slack valuation

Download fromHttp://www.newxing.com/Code/VC/game/1750.htmlThe operating interface is as follows;Look at the class diagram;ResourcesMain dialog box;Source Code Description:I machine chess program using a variety of search algorithms. The following are the main class descriptions for this program:Category 1.CEveluation: Valuation class, valuation of a given board.2.CMoveGenerator class: Go to the method gener

What is the asset net worth of a unit fund? How are the number and redemption amount of the subscribed fund units calculated based on the unit's net asset value? The net asset value of a fund refers to the balance after the total market value of the Fund assets calculated at the fair price is deducted from the debt at the time of a fund valuation. The balance is the equity of the Fund Holder. The process of calculating fund assets at fair price

Question 1: Use the status space to indicateA *SearchAlgorithmSolve the following problems:U2Choir in17They have to arrive at the concert venue within minutes, and they have to cross a bridge on the way. Four people start from the same end of the bridge. You have to help them reach the other end. The sky is dark, they only have one flashlight. At the same time, a maximum of two people can bridge the bridge together, while a flashlight must be held when crossing the bridge, so someone has to brin

(such as. com.cn if allowed to transfer) Domain Name Valuation: Based on the above several aspects, we can make a general assessment of the value of the domain name. See below Table: For. com Domain names: Domain Price Index Price length a length b length c length d length E Meaning a 50-1000 30-500 5-100 1-25 0-5 Meaning b 20-500 5-100 3-50 0.5-5 0-2 Meaning C 1-15 0.5-10 0.3-7.5 0.1-4 0-1.5 Meaning d 0.5-5 0.3-2.5 0.3-2.5 0.1-2 0-1.5 Meaning e 0-2

the c [I]-C [J] edge. If the points on both sides are different, the points on both sides are equal, and then the sides are completed, the weight of the completed edge is regarded as 0, after completing the km operation, you can calculate the values of d [I] And d [J] based on the values of a [I] and B [J. When creating a graph, if C [I]-C [J] # Include # Include String . H> # Include # Define Maxn 70 # Define Maxd 410 # Define Maxm 810 # Define INF 0x3f3f3f Int N, m, D, first [maxn], E, n

the KM algorithm can be O (N3. Each y vertex is given a "relaxation amount" function slack, Which is initialized to an infinite number every time the augmented path is searched. When you check the edge (I, j) in the process of searching for the augmented path, if itNot equal subgraph, The slack [J] is changed to a smaller value of the original value and a [I] + B [J]-W [I, j. In this way, allY vertex not i

data contains multiple sets of test cases, the first line of each set of data entered N, indicating the number of houses (also the number of people in the home), followed by n rows, the number of n per row represents the first village name of the room price (nOutputPlease output the maximum revenue value for each set of data, one row for each group of outputs.Sample Input2 100 10) 15 23Sample Output123 template questions, organize the template/************************************************aut

the village leader assigns).Test Instructions Description: Because this is titled Chinese title, this is not translated here. algorithm Analysis: maximum weight matching problem,km algorithm for the entry question. Baidu km algorithm has a lot of relevant introduction, here no longer described. Explanation Point, km optimization: The slack array saves the value min (Lx[x]-ly[y]-w[x][y]) of each y in the Y-set (binary graph: X-Set and Y-set) that is n

KM algorithm1#include 2 #defineN 15003 #defineINF 9999999994 using namespacestd;5 inta[n],bs[n],nx=0, ny=0, K;6 intLinky[n],lx[n],ly[n],slack[n];7 intVisx[n],visy[n],w[n][n];8 intMinintAintb) {return(aa:b;}9 intFindintx) {Tenvisx[x]=1; One for(inty=1; y){ A if(Visy[y])Continue; - intt=lx[x]+ly[y]-W[x][y]; - if(t==0) {visy[y]=1; the if(linky[y]==-1||find (Linky[y])) { -Linky[y]=x;return 1; - } -

metVis_boy[boy] =true; if(Match[boy] = =-1|| DFS (Match[boy])) {//find a guy who doesn't have a match, or the boy's sister can find someone else .Match[boy] =girl; return true; } } Else{Slack[boy]= Min (Slack[boy], GAP);//slack can be understood as the boy who wants to get a girl's heart. How much will it take to have a minimum spare tire appearance "cove

intMAXN = the;Const intINF =0x3f3f3f3f;intLOVE[MAXN][MAXN];//record the goodwill of every sister and every boyintEX_GIRL[MAXN];//the expectations of every sisterintEX_BOY[MAXN];//the expectations of every boyBOOLVIS_GIRL[MAXN];//record every match of the match GirlBOOLVIS_BOY[MAXN];//keep track of each match, match the boys.intMATCH[MAXN];//record each boy's match to the sister, if not, 1.intSLACK[MAXN];//keep track of the number of expectations that every man needs at least if he can be attrac

],slack[n];intN,ans,nx,ny;CharE[n][m];voidGetmap ()//Building Map{ inti,j,x,y,count,l; for(x =1; x ) { for(y =1; Y ) { if(x = =y) w[x][y]=0; Else{L= strlen (e[x]+1); Count=0; for(i = L,j =1; i >0e[y][j]!=' /'; I--, J + +) { if(E[x][i] = =E[y][j]) Count++; Else Break; } W[x][y]=count; } } } return; }intDfsintX//find an augmented path{ inty,tmp; V

One or Unvisited[neighbour] > newdistance: #如果两个点之间的距离之前是无穷大或者新距离小于原来的距离 unvisited[neighbour] = newdistance# Update distance Visited[current] = currentdistance# This point has been slack, record del unvisited[current] #从未访问过的字典中将这个点删除 if not unvisited:b reak# if all the points are slack, jump out of this cycle Candidates = [node for node in Unvisited.items () if NODE[1]] #找出目前还有拿些点未松弛过 Current, currentd

Contest (6)--host by BIT problem solving: Just like the cyclic tour in front of you.1#include 2 using namespacestd;3 Const intMAXN =310;4 Const intINF =0x3f3f3f3f;5 intW[MAXN][MAXN],LX[MAXN],LY[MAXN],SLACK[MAXN];6 intN,LINK[MAXN];7 BOOLS[MAXN],T[MAXN];8 BOOLMatchintu) {9S[u] =true;Ten for(intv =1; V v) { One if(T[v])Continue; A intD = lx[u] + ly[v]-W[u][v]; - if(!d) { -T[V] =true; the if(Link[v] = =-1||match (

HDU_3435 This is a perfect match for minimum weights. When I use the KM algorithm to create an adjacent table, I need to initialize the edge weight to MAX-w [e]. then, find the perfect match of the maximum right and convert the result back. Because it is an undirected graph, we need to create two directed edges for each undirected edge. #include#include#define MAXD 1010#define MAXM 20010#define MAX 10001#define INF 1000000000int first[MAXD], next[MAXM], v[MAXM], w[MAXM], N, M;int yM[MAXD], wM[

(Fabs (GAP) //If you meet the requirements, pay attention to floating point ah. Vis_boy[boy] =true; if(Match[boy] = =-1|| DFS (Match[boy])) {//find a guy who doesn't have a match, or the boy's sister can find someone else .Match[boy] =girl; return true; } } Else{Slack[boy]= Min (Slack[boy], GAP);//slack can be understood as the boy who wants to get a girl'

of their income. (Villagers who have the money to buy a house but not necessarily can buy it depends on what the village leader assigns).Input data contains multiple sets of test cases, the first row of each set of data input n, indicating the number of houses (also the number of people home), followed by n rows, the number of n per row represents the price of the room of the second village name (nOutput make the maximum revenue value for each set of data, one row for each set of outputs.Sample

(Google)N a buyer (advertiser)K something (AD bit)Buyer: BidSeller: Allocate resources to the buyer, and want the buyer to charge the fee (the method of collecting the fee has the specific auction method to decide)Auctions can be divided into single item auctions and multiple item auctions, first from individual item auctions. Single Item auctions have public auctions and sealed auctions.In a public auction there are usually two methods of auction: One is the price of the auction, the auction s

order.IdeasThe sequence of the transform is [i,j], which is inserted into the rear position of K.As a result of nCode #include UVA11882 Test InstructionsGive you a map, the map includes the 1~9 and the # characters, #是不能进入的, you can appear from any one can go, and constantly move to the surrounding four lattice, but can not walk the repeated path, each to a removable lattice, the value of the transformation is the rule is the new lattice in the number of the current value of the back one, na

Original link: http://www.cnblogs.com/Jason-Damon/archive/2012/04/21/2460850.htmlExcerpt from Baidu EncyclopediaThe Bellman-ford algorithm is a single-source shortest path algorithm with negative weights, which is very inefficient, but the code is easy to write. That is, the continuous relaxation (relaxation), each slack to update each edge, if the n-1 can be updated after the relaxation, then the picture has a negative ring (that is, the negative pow