sudoku maker and solver

Title Link: Valid-sudokuImport java.util.arrays;/** * Determine if a Sudoku is valid, according To:sudoku puzzles-the rules.the Sudoku Board Co Uld be partially filled, where empty cells is filled with the character '. A partially filled sudoku which is valid. Note:a Valid Sudoku board (partially filled) is not necessa

numbers are legal, which can make the program more efficient, as shown in the code:classSolution { Public: voidSolvesudoku (vectorChar> > Board) { if(Board.empty () | | board.size ()! =9|| board[0].size ()! =9)return; Solvesudokudfs (board,0,0); } BOOLSolvesudokudfs (vectorChar> > board,intIintj) {if(i = =9)return true; if(J >=9)returnSolvesudokudfs (board, i +1,0); if(Board[i][j] = ='.') { for(intK =1; K 9; ++k) {Board[i][j]= (Char) (k +'0'); if(isValid (board, I, J))

Programming the beauty of the first chapter of the 15th section, talking about the construction of Sudoku, a start to get this problem really no idea, but read the book in the introduction, found that the original solution of the idea and the N queen problem is consistent, but do not know why, anyway, at first did not think of this backtracking method, know that is solved by backtracking, The problem becomes much easier.Here we do not intend to implem

Solvesudoku (vectorPython source code (636MS):Class Solution: # @param {character[][]} board # @return {void} do not return anything, modify board In-place Instea D. def solvesudoku (self, Board): self. SudoKu (board,0,0) def SudoKu (self,board,i,j): If I==8 and J==9:return True if j==9:i+=1;j=0 if boa Rd[i][j]!= '. ': if self. SudoKu (board,i,j+1

Original title address: https://oj.leetcode.com/problems/sudoku-solver/Test instructionsWrite a program to solve a Sudoku puzzle by filling the empty cells.Empty cells is indicated by the character ‘.‘ .Assume that there would be is only one unique solution.A Sudoku Puzzle ...... and its solution numbers marked in red.

#-*-Coding:utf8-*-‘‘‘__author__ = ' [email protected] '37:sudoku Solverhttps://oj.leetcode.com/problems/sudoku-solver/Write a program to solve a Sudoku puzzle by filling the empty cells.Empty cells is indicated by the character '.Assume that there would be is only one unique solution.===comments by dabay===Progressive

LeetCode: Sudoku Solver, leetcodesudoku Sudoku Solver Total Accepted: 13937 Total Submissions: 66832My Submissions Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character'.'. You may assume that there will be only one

{ - return true; - } theBoard[i][j]= '. '; - } - return false; - } + } - } + return true; A } at Private BooleanIsvalidsudoku (Char[] board,intRowintColum) { - for(intj=0;j) - if(J! = Colum Board[row][j] = =Board[row][colum]) - return false; - -

Title:Write a program to solve a Sudoku puzzle by filling the empty cells.Empty cells is indicated by the character ‘.‘ .Assume that there would be is only one unique solution.A Sudoku Puzzle ...... and its solution numbers marked in red.Test Instructions:Write a program to solve Sudoku problems by filling in whitespace.These spaces are characters‘.‘填充。You can as

Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character‘.‘. You may assume that there will be only one unique solution. A Sudoku puzzle... ... And its solution numbers marked in red. The sudoku solver was finally reached. With the basis of valid

Sudoku Solver Total accepted:11799 Total submissions:56732 My submissions Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character'.'. You may assume that there will be only one unique solution. A Sudoku puzzle... ... And its solution numbers marked in

complexity: O (n2)1 class Solution2 {3 int used1[9][9], Used2[9][9], used3[9][9];4 5 Public:6 void Solvesudoku(VectorVectorChar> > Board)7 {8 VectorVectorint>> Place;9 for(int I = 0; I Board.size(); ++ I)Ten for(int J = 0; J Board[I].size(); ++ J) One { A if(Board[I][J] == '. ') - Place.push_back({I, J}); - Else the { - int Num = Board[I][J] - '

Topic Connectionhttps://leetcode.com/problems/sudoku-solver/Sudoku solverdescriptionWrite a program to solve a Sudoku puzzle by filling the empty cells.Empty cells is indicated by the character ‘.‘ .Assume that there would be is only one unique solution.A Sudoku Puzzle .....

the termination of the condition of recursion, to reach the termination conditions, the inspection results are qualified, qualified records down. And the essence of backtracking is in the following for loop, a total of 5 steps, the last two steps is just the first two steps of the anti-operation, and therefore become ' backtracking '. We can argue that backtracking is an optimization of brute force search (brute).A little gossip, to see Sudoku

/** 37. Sudoku Solver * 2015.12.13 by Mingyang * 1. Length standard: None * 2. Optional range: All the wood is worth the point, pick a number from 1 to 9 * 3. Take a step forward: if put in is validate, then Put * 4. Take a step back: if you put it in and the back is false, change the point back to * 5. Special case: No * 6. On repetition: none * The IsValid of this topic is difficult * row = I/3 * 3; Row *

Write a program to solve a Sudoku puzzle by filling the empty cells.Empty cells is indicated by the character ‘.‘ .Assume that there would be is only one unique solution.A Sudoku Puzzle ...... and its solution numbers marked in red.classSolution { Public: voidSolvesudoku (vectorChar>> Board) {Backtracking (board,0); } BOOLBacktracking (vectorChar>> board,intLine ) { //Find first empty cell

1 classSolution {2 Public:3 voidSolvesudoku (vectorChar>>Board) {4 Sudoku (board);5 }6 Private:7 BOOLSudoku (vectorChar>>Board)8 {9 for(inti =0; I 9; ++i) {Ten for(intj =0; J 9; ++j) { One if(Board[i][j] = ='.') { A for(intK =0; K 9; ++k) { -BOARD[I][J] ='1'+K; - if(IsValid (board, I, J) Sudoku (board))retur

for(intCol =0; Col 9; ++Col) { + if(Board[row][col] = ='.'){ - for(inti =1; I 9; ++i) { theBoard[row][col] ='0'+i; * if(checkvalid (board, Row, col)) { $ if(Dosudoku (board)) {Panax Notoginseng return true; - } the } +Board[row][col] ='.'; A } the return false; +

+'1'; if(IsValid (board,i,j)) DFS (board); if(!flag)//If no workable solution is found, the restorationBOARD[I][J] ='.'; Else //have found a workable solution, return directly, not continue the next cycle return; } if(k==9)//Maintenance If the fill 1-9 is not satisfied, the previous results have a problem return; } if(i==8 j==8)//found a workable solution.Flag =true; } } voidSolvesudoku (vect

; + } - } + } A return true; at } - - Private BooleanIsValid (Char[] board,intRowintCol) { - //TODO auto-generated Method Stub - for(inti=0;ii) { - if(i!=rowboard[i][col]==Board[row][col]) in return false; - } to for(inti=0;ii) { + if(i!=colboard[row][i]==Board[row][col]) - return false; the } * for(intI= (ROW/3) *3;ii) { $ f