squares on checkerboard

fake_func (P, x):f = np.poly1d (P) #多项式分布的函数return f (x)#残差函数def residuals (p, y, x):Return Y-fake_func (p, x)#随机选了9个点, as Xx = Np.linspace (0, 1, 9)A lot of points #画图的时候需要的 "continuous"X_show = Np.linspace (0, 1, 1000)y0 = Real_func (x)#加入正态分布噪音后的yy1 = [Np.random.normal (0, 0.1) + Y for y in y0]#先随机产生一组多项式分布的参数P0 = Np.random.randn (M)PLSQ = LEASTSQ (residuals, P0, args= (y1, x))Print (' Fitting Parameters: ', plsq[0]) #输出拟合参数Pl.plot (X_show, Real_func (x_show), label= ' real ')Pl.plot (X_show

the direct purpose of econometrics research is to determine the total regression function Yi=b1+b2xi+ui, however, only the observed values from a number of samples can be obtained, and the sample regression function established with sample information is as close as possible to "To estimate the total regression function. Therefore, it is possible to determine the criteria for establishing a regression function from different angles, and there are many methods to estimate the parameters of re

Sum of squares Public static void main (String [] args) throws IOException {int n; String s; BufferedReader buf; buf = new BufferedReader (new InputStreamReader (System. in); System. out. print ("enter a natural number:"); s = buf. readLine (); n = Integer. parseInt (s); System. out. print ("f (n) = 1"); for (int I = 2; I Exhaustive quantity public static void main(String args[]){int i,j;for(j=2;;j++) {for(i=2;i Quality Factor Public static void mai

Leetcode Note: Perfect Squares I. Description Given a positive integer n, find the least number of perfect square numbers (for example,1, 4, 9, 16, ...) Which sumn. For example, givenn = 12, Return 3 because12 = 4 + 4 + 4; Givenn = 13, Return 2 because13 = 4 + 9. Ii. Question Analysis The general idea of this question is to give a target integer and calculate the minimum number of the target integer from the total number of integers. A better solution

[LeetCode] Perfect Squares Given a positive integer n, find the least number of perfect square numbers (for example,1, 4, 9, 16, ...) Which sum to n. For example, given n =12, Return3Because12 = 4 + 4 + 4; Given n =13, Return2Because13 = 4 + 9. Credits:Special thanks to @ jianchao. li. fighter for adding this problem and creating all test cases. Subscribe to see which companies asked this questionSolutions Dynamic Programming Method. Seasonal Initiali

. out. Print ("*"); }Else{System. out. Print (" "); }}system. out. println (); } for(intI=0;i4; i++){ for(intj=0;j8; j + +){ if(J >ij8-i) {System. out. Print ("*"); }Else{System. out. Print (" "); }}system. out. println (); }Analysis: The first is to determine the length and width are 7 square, divided into two parts, the upper part is I is not see the space portion, with the increase in the *, I smaller, so for self-reduction, J is the number of asterisks, the low

). b); if(Roota! =ROOTB) {Union (Map.get (i). A, Map.get (i). b); Value[count++] =Map.get (i). V; Sum+=Map.get (i). V; if(Count = = n-1) Break; }} sum= SUM/(n-1); Doubletemp = 0; for(inti = 0;i ) {Temp= temp + (Value[i]-sum) * (Value[i]-sum); } temp= Temp/(n-1); if(Minresult >temp) Minresult=temp; } result.add (Minresult); } Public Static voidMain (string[] args) {main test=NewMain (); Scanner in=NewScanner (system.in); while(true) {n=I

Code modified from http://www.cnblogs.com/NanShan2016/p/5493429.htmlBaidu on the Internet a bit, mainly two examples, a use of polynomial functions, one is this. Some of the details are not understood, mainly to ignore the P is an array of parameters instead of a number (python basic problem), tangled up with notes to make a note # 修改自 http://www.cnblogs.com/NanShan2016/p/5493429.html ### 最小二乘法 python leastsq### import numpy as np from scipy.optimize import leastsq

) { for(inti =0; I 3; i++) for(intj =0; J 5; j + +) {if(i0 now[i+x][j+y]!=' ' square[i][j]==' ')Continue; Now[i+x][j+y] = Square[i][j]; } for(inti =1; I 2; i++) for(intj =1;j4; j + +) Now[i+x][j+y] =' ';}BOOLOk () { for(inti =0; I 5; i++) for(intj =0; J 9; j + +)if(Now[i][j]!=s[i][j])return false;return true;}voidOut () { for(inti =0; I 5; i++) { for(intj =0; J 9; j + +) cout BOOLDfsintDEP) {if(Dep >1 OK ())return true;if(DEP >=7)return false;intTemp[m+5][m+5]; for(inti =0; I 3; i++) { fo

https://vjudge.net/problem/UVA-12113On the 4*4 board, with 6 sheets of 2*2 paper, can you pose a given shapeViolent enumeration where each piece of paper is placed#include #includeusing namespacestd;Charend[5][Ten],start[5][9];BOOLOK;BOOLvis[9];voidJudgeCharp[5][9]){ for(intI=0;i5; i++) for(intj=0;j9; j + +) if(End[i][j]!=p[i][j])return; OK=true;}voidDfsintXCharp[5][9]){ if(OK)return; Judge (P); if(x==7)return; Chartmp[5][9]; intId=0; for(intI=0;i3; i++) fo

Method One:#include #include Double fun (int m){int n,i,k;double s = 0.0;for (n=3;n{K = sqrt (n);for (i=2;iif (n%i==0) break; If n is composite, end this layer for loopif (i>=k+1) s + = sqrt (n); I can not be exhausted by N, then N is prime number}return s;}void Main (){int m;Double S;FILE *out;printf ("\n\ninput m:");scanf ("%d", m);s = Fun (M);printf ("\n\ns=%f\n\n", s);}Method Two:#include #include Double fun (int m){/*int n,i,k;double s = 0.0;for (n=3;n{K = sqrt (n);for (i=2;iif (n%i==0) bre

in the use of PPT to make pictures show slides, although the PPT software has provided a lot of pictures show the form and effect of choice, but sometimes can not meet our special requirements. For example, having a picture displayed dynamically on a number of rounded squares is a ready-made effect that is not available in PPT. However, we can use the ready-made animation effect in PPT to create the new picture display effect we need (Figure 1).

Printed Phalanx with Java1 ImportJava.util.Scanner;2 3 Public classp1143 {4 5 Public Static voidMain (string[] args) {6 intI, J, n, k = 1;7 intA[][] =New int[100] [100];8Scanner reader =NewScanner (system.in);9n =reader.nextint ();Ten for(i = 1; I ) { One forj = i; J ) { AA[I][J] =K; -k++; - //s the } - for(j = i; J. ) { -A[j][n+1-i] =K; -k++; + //y - } + for(j = n+1-i; J

Sometimes you need to make a special spreadsheet and make all the tables into the squares you want. Share my experience with you today. 1, open Excel; 2, select all the cells (ctrl + a); 3, move the cursor between the two columns, so that the cursor into the image below, 4, press the left mouse button to drag, then the top will display pixels, the following figure: Select the pixel units you want, and then release the left mouse butt

IE11 Open the page will appear when the box, color box appears there is no law, such as the current open Web page without any problems, and so will continue to browse this page, the page will appear color box. Color box color is also not fixed, and sometimes yellow, red, black and so on. Generally browsing a few pages is not how to appear, when you open more than one page, and scrolling on the Web page, the probability of a color box will be very high. When you open the mailbox, the page appear

Win7 flagship system found that the desktop has a white box, can not be selected, click to refresh is useless, just like the wallpaper reduced a piece, it seems that the desktop is not beautiful, how to solve this problem? The following small series to teach you a way to solve the desktop appearance of white squares. The specific methods are as follows: 1, first start Task Manager, in the desktop taskbar blank, click the right mouse button to choose

The sum of squares and the sum of degrees of freedom This part is actually deduced through the χ2, but the concrete mathematical proof is not speaking, can be explained by the visual case. There is a 3 (m) x3 (n) array. A total of 9 samples, the sample mean value is 4, is also the mean value of each group, that is, mean of means. For sum of Square there is: total sum of square = group Sum of square + inter-group square, or overall fluctuation = intra

()#np. WHERE (PU! = 0) Returns the index of the element in Pu that is not 0, and assigns these elements to a value of 1, and does not know why this is assigned to a value of 1?Pu[np.where (PU! =0)] =1.0Ytcuiy = Fixed_vecs. T.dot (CuI). dot (fixed_vecs) Ytcupu = Fixed_vecs. T.dot (CuI + eye). Dot (Sparse.csr_matrix (PU). T) Xu = spsolve (yty + Ytcuiy + lambda_eye, ytcupu) solve_vecs[i] = XuifI +==0:Print ' Solved%i vecs in%d seconds '% (i, time.time ()-t) T = time.time ()returnSolve_vecs Alterna

least squares, usually used in our known mathematical model, but do not know the model parameters of the case, through the measured data to calculate the mathematical model, for example, in the problem, the mathematical model is the linear equation y=ax+b, but do not know the linear equation of a and B. Originally, we only need two groups (Xi,yi), we can solve A and B, but because of the measured data there are errors, so it is easy to think of a wa

Core code:1 //using least squares algorithm to find the polynomial2 voidYcleastsquaresfitspline::calculatemultinomialvalues (Const void* Valuesptr,intStrideintNintMfloatAConst3 {4Memset (A,0,sizeof(float)*m);5 6 floatXStep =1.0f/(N-1);7 8 inti,j,k;9 floatz,p,c,g,q,d1,d2,s[ -],t[ -],b[ -];Ten for(i=0; i1; i++) One { Aa[i]=0.0f; - } - the if(m>N) - { -m=N; - } + if(m> -) - { +m= -; A } at -z=0.0f; -