superhero superhero games

Bzoj 1191 Superhero Hero DescriptionNow the TV station has a kind of program called superhero, the approximate process is each player to the stage to answer the host several questions, and then according to answer the question how much to obtain a different number of prizes or bonuses. Moderator questions prepared a number of topics, only when the player correctly answer a question, can enter the next

Tags: bzoj bzoj1191 bipartite graph maximum matching Hungary Algorithm Given n tips and M questions, one of the two tips can be used for each question. The question must be answered continuously and the maximum number of questions can be answered. The maximum matching of a bipartite graph. If a problem occurs, the two sides are connected to the given tip, and the Hungary algorithm searches for the augmented path. If the two sides are not found, the break At first, I practiced a side betwee

1#include 2#include 3#include 4#include 5 using namespacestd;6 Const intmaxn=1001+ -;7 intP[MAXN][MAXN];8 intVIS[MAXN],LK[MAXN];9 intn,m;Ten One voidInit () A { -scanf"%d%d",n,m); - for(intI=1; i) the { - intu,v; -scanf"%d%d",u,v); -p[i][u]=p[i][v]=1; + } - } + A intFindintu) at { - for(intI=0; i) - { - if(!vis[i] P[u][i]) - { -vis[i]=1; in if(!lk[i] | |find (Lk[i])) - { tolk[i]=u; + return 1; - }

#include 5#include 6#include 7#include 8 #defineMAXN 10059 using namespacestd;Ten One A intMAP[MAXN][MAXN]; - intVIS[MAXN],ATT[MAXN]; - intN,m,ans; the - BOOLCanintx) - { - for(intI=1; i) + { - if(map[x][i]==1vis[i]==0) + { Avis[i]=1; at if(!att[i]| |can (Att[i])) - { -att[i]=x; - return 1; - } - } in - } to return 0; + } - the intMain () * { $Memset (ATT,0,sizeof(ATT));Panax Notoginsengscan

Go directly to Hungary, notice that "only when the player correctly answer a question, you can enter the next question, or be eliminated", once unable to meet the direct exit.1#include 2#include 3#include 4 #defineMAXN 20085 #defineMAXM 100086 7 structedge{8 intU,v,next;9 }EG[MAXM];Ten One intn,m,sum; A intLAST[MAXN],L[MAXN]; - BOOLPD[MAXN]; - the voidAddintUintv) - { -eg[++sum].u=u; -eg[sum].v=v; +eg[sum].next=Last[u]; -last[u]=sum; + } A BOOLFindintu) at { - for(intI=last[u];i;i=eg[

1191: [hnoi2006] Superhero herotime limit: 10 sec memory limit: 162 MB Submit: 1804 solved: 850 [Submit] [Status] Description There is now a program called superhero on the TV station. The general process is that each contestant answers several questions from the host on the stage, and then receives several prizes or bonuses based on the number of questions answered. The host has prepared several question

1191: [HNOI2006] super hero Hero DescriptionNow the TV station has a kind of program called superhero, the approximate process is each player to the stage to answer the host several questions, and then according to answer the question how much to obtain a different number of prizes or bonuses. Moderator questions prepared a number of topics, only when the player correctly answer a question, can enter the next question, or be eliminated. In order t

Descriptionnow the TV station has a kind of program called superhero, the approximate process is each player to the stage to answer the host several questions, and then according to answer the question how much to obtain a different number of prizes or bonuses. Moderator questions prepared a number of topics, only when the player correctly answer a question, can enter the next question, or be eliminated. In order to increase the interest of the progra

We will give you a detailed analysis of the photoshop software and share with you how to design the illustration of the superhero Wonder Girl.Tutorial sharing:1. DiagramAfter the subject matter is determined, the first step is the composition process. Some people think that composition is the core of creation, or the core part that reflects creativity. In fact, this is just a starting point,What we need to do at this point is to design the architectur

Q: You can use one of two trick answers to answer a single question. One trick can only be used once at most, and the maximum number of questions that can be answered in a row is allowed.Idea: I first thought of the maximum matching of a bipartite graph, but I was totally confused. I think there are two trick options available for each question. It is obviously wrong to use this to split the points and create a graph ..The correct solution is to use each question and each trick to build an edge.

The model of the Bipartite Graph is an adaptation of a classic question. As shown in a graph theory book, there are n people and M positions, and each position can only be provided to one person, while each person can only be qualified for a limited position due to limited ability, ask if there is a way to make everyone have a job, and if not, how many people can provide a job at most. If you have read this classic question, the idea of this question is as follows: Consider n questions as N poin

The bare maximum match.1#include 2#include 3#include 4 using namespacestd;5vectorint>g[2002];6typedef vectorint>:: iterator ITER;7 intn,m,mat[2002],x,y;8 BOOLvis[2002];9 BOOLDfsintU)Ten { One for(ITER it=g[u].begin (); It!=g[u].end (); it++) A if(!vis[*it]) - { -vis[*it]=1; the if(mat[*it]==-1|| DFS (mat[*it])) - { -mat[*it]=U; - return 1; + } - } + return 0; A } at intMax_match () - { -memset (mat,-1,sizeof(MAT));int