spring boot microservices example java

Problems with SpringSpring boot features, no special place1.Spring FoundationPS: About Spring configurationPs:spring ecology2.Spring Common ConfigurationThe trend of PS:SPRING4 development is to annotate all the configurations, in fact, to inject the appropriate resourcesPs:scope is the scope of the beanPS: Do not writ

to prototype scope1 2 3 xmlns:xsi=" Http://www.w3.org/2001/XMLSchema-instance "4 xsi: schemalocation= "Http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/ Spring-beans.xsd ">56 class=" Com.example.spring.HelloWorld "scope=" Prototype">7 8 Run output:Your message:i ' m object a13:52:03.767 [main] DEBUG org.springframework.beans.factory.support.defaultlistablebeanfactory-creating instance of b

("/jquery.min.js"); Srb.addurlmappings ("/pobstyle.css"); Srb.addurlmappings ("/sealsetup.exe"); return SRB; // }5. Add the code that creates the Pageofficectrl object in the Showword method of Democontroller, where the first parameter of the Webopen method is the disk path on the server side of the Office file, and the constants are temporarily used in this demo: d:\\ Test.doc　　 @RequestMapping (value= "/word", method=requestmethod.get) public Modelandview

implemented using filter.1 @Configuration2 Public classbeanconfiguration {3 4 @Bean5 PublicCorsfilter Corsfilter () {6 FinalUrlbasedcorsconfigurationsource Urlbasedcorsconfigurationsource =NewUrlbasedcorsconfigurationsource ();7 FinalCorsconfiguration corsconfiguration =Newcorsconfiguration ();8Corsconfiguration.setallowcredentials (true);9Corsconfiguration.addallowedorigin ("*");TenCorsconfiguration.addallowedheader ("*"); OneCorsconfiguration.addallowedmethod ("*"); AUrl

characters that can be populated with spring filter packaging, such as when SH is named app.sh placed in the Src/main/bin directory of the MAVEN format project, the following configuration can be added to the Pom file, such as:truetrue/*It is convenient to throw the package on the server after it has been hit:" chmod +x/data/ops/app/liam-service/bin/app.sh " "/data/ops/app/liam-service/bin/app.sh backup""/data/ ops/app/liam-service/bin/app.sh stop""

Learn how to connect to the view layer by using idea to build spring boot in Java learning-11: Add Dependency package for view (Modify Pom.xml) Dependency > groupId >org.springframework.bootgroupId> Artifactid>spring-boot-starter-freemarkerar

Create a new project and add support for the databaseDownload MySQL Driver pack mysql-connector-java-5.1.7-bin.jar, shortcut key ctrl+alt+shift+s, add jar package to ProjectWriting Test Text Jdbctemplatedemo.java1 PackageCom.jdbc;2 3 Importorg.junit.Test;4 Importorg.springframework.jdbc.core.JdbcTemplate;5 ImportOrg.springframework.jdbc.datasource.DriverManagerDataSource;6 7 Public classJdbctemplatedemo {8 @Test9 Public voidAdd () {TenDriverman

,jasper.jar,jasper-el.jar,ecj-*.jar,tomcat-api.jar,tomcat-util.jar,tomcat-util-scan.jar, Tomcat-coyote.jar,tomcat-dbcp.jar,tomcat-jni.jar,tomcat-websocket.jar,tomcat-i18n-en.jar,tomcat-i18n-es.jar, Tomcat-i18n-fr.jar,tomcat-i18n-ja.jar,tomcat-juli-adapters.jar,catalina-jmx-remote.jar,catalina-ws.jar, Tomcat-jdbc.jar,tools.jar,commons-beanutils*.jar,commons-codec*.jar,commons-collections*.jar,commons-dbcp*.jar , Commons-digester*.jar,commons-fileupload*.jar,commons-httpclient*.jar,commons-io*.jar

/schema/beans/spring-beans.xsd ">5 6 BeanID= "Userdao"class= "Com.example.spring.UserDao">Bean>7 8 BeanID= "UserService"class= "Com.example.spring.UserService" >9 Propertyname= "Userdao"ref= "Userdao"> Property>Ten Bean> One Beans>Note the injected property is the ID of the Userdao class.Writing Application.java1 Packagecom.example.spring;2 3 ImportOrg.springframework.context.support.AbstractApplicationContext;4 ImportOrg.springf

Application.java Packagecom.example.spring;ImportOrg.springframework.context.support.AbstractApplicationContext;ImportOrg.springframework.context.support.ClassPathXmlApplicationContext; Public classApplication { Public Static voidMain (string[] args) {//Where the bean configuration file is located d:\\ideaprojects\\spring\\src\\beans.xml//using the Abstractapplicationcontext containerAbstractapplicationcontext context =NewClasspathxmlapplicationconte

Tag:jetty embedded jetty Package Com.doctor.embeddedjetty;import Java.util.concurrent.timeunit;import Org.eclipse.jetty.server.Server; Import Org.eclipse.jetty.servlet.servletcontexthandler;import Org.eclipse.jetty.servlet.servletholder;import Org.springframework.web.context.support.annotationconfigwebapplicationcontext;import Org.springframework.web.servlet.dispatcherservlet;public class Embeddedjettyserver {private int port;p Rivate class Test code:Package Com.doctor.embeddedjetty;import stat

PublicHomeController (Resourceloader resourceloader) { This. Resourceloader =Resourceloader; } @RequestMapping (Method= Requestmethod.get, value = "/{yyyy}-{mm}-{dd}/{filename:.+}") @ResponseBody PublicResponseentitygetFile (@PathVariable string yyyy, @PathVariable string MM, @PathVariable string dd, @PathVariable string filename) { Try { returnResponseentity.ok (Resourceloader.getresource ("File:" + paths.get ("d:/upload/" + yyyy+ "-" +mm+ "-" +DD + "/", filename). toString ()); } C

Believe that most of the students who use IntelliJ will encounter this problem, even if the project used Spring-boot-devtools, modified class or HTML, JS, and so on, idea or will not automatically restart, to make a manual or restart,There is no use for hot deployment. This is not your configuration problem, believe yourself, the hot deployment of the few settings is simple, the root cause is because Intell

Application.java1 Packagecom.example.spring;2 3 ImportOrg.springframework.context.support.AbstractApplicationContext;4 ImportOrg.springframework.context.support.ClassPathXmlApplicationContext;5 6 Public classApplication {7 Public Static voidMain (string[] args) {8 //Where the bean configuration file is located d:\\ideaprojects\\spring\\src\\beans.xml9 //using the Abstractapplicationcontext containerTenAbstractapplicationcontext

:@RequestMapping ("/json") @ResponseBody public list json () { return userservice.getallusernames ();}Spring's role here is to inject the userservice needed by HomeController, run the program, and access the Http://localhost:8080/demo4springmvc-spring/json:["Zhangsan", "Lisi", "Wangwu"]SOURCE downloadAnother feature of spring is that AOP is not needed, and so on when the log is required to write, of cou

accessed normally, HTTP ://localhost:8080/demo4ssh-security/admin but not accessible:Spring Security Basic configuration is this, compared to the previous several, Spring security such basic configuration is not much use, now who can still use the plaintext password, MD5 encryption in the way of salt is good configuration (I write by email as salt, But for the sake of simplicity, I have no email in the user table of this demo, so I need to pay attent

Java Spring Loose coupling The object-oriented concept is a good design to break the system into a group of reusable objects. However, when the system becomes larger, especially in Java projects, large object dependencies will always be tightly coupled to cause the object to be difficult to manage or modify. In this case, you can use the

Org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadbeandefinitionsInfo:loading XML Bean definitions from class path resource [Spring-webservice.xml]October 27, 2015 10:39:09 pm Org.apache.cxf.service.factory.ReflectionServiceFactoryBean buildservicefromclassInfo:creating Service {Http://webservice.fansunion.cn/}userfacadeservice from class Cn.fansunion.webservice.UserFacadeWebService3. You can also access http://localhost:8080/webServi

JAVA entry [21]-simple Spring Data JPA example,-springjpa Spring has powerful support for JPA. Developers only need to focus on the implementation code of core business logic, and do not need to focus too much on the creation of EntityManager, transaction processing, and other JPA-related processing.

used PackageCom.test.bean; Public classPerson {PrivateString name; Private intAge ; PublicString GetName () {returnname; } Public voidsetName (String name) { This. Name =name; } Public intGetage () {returnAge ; } Public voidSetage (intAge ) { This. Age =Age ; } Public voidinfo () {System.out.println ("Let's eat spicy soup together!" "); System.out.println ("Name:" +getname () + "Age:" +getage ()); }}4 Test class Packagetestspring;ImportOrg.springframework.context.Applic