# by inputting data calculating results expression= '; calculator () {echo "Please enter a number:"; readx;echo "Please enter another number:"; ready ;echo "Please enter operation symbol:"; readsymbol;case $symbol in+) ret= ' expr $x + $y '; expression= "$x + $y"; ;; -) ret= ' expr $x - $y '; expression= "$x-$y"; ;; \*) ret= ' expr $x \* $y '; expression= "$x * $y"; ;; /) ret= ' expr $x / $y '; expression = "$x/$y";;; %) ret= ' expr $x %

LINUX Redhat 第5-6 Unit Exercises

to create files in/sc directory and/CW directory, but cannot delete files.650) this.width=650; "Src=" https://s5.51cto.com/wyfs02/M01/8F/9B/wKiom1jmSgSw4RpgAAK0RV03P-E807.png-wh_500x0-wm_ 3-wmp_4-s_2570044280.png "title=" screenshot from 2017-04-06 22-00-18.png "alt=" Wkiom1jmsgsw4rpgaak0rv03p-e807.png-wh_50 "/>4. Set normal user new file permission to "r--r-----"650) this.width=650; "Src=" https://s1.51cto.com/wyfs02/M02/8F/9E/wKioL1jnFl2AkhrzAAWARkZUkBA690.png-wh_500x0-wm_ 3-wmp_4-s_370629021

LINUX Redhat First unit exercises

/gravity/ Southeast "/>8. Use a shortcut to invoke the 4th command that has been executed in the shell! Number: How many lines of command to execute! Letter: Executes the most recent one that starts with this letter9. Use a shortcut to execute the most recent command with the "date" keywordEnter Command!date650) this.width=650; "Src=" http://img.blog.csdn.net/20170329180727249?watermark/2/text/ ahr0cdovl2jsb2cuy3nkbi5uzxqvc29saxr1zgvftq==/font/5a6l5l2t/fontsize/400/fill/i0jbqkfcma==/dissolve/70/

command usage and some small exercises for Linux files

: Valid for all usersNormal User:. BASHRC: Valid only for yourself6. Display all files or directories in the/var directory that start with L, end with a lowercase letter, and have at least one digit (can have other characters) appear in the middlels/var/l*[[:d Igit:]]*[[:lower:]]7. Displays files or directories that start with any number and end with a non-number in the/etc directory# ls-ld/etc/[0-9]*[^[:d igit:]]8, display in/etc directory, start with a non-letter, followed by a letter and any

Shell scripting Exercises (12.11)

("/e/u261/lang/zh-cn/ Images/localimage.png ") no-repeat center;border:1px solid #ddd;" alt= "Spacer.gif"/>Method Two: seq is a fixed notationIdea: 1. First define a variable i2. Let the value of sum first start with the value of 0,i from 1 to 1001.3. Let I equals a number to remove to 2 if equal to 0, is the number we want to let them add together can get the sum neededVim sum2.sh#/bin/bash#written by Lizheng#about sumLet sum=0For I in $ (seq 1 100); DoIf [$[$i%2] = = 0]; ThenLet sum+= $iFiDon

Learning linux-Basic Five (Rights management exercises)

]$ exitexit[[email protected] ~]# groupmems-l-G VLAN Vlan1    Second, the new files created in the/testdir/data automatically belong to the G1 Group, group G2 members such as: Alice can have read and write permissions to these new files, group G3 members such as: Alice can have read and write access to these new files, group G3 members such as: Tom can only have read access to the new file, Other users (not part of G1,G2,G3) cannot access this folder.[[email protected] testdir]# mkdir-p/da

"Learn Linux with Amin" chapter 10th Shell Basics: After-school exercises and answers

execution fails, the following command is ignored. || : If one command executes successfully in multiple commands, the following command is ignored, otherwise the following command is run. 16. What if you just want to let a user use a variable?VIM/HOME/USERNAME/.BASHRC add a line of export abc=123 and then SOURCE/HOME/USERNAME/.BASHRC17. Which command will be used to list all the variables in the system and the current user defined custom variables?SetThis article is from the "fragrant

Regular Expressions and grep exercises (Linux)

1, in the current system create user student Student1 Student2, find the current system named student (must appear at the beginning) of the user's account and related information, the file is/etc/passwdgrep "^student\>"/etc/passwd | Cut-d:-F32, analyze the following text in the/etc/inittab file the characteristics of the first two lines (where the number must be the same in each line), write a pattern that can be found exactly like two lines:11:1:WAIT:ETC/RC.D/RC 113:3:WAIT:ETC/RC.D/RC 3grep "^1

0913&0915 Exercises: Shell Scripts, Sed&awk

number of files in two files and their total number of rows;650) this.width=650; "src=" http://s3.51cto.com/wyfs02/M01/73/95/wKioL1YBnRHSiaStAAGLfT_VfkQ251.jpg "/>Run the script test:650) this.width=650; "src=" http://s3.51cto.com/wyfs02/M02/73/98/wKiom1YBnRGiv43lAAGgZ-kn_IQ195.jpg "/>Exercise 5:Write a script(1) Prompt user to enter a string(2) Judgment:If quit is entered, exit the scriptOtherwise, the string content of its input is displayed650) this.width=650; "src=" http://s3.51cto.com/wyfs

Linux Learning: Vim exercises

1. Copy the/etc/grub.conf configuration file to the/tmp directory and use the Find replacement command to delete the white space character at the beginning of the/etc/grub.conf file 12 [[email protected] tmp] # cp-sv/etc/grub.conf."/etc/grub.conf" - "./grub.conf" 1 :%s/^[[:space:]]//g 2. Copy the/etc/rc.d/init.d/functions file to the/tmp directory and add a # to the beginning of the line beginning with a white-space ch

Shell program Exercises

#!/bin/sh notifications are explained by bash. If you execute the shell command date in the Echo statement, you need to precede the date command with the symbol ;You cannot execute the file immediately after editing the file, and you need to set executable permissions for the file. chmod +x DateAnother way to do date is to pass it as a parameter to the shell command:Method 3In order to compile and execute the shell program in any directory, we can add the directory where the program is located t

2017-2018-2 20172315 "Java Programming" course pair programming Exercises _ arithmetic

Analysis Demand analysis (including learning new technologies) 300 360 Coding Standard Code specification (to develop appropriate specifications for current development) 30 15 Design UML Design Project UML class diagram 60 120 Coding Specific code 2000 2400 Code Review Code review 30 40 Test Test (

2017-2018-2 20172302 "Java Programming" course pair programming Exercises _ arithmetic

Standard Code specification (to develop appropriate specifications for current development) 60 Design UML Design Project UML class diagram 60 Coding Specific code 1500 Code Review Code review 30 Test tests (Self-test, modify code, commit changes) 300 Size Measurement calculation effort (actual time) 2 2 Postmortem Process Improvement Plan Summariz

8 Queen-----Backtracking C + + programming exercises

/* * Eight queens Problem backtracking programming exercise * on the 8x8 chessboard, place 8 queens, two Queens cannot 22 attack * Also, straight line, vertical 45 degrees, 135 degrees direction cannot appear two queens * Copyright Michael 2014-12-19 * QQ 119206 5414 **/#include 8 Queen-----Backtracking C + + programming exercises

Algorithm analysis Exercises (1)

12.11. The qualitative factor is in number theory, the mass factor of a positive integer refers to the integer of prime numbers that can be divisible by the numbers.Two positive integers without a common mass factor are called coprime. The factorization of positive integers gives a series of qualitative factors, after all the mass factors are multiplied. Qualitative factors such as repetition will be expressed as an exponent. According to fundamental theorem of arithmetic, any positive integer h

Daily Go Language Bible--complex number, Boolean, string exercises

string s: = Fmt. Sprintf ("%.2f", str)//Remove the decimal part after the var end string if dot: = Strings. LastIndex (S, "."); Dot >= 0 {end = S[dot:] s = s[:d ot]} num: = Len (s) var buf bytes.b Uffer J: = 1 for i:=num-1;i>=0;i--{buf. WriteByte (S[i]) if j%3==0 i!=0{buf. WriteString (",")} J + +} res:=buf. String () var r bytes. Buffer//Invert string for I:=len (res) -1;i>=0;i--{R.writebyte (Res[i])} R.writestri Ng (end) return r.string ()}//Exercise 3.12: Write a function that determines wh

Recursive exercises of integers A through B and (c/C + +)

/********************************************************************************* Copyright (C), 1988-1999, Drvivermonkey. Co., Ltd. File Name: author:driver Monkey Version: mail:[email protected] qq:196568501 date:2014.04.02 Description: recursive exercises of a to B integers and **************************************************************************** / #include Integer and (c + +) of A to B of the recursive exercise

C Language Exercises-1

100 within the odd andOdd number of numbersEven andNumber of even numbers#include int main (){int i;int sum=0;int sum1=0;int sum2=0;for (i=1;i{Sum=sum+i;}int cnt=0;for (i=1;i{if (i%2==1)cnt++;}printf ("Number of odd numbers within 100 =%d\n", CNT);printf ("100 odd Cycles in number =%d\n", i);printf ("Odd and =%d\n\n\n\n within 100", sum);printf ("100 odd and Average =%d", sum3/cnt3);for (i=2;iSum1=sum1+i;printf ("Even-numbered cycles =%d\n", i);printf ("sum1=%d\n", sum1);return 0;} C language

python--Exercises--list sort Sort,sorted,reverse=true,reverse

L=[]For I in range (3):X=int (Input ("Shuru:"))L.append (x)Print (L)Print (sorted (l))Print (sorted (l,reverse=true)L.sort ()Print (L)L.reverse ()Print (L) #!/usr/bin/python3L=[]For I in range (5):X=int (Input ("Shuru:"))L.append (x)Print ("Chushi Xulie", L)Print ("Linshi Xulie Print ("Linshi daoxu >", Sorted (l,reverse=true))L.sort ()Print ("You Xiaodao da", L)L.sort (Reverse=true)Print ("Youda Daoxiao", L)L.reverse ()Print ("Dao Xu Xian Shi", l)python--E

Tree structure exercises--sequential traversal of ordered binary tree (binary search tree)

=key; P->lchild =NULL; P->rchild =NULL; T=p; } Else { if(Key data) T->lchild = Insert (t->lchild, key); ElseT->rchild = Insert (t->rchild, key); } returnt;}voidInorder (Tree *6) { if(t!=NULL) {inorder (t-lchild); CNT++; if(cnt==N) printf ("%d\n", t->data); Elseprintf ("%d", t->data); Inorder (t-rchild); }}intMain () { while(~SCANF ("%d", N)) {Tree* t =NULL; CNT=0; for(i=0; i) {scanf ("%d", key); T=Insert (t, key); } inorder (t); } return 0;}Tree structure

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