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(select Peopleid,seq from Vitae GROUP by PEOPLEID,SEQ have count (*) > 1)and rowID not in (select min (rowid) from Vitae GROUP by PEOPLEID,SEQ have Count (*) >1)Add:There are more than two duplicate records, one is a completely duplicate record, that is, all the fields are duplicated records, and the second is some ke
count (*) > 1)and rowID not in (select min (rowid) from Vitae GROUP by PEOPLEID,SEQ have Count (*) >1)Add:There are more than two duplicate records, one is a completely duplicate record, that is, all the fields are duplicated records, and the second is some key field duplicate
that both fields have a unique result set of select Identity (int,1,1) as Autoid, * into #Tmp From TableName Select min (autoid) as autoid to #Tmp2 from #Tmp GROUP by name,autoid Select * from #Tmp where autoid in (s Elect autoid from #tmp2) The last select is the result set that name,address does not duplicate (but one moreAutoid field, which can be written to omit this column in the SELECT clause when it
For example, there is a personnel table (table name: peosons)If you want to query records whose names, ID card numbers, and addresses are identical
Select p1. * from persons p1, persons p2 where p1.id
The above results can be achieved.
Several SQL statements used to delete Repeated Records
1. Use the rowid Method
2. U
single-table only query by: DISTINCTUnique query for multiple tables: Group byDistinct when querying multiple tables, the LEFT join is valid and the full connection is invalid.When using MySQL, it is sometimes necessary to query for a record that does not duplicate a field, although MySQL provides the DISTINCT keyword
want to use a statement query to get all the data that name does not duplicate, then you must use distinct to remove the extra duplicate records. The result of the select distinct name from table is that the name a C seems to have worked, but I What do you want to get the ID value? Change the
rowcount @ maxdelete from table name where primary field = @ idfetch cur_rows into @ ID, @ maxendclose cur_rowsset rowcount 0 method 2 "Repeat record" there are two duplicate records. One is a completely repeated record, that is, a record with all fields repeated, second, some records with duplicate keyword segments,
temporary table starts with a two number sign (# #) and is visible to any user after it is created, and is deleted when all users referencing the table are disconnected from SQL Server.This duplication occurs because the table is poorly designed and the unique index columns are added to resolve.3. duplicate records for some key fields: the same value as name an
Label:MongoDB version number is, MongoDB shell version:2.4.4The operating environment, Shell window, is as follows: [mongo_user@mongodb_dbs ~]# mongo --port 30100
2.4.4
127.0.0.1:30000/test
mongos>
usepos
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1, the first statistical grouping records, the Paymentorder field to group statistics, to find out all the statistical results, the group statistics of >1// 这里分组统计出来取分组字段paymentOrder的值_id、最大的objectid值max_id、分组统计数count
vargroup=([
{$grou
(*) >1) 5, redundant records in lookup table (multiple fields), with no rowid minimum records Selec
T * from Vitae a WHERE (A.PEOPLEID,A.SEQ) in (select Peopleid,seq to Vitae GROUP by PEOPLEID,SEQ have count (*) > 1) and rowID not in (SelecT min (rowid) from Vitae GROUP by PEOPLEID,SEQ have Count (*) >1)
Two SayThere is a field "name" in Table A, and the "name" value between different
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/**/
/*-- Query the General Stored Procedure of Repeated RecordsIt can be found that the data in the table is repeated. Here, the record is repeated except the primary key.If the
Ways to query and delete duplicate recordsA1, look for redundant records in the table, duplicate records are based on a single field (Peopleid) to determineSELECT * from Peoplewhere Peopleid in (select Peopleid from People GROUP by Peopleid have count (Peopleid) > 1)2, delet
with duplicate data. This process seems complex, in fact, only the implementation of group by in the T-SQL... Having... .
var ds=db.paymentinfo.aggregate(group, match);
PS: the match is invalid. A lot of data with the count value of 1 is displayed, that is, {"match": {"count": {"gt": 2 }}; failed, why?
4. Back up the data before deletion.
Backup
/usr/local/mongodb/mongodb-linux-x86_64-2.4.4/bin/mongoexpor
Label:rowidbsprowfromsql Query group byseq duplicate record 1. Find redundant duplicate records in the table, duplicate records are based on a single field (Peopleid) to determine the select * from people where Peopleid in (sele
Example:Table stuinfo, which has three fields: recno (auto-increment), stuid, and stuname
The SQL statement used to create the table is as follows:
Create Table [stuinfo] (
[Recno] [int] identity (1, 1) not null,
[Stuid] [varchar] (10) Collate chinese_prc_ci_as not null,
[Stuname] [varchar] (10) Collate chinese_prc_ci_as not null
) On [primary]
Go
1. Check the repeated values of one or more columns.(Only the value of the reco
SQL removes duplicate records, SQL removes duplicates
There are two Repeated Records. One is a completely repeated record, that is, records with all fields being repeated, and the other is rec
the third and the first two.The first 8 items of the sequence are:1, 1, 2, 3, 5, 8, 13, 21
More and better ways
If you want to have the name, ID number, address of these three fields exactly the same records querySelect p1.* from Persons p1,persons P2 where p1.id
can achieve this effect.
Several SQL statements that delete duplicate records1. Using the rowID
Find records for all duplicate headings:
?
1
SELECT * from T_info a WHERE (SELECT COUNT (*) from t_info where title = A.title) > 1) Order by Title DESC
First, find duplicate records
1. Find all duplicate reco
Today due to the work needs, need to find a field in the database a different record value, very simple question is I think too complex, is very depressed, the reason is a command of SQL forgot, now the problem has been solved, quickly take to do the memo.
In fact here only need to use the DISTINCT command in SQL, very simple, the syntax is as follows:
Copy Code code as follows:
SELECT DISTINCT
fields) in the tableSELECT * from Persons awhere (a.personid,a.city) in (select Personid,city from Persons GROUP by Personid,city have count (*) > 1)order by PersonID;PERSONID LASTNAME FIRSTNAME ADDRESS City1 a AA AAA AAAA1 a AA AAA AAAA1 a AA AAA AAAA1 a AA AAA AAAA2 a AA AAA AAAA2 a AA AAA AAAA3 a AA AAA AAAA3 a AA AAA AAAA4. Delete extra duplicate records (multiple fields) in the table, leaving only the
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