slack hipaa

],slack[n];intN,ans,nx,ny;CharE[n][m];voidGetmap ()//Building Map{ inti,j,x,y,count,l; for(x =1; x ) { for(y =1; Y ) { if(x = =y) w[x][y]=0; Else{L= strlen (e[x]+1); Count=0; for(i = L,j =1; i >0e[y][j]!=' /'; I--, J + +) { if(E[x][i] = =E[y][j]) Count++; Else Break; } W[x][y]=count; } } } return; }intDfsintX//find an augmented path{ inty,tmp; V

One or Unvisited[neighbour] > newdistance: #如果两个点之间的距离之前是无穷大或者新距离小于原来的距离 unvisited[neighbour] = newdistance# Update distance Visited[current] = currentdistance# This point has been slack, record del unvisited[current] #从未访问过的字典中将这个点删除 if not unvisited:b reak# if all the points are slack, jump out of this cycle Candidates = [node for node in Unvisited.items () if NODE[1]] #找出目前还有拿些点未松弛过 Current, currentd

Contest (6)--host by BIT problem solving: Just like the cyclic tour in front of you.1#include 2 using namespacestd;3 Const intMAXN =310;4 Const intINF =0x3f3f3f3f;5 intW[MAXN][MAXN],LX[MAXN],LY[MAXN],SLACK[MAXN];6 intN,LINK[MAXN];7 BOOLS[MAXN],T[MAXN];8 BOOLMatchintu) {9S[u] =true;Ten for(intv =1; V v) { One if(T[v])Continue; A intD = lx[u] + ly[v]-W[u][v]; - if(!d) { -T[V] =true; the if(Link[v] = =-1||match (

HDU_3435 This is a perfect match for minimum weights. When I use the KM algorithm to create an adjacent table, I need to initialize the edge weight to MAX-w [e]. then, find the perfect match of the maximum right and convert the result back. Because it is an undirected graph, we need to create two directed edges for each undirected edge. #include#include#define MAXD 1010#define MAXM 20010#define MAX 10001#define INF 1000000000int first[MAXD], next[MAXM], v[MAXM], w[MAXM], N, M;int yM[MAXD], wM[

(Fabs (GAP) //If you meet the requirements, pay attention to floating point ah. Vis_boy[boy] =true; if(Match[boy] = =-1|| DFS (Match[boy])) {//find a guy who doesn't have a match, or the boy's sister can find someone else .Match[boy] =girl; return true; } } Else{Slack[boy]= Min (Slack[boy], GAP);//slack can be understood as the boy who wants to get a girl'

of their income. (Villagers who have the money to buy a house but not necessarily can buy it depends on what the village leader assigns).Input data contains multiple sets of test cases, the first row of each set of data input n, indicating the number of houses (also the number of people home), followed by n rows, the number of n per row represents the price of the room of the second village name (nOutput make the maximum revenue value for each set of data, one row for each set of outputs.Sample

changes to user permissions and user group accounts; and vigilant monitoring of servers, check for suspicious file activity. Whether unauthorized users attempt to access personal files or get bored with their work to download MP3 files, the real security policy management tool will notify the corresponding administrator and automatically take the scheduled action. With this real-time tracking, notification, and repair function, the dangers of Internal Security damages can be easily controlled a

scenarios, the product now has three versions: Enterprise Edition, Standard Edition, branch architecture edition and Development edition. Biztalk Server 2006 R2 Enterprise Edition, Standard Edition and branch edition are licensed based on each processor. Each processor installed with any BizTalk Server components (such as the BizTalk Server rule engine) requires a license. However, some tools and components can be installed on a separate machine without a processor license. For more information

called Direct. Unlike the Connect,direct design, it is a peer-to-peer structure. Medical providers who are accustomed to sending messages back and forth are familiar with the open, Peer-to-peer data exchange model of direct, so direct is more likely to be used. e-mail security and medical IT Patient data stored in the medical IT system must comply with strict privacy and security regulations, such as the health Insurance Circulation and Accountability Act (

In order to bring better security and control to network services, the United States Louisiana decided to replace the existing wide area network (WAN), and the use of Ethernet switches (provided by Enterasys Network Company)-driven dedicated fiber ring network, At the same time for the deployment of mobile office staff need 802.11n wireless mesh network is ready. "The network upgrades are partly due to the government's regulations, including the Health Insurance Portability and Accountability A

Original link: http://www.cnblogs.com/Jason-Damon/archive/2012/04/21/2460850.htmlExcerpt from Baidu EncyclopediaThe Bellman-ford algorithm is a single-source shortest path algorithm with negative weights, which is very inefficient, but the code is easy to write. That is, the continuous relaxation (relaxation), each slack to update each edge, if the n-1 can be updated after the relaxation, then the picture has a negative ring (that is, the negative pow

after the task is executed. This command receives an API token, the name of the room, and the user name of the sender displayed in the message: @servers(['web' => '192.168.1.1'])@task('foo', ['on' => 'web']) ls -al@endtask@after @hipchat('token', 'room', 'Envoy')@endafter If necessary, you can also send custom messages to the HipChat room. When building a message, the available variables of the task are also available in the message: @after @hipchat('token', 'room', 'Envoy', "$task ran in

staggered road X4, Y2, X3, Y0 X1, not found? there is a X4---------Y2, X3, X0--Y1-X2 The inverse of the path attribute becomes the upper (right) graph. At this point, all the vertices in set X already have corresponding matching, that is, complete matching! That is, the maximum weight of this binary graph match! X0-Y1X1-Y0X2-Y4X3-Y3X4-Y2Maximum power value is 30What about the minimum weight matching requirement? Very simple, before solving the ownership value of the opposite number, the results

Test instructions: N students arranged to M dormitory, each student to the dormitory has a rating, positive, 0, negative, now the evaluation is negative, can not let this student go to this room, ask how to arrange to let all the students live in the dormitory and the most evaluation.Idea: When building the weight of a graph, filter out negative edges.#include #include #include #include #include #include #include #include #include #include #include #include #define Lson (rt#define Rson (rt#defin

KM algorithm binary graph maximum weighted value matching#include #include#include#includeConst intMAXN =356;Const intINF = (1 to)-1;intW[MAXN][MAXN];intLX[MAXN],LY[MAXN];intLINKY[MAXN];intVISX[MAXN],VISY[MAXN];intSLACK[MAXN];intNx,ny;BOOLFindintx) {Visx[x]=true; for(inty =0; Y ) { if(Visy[y])Continue; intt = lx[x] + ly[y]-W[x][y]; if(t==0) {Visy[y]=true; if(linky[y]==-1||find (Linky[y])) {Linky[y]=x; return true; } } Else if(Slack