supermicro 2 5 to 3 5

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Using regular expressions to implement the Operation Express = ' 1-2* ((60-30 + ( -40/5) * (9-2*5/3 +7/3*99/4*2998 +10 *568/14))-( -4*3)/(16-3*2)) '

#!/usr/bin/env python# Coding:utf-8Import Redef Dealwith (Express): Express.replace ('+-','-') Express.replace ('--','+') returnexpressdef Col_suanshu (exp):if '/' inchexp:a,b= Exp.split ('/') returnStrfloat(a)/float(b))if '*' inchexp:a,b= Exp.split ('*') returnStrfloat(a) *float(b) def get_no_barcate (Express): Express=express.strip ('()') Print ('>>>', Express) whileTrue:ret= Re.search ("-?\d+\.? \d*[*/]-?\d+\.? \d*", Express)ifRet:res=Col_suanshu (Ret.group ()) Express= Ex

(Two new ideas about an algorithm question) give you a set of strings, such as {5, 2, 3, 2, 4, 5, 1, 5}, so that you can output the one with the most occurrences and the largest number, appears several times

It is not very difficult to see an algorithm question on the Internet. There are also solutions for searching, but there are usually several layers of for loops. I tried to write it down. /*** Give you a set of strings such as {5, 2, 3, 2, 4, 5,}, so that you can output the

Thunder programming questions: programming: Find a number in addition to 2 + 1 In addition to 3 + 2 in addition to 4 + 3 in addition to 5 + 4 in addition to 6 + 5 in addition to 7 + 0

Package com; public class test {public static void main (string [] ARGs) {system. out. println (getsteps1 (); system. out. println (">>>>>>>>>>>>>>>>>>>>>>>>>>>>"); system. out. println (test. getsteps (); system. out. println (">>>>>>>>>>>>>>>>>>>>>>>>>>>> ");} public static int getsteps () {// use the minimum public multiple to reduce the number of traversal times. Int I = 1; int step = 2; Boolean maxstep = false; while (true) {system. Out. Print ("

There is a fractional sequence of 2/1 + 3/2 + 5/3 + 8/5 + 13/8 +... Find the sum of the first 20 items of the series.

There is a fractional sequence of 2/1 + 3/2 + 5/3 + 8/5 + 13/8 +... Find the sum of the first 20 items of the series.Program: # Include Output result: 32.660261 Press any key to continue

C language: There is a score sequence: 2/1 + 3/2 + 5/3 + 8/5 + 13/8 +... Find the sum of the first 20 items in this series

C language: There is a score sequence: 2/1 + 3/2 + 5/3 + 8/5 + 13/8 +... Find the sum of the first 20 items in this seriesProgram: # Include Output result: 32.660261 Press any key to continue

Starting 3 threads, thread 1 printing 1 to 5, thread 2 printing 5 to 10, thread 3 printing 11 to 15, then thread 1 printing 16 to 20, and so on ... Print until 30

Starting 3 threads, thread 1 printing 1 to 5, thread 2 printing 5 to 10, thread 3 printing 11 to 15, then thread 1 printing 16 to 20, and so on ... Print until 30 public class Mainthread {private static int num;//current record number private static final int threadnum

16. There is a fractional sequence of 1/2, 2/3, 3/5, 5/8, 8/13 ,... Calculate the sum of the first 200 items of the sequence.

Vector used: # include # Include Using namespace STD; Int fenshu (INT ); Int main () { Double sum = 0, sum1 = 0; For (INT I = 2; I { Sum1 + = fenshu (I ); } Sum = sum1 + 0.5; Cout Return 0; } Int fenshu (INT index) { Double temp; Vector A. Reserve (3 ); A. At (0) = 1; A. at (1) = 2; For (INT I = 2; I { A. insert (A.

1, 2, 3, 5, 7, 8, 10, 11, 12, 13, 14, 15, 16, 21, 22-"1 ~ 3, 5, 7 ~ 8, 10 ~ 16,21 ~ 22

In order to omit the space and make it visible to the operator who manually fills in the paper, the volume number on the card of the materials shelf is determined to be classified and sorted, as shown in A-3, A-4, A-5, A-8 forming A-3 ~ 5, 8, etc. The following code uses a few auxiliary list /// /// Similar to 1,

Use 1, 2, 3, 4, and 5 to form a five-digit repeat. 4 cannot be In the third place, and 3 cannot be connected to 5 (the simplest way)

Package COM. WZS; // Add difficulty to the first question. Use the numbers 1, 2, 3, 4, and 5 to write a main function in Java and print out all the different orders, // For example, 51234, 12345, etc., the requirement: "4" cannot be In the third place, "3" and "5" cannot be

There are now n ordered arrays in the M group, such as {1, 2, 3, 3}, {2, 3, 4, 6}, {1, 3, 5, 7}. In these arrays, select the data smaller than K, then return this value

Problem description: there are now n ordered arrays in M groups, such as {1, 2, 3, 4}, {2, 3, 6}, {1, 3, 5, 7 }, select the data smaller than K in these arrays and return this value. Idea: Compare the minimum data selected each ti

Obtain the fractional sequence: 2/1, 3/2, 5/3, 8/5, 13/8, 21/13... The sum of the first 20 items

/***//** * Fractionserial. Java * There is a fractional sequence: 2/1, 3/2, 5/3, 8/5, 13/8, 21/13... * Calculate the sum of the first 20 items of the series. * @ Author Deng Chao (codingmouse) * @ Version 0.2 * Development/test en

Calculate the sum of the First n items of the Fibonacci fractional sequence (N is a constant, and the Fibonacci fractional sequence is 2/1, 3/2, 5/3, 8/5 ,...)

Calculate the sum of the First n items of the Fibonacci fractional sequence (N is a constant, and the Fibonacci fractional sequence is 2/1, 3/2, 5/3, 8/5 ,...). # Include Stdio. h > # Include Conio. h > Void

There is a fractional sequence: 2/1, 3/2, 5/3, 8/5, 13/8, 21/13... find the sum of the first 20 items of this series

# Include }/* The numerator behind the score is equal to the numerator plus the denominator of the previous score, and the denominator of the subsequent score is equal to the numerator with the previous score */ There is a fractional sequence: 2/1, 3/2, 5/3, 8/

Opencv learning notes 1, (tbb_debug error, learning opencv examples 2-1, 2-2, 2-3, 2-4, 2-5, 2-6, 2-7, 2-8, 22-9, 2-0)

Opencv experiences (1) The second chapter of learning opencv mainly introduces some common and interesting functions and data types, so that students at the beginning are more interested in image processing, although I do not understand the internal experiment of the function and the meaning of some defined constants, I am still very happy after learning Chapter 2. At least I know some basics of image processing, such as contour processing; Knowledge

Int a [5] = {1, 2, 3, 4, 5}; printf (& quot; % d \ n & quot;, * (int *) (& amp; a + 1)-2);, printf % d

Int a [5] = {1, 2, 3, 4, 5}; printf ("% d \ n", * (int *) ( a + 1)-2 );, printf % d What is the result of a certain convincing pen question in a certain year? The answer is 4. Why? My understanding (do not know if it is correct ): A is an array pointer of the int type [

[Programming question] calculates the longest descending subsequence of an array, for example, {9, 4, 3, 2}. The longest descending subsequence is {9, 5, 4, 3, 2}

47. Innovation workshop (algorithm ):Returns the longest descending subsequence of an array, for example, {9, 4, 3, 2, 5, 3, 2,4,3, 2} Idea: Dynamic Planning Calculates the longest descending subsequence of the sequence of the current number. Each time you look for the long

C, enter a positive integer that outputs all of its prime number factors (such as 180=5*3*3*2*2) in order from large to small

1#include 2 using namespacestd;3 4 intMain ()5 {6 Longnum;7 8 while(Cin >>num) {9 if(num = =1){Tencout Endl; One Continue; A } - - for(inti =2; I i) { the if(num%i = =0){ -num = num/i; -cout " "; -i--;//When a prime number is encount

An array of integers and the largest contiguous subarray, for example: [1, 2,-4, 4, 10,-3, 4,-5, 1] The largest contiguous subarray is [4, 10,-3, 4] (to be stated and programmed)

$arr= [1, 2,-4, 4, 10,-23, 4,-5, 1]; $max _sum= 0; $sum=0; $new= []; $i= 1; Echo' ; foreach($arr as $key=$value ){ if($sum){ unset($new[$i]); $i++; $sum=$value; }Else{ $sum+=$value; } $new[$i][] =$value; if($max _sum$sum){ $max _arr=$new; $max _sum=$sum; } } Print_r($max _sum); Print_r($max _arr); Exit;An array of integers and the largest contiguous subarray, for

Title: Decompose a positive integer into factorization. For example: Enter 90 and print out 90=2*3*3*5.

1 ImportJava.util.*;2 Public classlianxi04{3 Public Static voidMain (String []a) {4Scanner s =NewScanner (system.in);5System.out.print ("Please type a positive integer:"); 6 intn=s.nextint ();7 intk=2; 8System.out.print (n + "=" );9 while(k N) {Ten if(k = = N) {System.out.println (n); Break;} One Else if(n% k

Factorization a positive integer into a prime factor. For example, enter 90 and print 90 = 2*3*3*5.

// Question: decompose a positive integer into a prime factor. For example, enter 90 and print 90 = 2*3*3*5.// Program analysis: to decompose the prime factor of N, you should first find a minimum prime number k, and then follow the steps below to complete:// (1) if the prime number is equal to N, it indicates that the

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