subtract months from date

Add and subtract functions for SQL Server Date: DATEDIFF DATEADDDATEDIFF: Returns the number of date boundaries and time boundaries across two specified dates, syntax: DATEDIFF (datepart, StartDate, enddate) minus EndDate with StartDateNote:

Original address: http://blog.csdn.net/xyzqiang/article/details/6577831Add and subtract functions for SQL Server Date: DATEDIFF DATEADDDATEDIFF: Returns the number of date boundaries and time boundaries across two specified dates, syntax: DATEDIFF

Before we know that SQL has the DateDiff () function, we need to calculate the date and time difference. I will directly put it in a program like php, asp, and asp.net for calculation, now I will share with you how to use the DateDiff function to

This is the SQL script that calculates the first day of the one month:SELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ()), 0)--the first day of the monthSELECT DATEADD (mm, DATEDIFF (Mm,0,getdate ())-1, 0)-the first day of the monthSELECT DATEADD

Mysql sets two date formats to subtract. mysql sets two date formats to Subtract: Original data table data: Select (atime-btime) sec from data table; The subtraction result is not a second. pay special attention to it! Result: To

The following summarizes the implementation methods for obtaining a specified date in Java. For more information, seeCopy codeThe Code is as follows:Format a Date String --> Date or Data --> String SimpleDateFormat sdf = new SimpleDateFormat

Using date types in PL/SQLThe previous article described the use of strings and numbers in PL/SQL. There is no doubt that strings and numbers are important, but you can be sure that no application is dependent on the date.You need to record events,

Date and Time functionsThis chapter discusses some functions that can be used to manipulate time values. See section 11.3, "Date and Time type" for valid formats for each time and date type with a range and a specified value. The following example

Use the function date () to implement the displayed in the format: year-month-day hours: minutes: secRelated Time parameters:A-"AM" or "PM"A-"AM" or "PM"D-A few days, two digits, if less than two digits before the 0; such as: "01" to "31"D-Days of

SelectTimediff ('23:40:00','18:30:00'); --subtract two time select substring (Timediff ('23:40:00','18:30:00'),1,5) ----“ to：Ten"Subtract back hours: minutesSelectDateDiff'2008-08-08','2008-08-01'); --7-----Two date subtractionSelectTo_days ('2008-09