sledgehammer exercise

Exercise 3-67 OriginalExercise 3.67. Modify The pairs procedure so (pairs integers integers) would produce the stream of all pairs of integers (i,j) (Witho UT the condition i Code(Define (all-pairs s T) (Cons-stream (list (stream-car s) (stream-car T)) (Interleave (interleave(stream-map (Lambda (x) ( list ( stream-car s) x ) ( stream-cdr t))( All-pairs (stream-cdr s) (stream-cdr t )))

Exercise 3-68 OriginalExercise 3.68. Louis Reasoner thinks that building a stream of the pairs from three parts is unnecessarily complicated. Instead of separating the pair (s0,t0) from the rest of the pairs on the first row, he proposes to work with the whole FIR St row, as follows: (define (pairs s t ) (interleave ( Stream-map (lambda (x ) (list (stream-car s) x) ) t ) (pairs (stream-cdr s) ( stream-cdr t ) ) ) ) Does

Exercise 3-69 OriginalCode(Define (triples s T u) (Cons-stream (list(stream-car s)(stream-car t)( Stream-car u)) (Interleave (stream-map (Lambda (x) ( cons (stream-car s) x))(stream-cdr (pairs t u) )) (triples (stream-cdr s)(stream-cdr t) (stream-cdr u)) ))); Value:triples(Define (phythagorean-numbers) (define (square x) (* x x)) (define numbers (triles integers integers integers)) (stream-filter

Exercise 3-70 OriginalCode(Define (merge-weighted S1 s2 weight) (Cond ((stream-null s1) S2) ((stream-null S2) s1) (Else ( Let ((cars1 (stream-car s1)) (cars2 (stream-car S2) )) (Cond ( ( weight cars1 ) ( weight cars2 ) ( cons-stream cars1 (merge-weighted (stream-cdr s1) s2 weight)) ) ((= (weight cars1) (weight cars2)) (cons-stream cars1 (merge-weighted (stream-cdr s1) s2 weight ))) (else (cons-stream cars2 (merge-weighted s1 (stream-c

Exercise 2.66This problem is equivalent to two fork tree in the actual project of one application, we still need to use the previous three processes learned: entry, Left-branch, Right-branch. The three functions are taking out the node, the left branch and the right branch. And according to the topic request, here also need a key that gets the value. Of course, as shown in the book above, key does not need to be written out, and here is a desire to th

Python exercise Questions 4-digit three-digit non-repetition, python exercise questions I heard that doing exercises is the best way to master a programming language, so I will try to have over 100 questions first. ---------------------------------------------------------------------- [Python exercise 001]There are 1, 2, 3, and 4 numbers. How many three number

Oracle Database exercise example and answer sharing, oracle exercise questions I. Create a table 1. create table empgj (empno number () primary key, ename varchar2 (10), 2.job varchar2 (9), mgr number (), hiredate date, sal number ), comm 3. number (7, 2), deptno number (2, 0); 4. -- 1 5. insert into empgj (empno, ename, job, mgr, hiredate, sal, comm, deptno) values 6. (7369, 'Smith ', 'cler', 7902, to_dat

Exercise 3-1 Score StatisticsEnter some student's score, which score appears the most times? If there are multiple parallel, from small to large output.Task 1: Non-negative integers with fractions not exceeding 100Task 2: The score does not exceed 100 of the nonnegative real number, but retains a maximum of two decimal places.Task 1#include Task 2#include Summary: Task 2 degree set to double, then to int, with floor (m+0.5), previously encountered, re

Exercise 15.8: Give definitions of static types and dynamic types.A: Static type: Is the type of the variable declaration, or the type generated by the expression, and the type is known at compile time .Dynamic type: Is the type of object in memory that is represented by a variable or expression and is not known until run time .Exercise 15.9: Under what circumstances can the static type of an expression be

Exercise 2.73A small problem, this is because the scheme of the number, the direct provision of variables, the former will be treated as a numeric type, the latter will be used as the symbol type. Therefore, it is not necessary to add these two predicates to the data-driven dispatch. If you add a flag to a numeric type or symbol type, it is not a waste of space or time to judge a known type in the get process.b, we have completed the problem according

Exercise 3-72 OriginalExercise 3.72. In a similar-to-exercise 3.71 generate a stream of all numbers so can be written as the sum of of the squares in three Different ways (showing how they can is so written).Code (define (square x) (* x x)) (define (sum-square x) (+ (square (car x) ) (square (cadr x) ))) (Define (squaresn s) (define (stream-cadr s) (stream-car (stream-cdr s)) ) (define

Exercise 3-82 OriginalExercise 3.82. Redo Exercise 3.5 on Monte Carlo integration in terms of streams. The stream version of Estimate-integral is not a argument telling how many trials to perform. Instead, it'll produce a stream of estimates based on successively more trials.Code (define ( Random-in-range Low High) (let ( (range ( - High low) ) ) (+ low (* (random ) range) ) ) ) (def

Python uses a for while loop to print the Yang Hui triangle exercise (list index exercise).Yang Hui Triangle is a number of triangular tables, the general form is as follows:11 11 2 11 3 3 11 4 6) 4 11 5 10 10 5 11 6 15 20 15 6 1.......................The most essential feature of the Yang Hui Triangle is that its two hypotenuse is made up of the number 1, while the remaining number equals the sum of two nu

Exercise 3-3 the last three bits of the productEnter several words, enter a number of integers (which can be positive, negative, or 0), and output the last three bits of their product. These integers are mixed with a string of uppercase letters, and your program should ignore them. Tip: Try to enter a string when executing scanf ("%d").#include Summary: 1 Note overflow2 for a break in the bad, the next code is to determine where the for-through-bad ex

HTML5 basics Exercise 1. HTML5 basics exercise 1. What is the HTML version before HTML5? A:In HTML 4.01 2. Is doctype correct for HTML5? A: 3. In HTML5, Which element is used to combine the title element? A: 4. Is HTML5 supported?Element? A:No 5. Is HTML5 supported?Element? Answer: No 6. In HTML5, onblur and onfocus are: A:Event attributes 7. The correct HTML5 elements used to play HTML5 video files a

Razor Exercise 2, razor exercise Razor data types include string, int, float, decimal, and bool.In addition, data type conversion is required. The common methods are as follows:ToString (): converts the data type to string ). This is the same as the C # syntax.IsBool () and AsBool () convert strings to Boolean values ).IsFloat () and AsFloat () convert strings to floating-point ).IsInt () and AsInt () conv

Razor Exercise 3, razor exercise In Razor syntax, it uses three types of material loop processing: for, while, and foreach. The following Insus. NET illustrates an example in the ASP. net mvc environment by appending the source code:While: Animation demonstration:

Label: style color for SP on BS amp AD Size6. set $ a, B \ In M_n $, $ A $ to a positive matrix, and $ B $ to a Hermite matrix. then $ \ Bex a + B \ mbox {positive definite when and only when} \ lm_j (a ^ {-1} B)>-1, \ quad j = 1, \ cdots, N. \ EEx $Proof: $ \ beex \ Bea \ quad A + B \ mbox {Zhengding }\\ \ LRA e + A ^ {-1/2} Ba ^ {-1/2} \ mbox {Zhengding }\\ \ LRA \ lm_j (a ^ {-1/2} Ba ^ {-1/2})> -1, \ quad \ forall \ j = 1, \ cdots, n \ \ LRA \ lm_j (a ^ {-1} B)>-1, \ quad j = 1, \ cdots, N,

$ \ Bex R =\frac {1} {\ SQRT {2 }}\ sex {\ BA {CC}-1 1 \ 1 1 \ EA} \ EEx $ make $ \ Bex R ^ t \ sex {\ BA {CC} s _ {2j-1} 0 \ 0 S _ {2j} \ EA} R = \ sex {\ BA {CC} B _j C_j \ C_j B _j \ EA }, \ quad 2b_j = S _ {2j-1} + S _ {2j}, \ quad 2c_j = S _ {2j}-S _ {2j-1 }. \ EEx $ so, $ \ beex \ Bea \ quad \ diag (R, \ cdots, R) ^ t \ diag (S_1, \ cdots, s_n) \ diag (R, \ cdots, R) \\\=\ diag \ sex {\ BA {CC} B _1 C_1 \ C_1 B _1 \ EA }, \ cdots, \ sex {\ BA {CC} B _k c_k \ c_k B _k \ EA }\\\=

Label: style color for SP on BS amp AD Size 3. Prove that the numerical radius $ W (\ cdot) $ is a norm on $ M_n $. Proof: (1 ). $ \ beex \ Bea W (a) \ geq 0; \ W (A) = 0 \ rA x ^ * AX = 0, \ quad \ forall \ x \ \ rA x ^ * Ay = \ frac {1} {4} \ sum _ {k = 0} ^ 3 I ^ k (x + I ^ KY) ^ * a (x + I ^ KY) = 0, \ quad \ forall \ X, Y \ \ rA ay = 0, \ quad \ forall \ Y \ \ rA a = 0. \ EEA \ eeex $(2 ). $ \ beex \ Bea \ quad | x ^ * (\ Al A) x | = | \ Al | \ cdot | x ^ * ax |, \ quad \ forall