sliding window maximum

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"Sword Point offer" the maximum value of the sliding window, C + + implementation

Original blog, reproduced please indicate the source! # topics # ideas Use a double-ended queue in C + + to hold a subscript that may be the maximum of a sliding window, where the first element of the team holds the subscript for the current window's maximum value. Updates the queue when the

Sliding Window Maximum

Given an array nums, there is a sliding window of size K which are moving from the very left of the array To the very right. You can only see the K numbers in the window. Each of the sliding window moves right by one position.For example,Given nums = [1,3,-1,-3,5,3,6,7] , an

[leetcode]239. Sliding window maximum slide max

Given an array nums, there is a sliding window of size K which are moving from the very left of the array To the very right. You can only see the K numbers in the window. Each of the sliding window moves right by one position. Return the max

239. Sliding Window Maximum

} One A @Override - Public intcompareTo (Pair p) { - return This. Key This. Key = = P.key? 0:-1);//reverse order, from Large to Small the } - } - - Public int[] Maxslidingwindow (int[] Nums,intk) { + if(Nums.length = = 0 | | k return New int[0]; - +PriorityqueueNewPriorityqueue(); A int[] ret =New int[Nums.length-k + 1]; at inti = 0; - - for(i = 0; i ) { -Que.add (NewPair (Nums[i], i

(heap) 239. Sliding Window Maximum

Topic:Given an array nums, there is a sliding window of size K which are moving from the very left of the array To the very right. You can only see the K numbers in the window. Each of the sliding window moves right by one position.For example,Given nums = [1,3,-1,-3,5,3,6,7

Leetcode 239 Sliding Window Maximum, leetcodesliding

Leetcode 239 Sliding Window Maximum, leetcodesliding1. Problem Description Given an integer array and a k-sized sliding window, the sliding window moves a number from left to right each

[Leetcode 239] Sliding Window Maximum

Given an array nums, there is a sliding window of size K which are moving from the very left of the array To the very right. You can only see the K numbers in the window. Each of the sliding window moves right by one position.for example,givennums =[1,3,-1,-3,5,3,6,7" , And

239. Sliding Window Maximum

Given an array nums, there isA sliding window of size K which isMoving fromThe very left of the array to the very right. You can only see the K numbersinchThe window. Each of the sliding window moves right by one position. For Example,given Nums= [1,3,-1,-3,5,3,6,7], and k =

Leetcode--sliding Window Maximum

TopicGiven an array nums, there is a sliding window of size k which are moving from the very left of the array to the very right . You can only see the K numbers in the window. Each of the sliding window moves right by one position.For example,Given nums = [1,3,-1,-3,5,3,6,7

239. Sliding Window Maximum

maximum number of the current window subscript. Each cycle, the number of deque less than nums[i] is excluded. Add the subscript of the right edge of the window to the deque, while rejecting the ordinal of the deque head crossing. When the number of traversed has reached the size of the window, the subscript of the nu

Leetcode--Sliding Window Maximum

Title Description:Given an array nums, there is a sliding window of size k which are moving from the very left of the array to the very right . You can only see the K numbers in the window. Each of the sliding window moves right by one position.For example,Given nums = [1,3,

Leetcode 239:sliding Window Maximum

windows with a linkedlist. If 3 appears, then 1 is not likely to be the maximum value. So you can remove 1. Then-1 appeared. You cannot remove 3 at this time. Because 3 can be the maximum value. That is, if the number of occurrences is larger than the number that appears first, the previous number can be deleted. When the index at the top of the list exceeds the window

Leetcode Sliding Window Maximum

The original title link is here: https://leetcode.com/problems/sliding-window-maximum/[1,3,-1,-3,5,3,6,7], and k = 3.With a deque, the index is stored inside. Before adding index from the tail, check deque's trailing index element Nums[ls.getlast ()] is smaller or equal than the element to be added nums[i], if so, remove the trailing index and remove it until it

leetcode@ [239]sliding Window Maximum

https://leetcode.com/problems/sliding-window-maximum/Given an array nums, there is a sliding window of size K which are moving from the very left of the array To the very right. You can only see the Knumbers in the window. Each of

[Leetcode] Sliding window Maximum Slide max

Given an array nums, there is a sliding window of size K which are moving from the very left of the array To the very right. You can only see the K numbers in the window. Each of the sliding window moves right by one position.For example,Given nums = [1,3,-1,-3,5,3,6,7] , an

Maximum value of sliding window

Title: Given an array and the size of the sliding window, find the maximum value in all the sliding windows. For example, if the input array {2,3,4,2,6,2,5,1} and the size of the sliding window 3, there are altogether 6

[Leetcode]239. Sliding Window Maximum

>result;5 inti =0;6 7 for(i =0; I 1; i++)8 {9 while(!idq.empty () (Idq.back () Nums[i]))Ten Idq.pop_back (); One Idq.push_back (Nums[i]); A } - - for(i = k-1; I ) the { - while(!idq.empty () (Idq.back () Nums[i])) - Idq.pop_back (); - Idq.push_back (Nums[i]); + - Result.push_back (Idq.front ()); + A if(Idq.front () = = Nums[i-k +1]) at Idq.pop_front (); - }

Leetcode-sliding Window Maximum

Public classSolution {2 Public int[] Maxslidingwindow (int[] Nums,intk) {3 if(k==0 | | nums.length==0 | | k>nums.length)return New int[K];4 5 int[] Windowmax =New int[Nums.length-k + 1];6 int[] Rightmax =New int[K];7 //initialization8 intindex = k-1;9 intWindex = 0;Ten intMindex = 0; One intLeftmax =Integer.min_value; A while(Index nums.length) { - //if reaches the end of current section. -

Array sliding window Compare maximum value

importjava.util.arraylist;importjava.util.arrays;importjava.util.deque;import java.util.list;importjava.util.concurrent.linkedblockingdeque;/*** has a xxx The array arr and a window of size w slide from the leftmost edge of the array to the far right, and the window slides one position at a time to the right. * returns an array of length n-w+1 res,res[i] represents the

Sliding Window Maximum

//Auxiliary queue that's sorted in descending order -linkedlistNewLinkedlist(); - for(inti =0; i ) { the //Enqueue. Remove those smaller values - intdata =A[i]; - while(!q.isempty () q.getlast () data) { - q.removelast (); + } - q.add (data); + if(I 1)Continue; A //dequeue. If The current number is the maximum. Also Remove it at //From the

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