sqrt code

Transferred from: http://www.cnblogs.com/pkuoliver/archive/2010/10/06/sotry-about-sqrt.htmlSource: http://diducoder.com/sotry-about-sqrt.htmlWell, I admit I'm heading the party, but since you're here, take a serious look and make sure you get it.We

Although you may not have thought about this problem at ordinary times, it's not that easy to say that it's just like "getting a gun in front of a while, it's not that simple, we use the binary method to test the number of squares in the middle of

First declare: This article for the network reprint, address: http://www.cnblogs.com/pkuoliver/archive/2010/10/06/sotry-about-sqrt.html ========================================================== ======================== Source code:

SQRT (x)Total Accepted: 93296 Total Submissions: 368340 Difficulty: Medium Submission URL: https://leetcode.com/problems/sqrtx/Implement int sqrt(int x) .Compute and return the square root of X.Analysis:Solution 1: Newton's Iterative Method (Newton

We usually have some data operation operations and need to call sqrt, exp, abs and other functions. Have you ever thought about how these function systems are implemented? Take the most common sqrt function as an example. How can the system

ImplementInt SQRT (int x). Compute and return the square rootX. Https://oj.leetcode.com/problems/sqrtx/   Idea 1: the square root of a number must be 0 ~ X/2 + 1, so binary search in this range. Note: Long is used in the intermediate

C Language Standard library:http://www.cplusplus.com/reference/cmath/In an interval, each time the square of the middle number to test, if large, then try the middle of the left interval, if it is small, then take the middle of the right interval to

We usually have some operations of data operations, need to call sqrt,exp,abs and other functions, then you have not thought: how do these functional systems are implemented? Take the most commonly used sqrt function, how does the system implement

Implement int sqrt(int x) . This problem is essentially the largest integer under sqrt (x). Binary search is a more easily thought-out approach. Another, on the internet and learn the other people's Newton iterative method. This is my original

SQRT (X) Implementint sqrt(int x). Compute and return the square rootX. Note ]: 1. Int type may overflow, so multiplication is not allowed. Try to use division. 2. The vast majority of numbers are not open-ended. How can we get close