student grade program in c

Test instructionsHave n jewels m box Jewel value a box value bEach jewel is placed in a box and costs ABS (A-B)The box can put jewels in infinity.Ask for the minimum costWater problemPre-treatment of each value of jewelry placed in the box O (n)Find the closest left box from left to right L find the closest right box from right to left RTake min#include #include#includestring>#include#include#includeusing namespacestd;Const intn=20005;intn,k,m;intL[n],r[n];intv[Ten*N],s[n];intMain () {inti,j; in

#include #include#include#includeusing namespacestd;Const intmaxn= -;Long Longx,k;Long LongBASEX[MAXN];Long LongBASEK[MAXN];intTOTX,TOTK;intMain () {intT; scanf ("%d",T); while(t--) {scanf ("%lld%lld",x,j); Totx=totk=0; memset (Basex,0,sizeofbasex); memset (Basek,0,sizeofBasek); while(X) {Basex[totx++]=x%2; X=x/2; } while(K) {BASEK[TOTK++]=k%2; K=k/2; } intnow=0; for(intI=0; i) { for(intJ=now;; J + +) { if(basex[j]==0) {Basex

#include #include#include#includestring>#includeusing namespacestd;intT;Chars[ -+Ten];Charr[ -+Ten];mapstring,int>m;structdan{Chars[ -+Ten]; intnum;} d[1000000+Ten];intsum;inttot;BOOLcmpConstDana,Constdanb) { if(A.num==b.num)returnstrcmp (A.S,B.S) 0; returnA.num>B.num;}//Turn lowercasevoidF () { for(intI=0; s[i];i++) if(s[i]>='A's[i]'Z') S[i]=s[i]-'A'+'a';}voidWork () {intlen=strlen (s); Tot=0; for(intI=0; i) { if(s[i]>='a's[i]'Z') r[tot++]=S[i]; Else{R[tot]=' /'; if(strlen

Requirement: write a program to enter the student's student ID, name, and score information, sorted from high to low according to the student's score. # Include # Include Typedef struct student_score{Int ID;Char name [20];Int score; } Stu; // defines the struct. Int main (INT argc, const char * argv []){Int I, J;Int num;Stu TMP, STU [100]; Printf ("how many students? Input the num :");Scanf ("% d", num

Class Demo{public static void Mian (string[] args){System.out.println ("Hello World");System.out.print ("I want to make a TV show about the life of Baoshan University");}}Class is a format, and now I don't know what it is. These things are all code, you should first save the *.java format with NotepadCompile the file in the Javac in class format and open it by the Java program.There is a difference between print and println, which prints out a line followed by an empty line.Java is case-sensitiv

=strlen (str); for(inti=len-1; i>=0; i--){ if(str[i]=='1') {ans+=p; } P*=2; } returnans;}intBinary (LL Val,intID) {Vectorint> VEC =Mp[val]; intDown =0, up = Vec.size ()-1, r=-1, l=INF; while(downUp ) { intMid = (down+up) >>1; if(id-vec[mid]>=A) {R=mid; down= mid+1; }Elseup = mid-1; } Down=0, up = Vec.size ()-1; while(downUp ) { intMid = (down+up) >>1; if(id-vec[mid]c) {L=mid; up= mid-1; }ElseDown = mid+1; } //printf ("%d%d\n", l,r); if(L>r)return 0; returnr-l+1;

, so it is not very clear whether or not, and other ideas, such as statistics so the collection of pinyin (should not be too much), as for the statistics of English and Spanish, at present I still did not think of some good ideas, have participated in the Great God for advice ~The final result, we ranked 40th (over 4 questions of the first, to their comfort ~), the second prize or the difference of 4 places, although the process is important, but in fact, to tell the truth oneself still quite va

+1, cmp);103priority_queueint,vectorint>,cmp1>q;104 the for(i=1; i)106 {107Q.push (i); y=a[i].et;108sum-=a[i].d;109x=q.top (); the while(y-a[x].st>ta !)Q.empty ())111 { thesum+=a[x].d;113Q.pop (); x=q.top (); the } theans=min (ans,sum); the }117printf"%d\n", ans);118 }119 return 0; - }121 /*122 //123 124 // the */View CodeHihocoder 1391 Countries "preprocessing + sorting + heap" (ACM-ICPC International College

Topic: problem 2268 Cutting Game accept:10 Submit:12Time limit:1000 mSec Memory limit:32768 KB problem Description Fat brother and Maze is playing a kind of the special (hentai) game with a piece of gold of length n where n was an integer. Although, Fat Brother and Maze can buy almost everything in this world (except love) with this gold, but they still think That's not convenient enough. Just like if they would like to buy the moon with M lengths of the gold, the man who sold the moon need to p

1; the } the ll Max (ll A,ll b) About { the returnA>b?a:b; the } the intMain () + { - intT; thescanf"%d",t);Bayi while(t--) the { the ll N; -scanf"%llu",n); - if(n==4) theprintf"2 2\n"); the Else the { the for(LL i=2; i2; ++i) - { the if(Is_prime (i) is_prime (ni)) the { theprintf"%llu%llu\n", i,n-i);94 Break; the } the } the }98 } About}

finished, but debug again appeared the pit Dad's low-level error, small bug tune for a long time, the above write the void function, the following written ans=f (x), there is a low-level boundary write wrong, tune for a while, fortunately 1 A, c I write down the code to waste a lot of times. Then at this time we 5 questions, stuck in the I question, the leader continues to adjust his WA code, I began to push the algorithm of I problem inverse example to try to find a bug, butAfter Hu Niu introd

after the expert judges of the layers of carefully selected and serious discussion, congratulations to the following students finally selected CSDN University Club "College students program ape It Love letter 2014 loves the Confession Challenge Event" winners list. The winner will receive an email notification within this week. Please respond to the email request for the prize collection method. At the same time, all winners will receive exclusive ma

BigInteger (ASTR); BigInteger B = new BigInteger (BSTR); BigInteger n = biginteger.valueof (5); BigInteger temp = b.multiply (n);//?? Number of digits multiplied by 5 times times//System.out.println (temp); BigInteger r = a.subtract (temp);//Use the original remaining number minus 5* single digit/SYSTEM.OUT.PRINTLN (R); R = R.abs ();//Convert to absolute value//SYSTEM.OUT.PRINTLN (R); BigInteger m = biginteger.valueof (17); System.out.println (m); System.out.println (R.mod (m)); if (R.mod (m).

are integers. There is a space between the data. OutputFor each set of test data, the output is one line: The number of treasures the robot has to carry the most valueSample input22 30 10 1010 10 803 30 3 92 8 55 7 100Sample output120134D[k][x1][y1][x2][y2]={max (d[k-1][x1-1][y1][x2][y2-1],　　　　　　　　　　　　　　　D[k-1][x1-1][y1][x2-1][y2],　　　　　　　　　　　　　　　D[K-1][X1][Y1-1][X2][Y2-1],　　　　　　　　　　　　　　　D[k-1][x1][y1-1][x2-1][y2])　　　　　　　　　　　　　+A[X1][Y1]+A[X2][Y2];　　　　　　　　　　　　　};#include #include#includeusing na

Beijing University Student Information bar whole site program V1.0 cookie Injection Cast blogIn the gonggao. asp file, rows 9-31:Dim id, rs, SQLId = trim (request ("id") // noteIf id = "" thenCall list ()Response. endEnd ifSet rs = server. createobject ("adodb. recordset ")SQL = "select * from [gonggao] where id =" cstr (id) // noteIf rs. eof and rs. bof thenResponse. write "no news"Response. endEnd ifFunc

Title Link: http://acm.hdu.edu.cn/contests/contest_showproblem.php?pid=1011cid=719Sample Input 2 AABCCACDEAA Sample outputcase # 1 3 Case # 2 4***************************************************Test instructions: I can only say Test instructions God horse is a cloud, purely interference, directly look at the code bar1#include 2#include string.h>3#include 4#include 5#include 6 using namespacestd;7 #defineN 11008 9 Chars[110000];Ten intv[ -]; One A intMain () - { - inti,t,k=1, Len; the -scan

"Internet".TipsPages in the cache before visiting 1st URL [null, NULL]Pages in the cache before visiting 2nd URL [www.bing.com (1), NULL]Pages in the cache before visiting 3rd URL [www.bing.com (1), www.microsoft.com (2)]Pages in the cache before visiting 4th URL [www.bing.com (1), www.microsoft.com (3)]Pages in the cache before visiting 5th URL [windows.microsoft.com (4), www.microsoft.com (3)]The number in parentheses was the last visiting timestamp of the page.Sample input5 2www.bing.comwww.

Number of combinations:AC Code:#include #include#includeusing namespacestd;intc[1010][1010];intMain () {intT, N, K; for(inti =0; I 1001; i++) c[i][0] =1; for(inti =1; I 1001; i++) { for(intj =1; J 1001; J + +) {C[i][j]= (C[i-1][j-1] + c[i-1][J])%10000003; }} scanf ("%d", t); while(t--) {scanf ("%d%d", n, k); printf ("%d\n", C[n][k]); } return 0;}/************************************** problem id:sdut OJ D User name:xam140325 Choru Result: Accepted take memory:4464k take time:20m

tree, the shortest distance of two nodes, first let the following node jump to the top of the node on the layer, record the number of steps, and then two nodes a jump, until meet, record steps, two steps to add on it.#include G Hearthstone IIhttp://www.sdutacm.org/sdutoj/problem.php?action=showproblemproblemid=2883Test instructions for n races to use the M-table, each table is used at least once, the table is different, ask how many kinds of arrangement method.That is, to divide n elements into

the one contains the largest length of roads.Can you help him?InputThere is no more than test cases, and the most cases is very small.The first line of the input contains an integer T which means the number of the test cases.The first line of all test case contains-integers, N, m, which is the number of vertices and the number of edges. All vertices is numbered from 1 to N.The next m lines, each line consists of three integers, u, V, W, which means there are an undirected edge between U and V,