tesla q3

English Description: Design an algorithm to find the kth number such, the only prime factors is 3, 5, and 7Idea: Factorization can only be 3,5,7, set this number to Val, then val = (3^i) (5^j) (7^n) (i,j,n>=0), obviously the 1th number is 1, 2nd is 1*3, 3rd is 1*5, 4th is 1*7, 5th is 3*3, 6th is a 5, the 7th one for 3*7 ...If the number of money k-1 into a linked list R, it can be seen that the number of K is 3 or 5 or 7 times the number of previous k-1 one, to get a minimum number of R has not

of the management business, and only the management function and the business meet the consistency to achieve interoperability. Now many telecom companies have launched access network products and their operation management system, but the access network of different manufacturers still difficult to achieve unified network management, this is precisely because they can only meet a level or a number of levels of consistency, rather than complete consistency. The formation of access network vend

just because the code is long-cut inefficient but easy to understandSelect Id,[name],' 1 ' = (select sum ([profile]) from test where id=a.id and Quarter=1),' 2 ' = (select sum ([profile]) from test where id=a.id and quarter=2),' 3 ' = (select sum ([profile]) from test where id=a.id and quarter=3),' 4 ' = (select sum ([profile]) from test where id=a.id and quarter=4)From Test as aGROUP BY Id,name-----------------------------------------------------------------------------------------Unpivot func

some energy. In my extracurricular search, I am very attracted to the now very famous Tesla Tesla: Tesla is committed to using the most innovative technology to accelerate the development of sustainable transport. Tesla has technically provided an efficient way to achieve sustainable energy supply, reducing global tra

difference will be greater, UBUNTU+GPU is the only choice.Test Platform 1:I7-4770K/16G/GTX 770/cuda 6.5MNIST Windows8.1 on cpu:620sMNIST Windows8.1 on gpu:190sMNIST Ubuntu 14.04 on cpu:270sMNIST Ubuntu 14.04 on gpu:160sMNIST Ubuntu 14.04 on GPUs with cudnn:30sCifar10_full on GPU wihtout cudnn:73m45s = 4428s (iteration 70000)Cifar10_full on GPU with cudnn:20m7s = 1207s (iteration 70000)Test Platform 2: Gigabyte p35x v3,[email protected]/16g/nvidia GTX 980 8GMNIST Ubuntu 15.04 on GPUs with cudnn:

installation are complete, and the following is a simple set of data controls. The experiment originates from the mnist data set, which mainly investigates the performance of CPU and GPU under different systems. Can see the obvious difference. Although the mnist datasets are very easy to believe, the difference is greater and UBUNTU+GPU is the only choice for complex datasets.Test Platform 1 : I7-4770K/16G/GTX 770/cuda 6.5MNIST Windows8.1 on CPU : 620sMNIST Windows8.1 on GPU : 190sMNIST Ubuntu

established the general theory of relativity. The equator radius of mercury is about 2440 km, which is 38.3% of the earth's size. The mass is 5.6% × 3.33 grams, which is also 1026 of the earth's size. The average density is 5.6% grams/cm. 3, second only to the earth, the acceleration of surface gravity is 373 cm/second 2. The inversion rate is 0.06, and the color index is + 0.91, which is slightly smaller than that of the moon. The surface of mercury is very similar to the moon, with many diffe

mnist data set, mainly to examine the performance of the CPU and GPU under different systems. Can see the obvious difference, although the Mnist dataset is very simple, believe that the complex data set, the difference will be greater, UBUNTU+GPU is the only choice.Test Platform 1:I7-4770K/16G/GTX 770/cuda 6.5MNIST Windows8.1 on cpu:620sMNIST Windows8.1 on gpu:190sMNIST Ubuntu 14.04 on cpu:270sMNIST Ubuntu 14.04 on gpu:160sMNIST Ubuntu 14.04 on Gpuwith cudnn:30sCifar10_full on Gpuwihtout cudnn:

the performance of the CPU and GPU under different systems. Can see the obvious difference, although the Mnist dataset is very simple, believe that the complex data set, the difference will be greater, UBUNTU+GPU is the only choice.Test Platform 1 : I7-4770K/16G/GTX 770/cuda 6.5MNIST Windows8.1 on CPU : 620sMNIST Windows8.1 on GPU : 190sMNIST Ubuntu 14.04 on CPU : 270sMNIST Ubuntu 14.04 on GPU : 160sMNIST Ubuntu 14.04 on Gpuwith CuDNN : 101cifar10_full on Gpuwihtout CuDNN : 73m45s = 4428s ( Ite

= My_car.read_odometer () my_car.updata_odometer (My_car.read_) Odometer () My_car.increment_odometer () My_car.read_odometer () class Electriccar (CAR): "", DocString for Electriccar "" Def __init__ (self, make, model, year): ' Initialize the properties of the parent class ' super (Electriccar, self). __init__ (make, model, year) #self . arg = arg My_tesla = Electriccar (' Tesla ', ' Model S ', 2016) print (My_tesla.get_name ())Result :2016

Stored Procedures | issues Only one table is involved: Xkb_treenode The table structure is like this: node_id int//Node ID parentnode_id int//parent Node ID Node_text varchar//node content IsModule bit//whether leaf node The data that is now saved is: node_id parentnode_id Node_text IsModule 1-1 Languages and Literature 0 2-1 Mathematics 0 3-1 Technology 0 4 1 Languages 0 5 1 Foreign Languages 0 6 5 English 0 7 6 Junior English 0 8 7 Tesla Tower 1

Http://blog.sina.com.cn/s/blog_6a706ff30100sgbb.html What is a four-digit number of points. The quartile, which is statistically, arranges all the values from small to large and divides them into four equal points, with a score of four in the three-point position. The 14th Division (Q1), also known as the "smaller four", is equal to the number of all the values in the sample from small to large after the 25th. The 24th (Q2), also known as the "median", is equal to the number of all values in

"OK, encryption complete! "?> Encryption Method 2: The Code is as follows: Function RandAbc ($ length = "") {// returns a random string$ Str = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz ";Return str_shuffle ($ str );}$ Filename = 'index. php'; // file to be encrypted$ T_k1 = RandAbc (); // random key 1$ T_k2 = RandAbc (); // random key 2$ Vstr = file_get_contents ($ filename );$ V1 = base64_encode ($ vstr );$ C = strtr ($ v1, $ T_k1, $ T_k2); // replace the corresponding characte

function RandAbc($length=""){//返回随机字符串$str="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";return str_shuffle($str);}$filepath=‘index.php‘;$path_parts= pathinfo($filepath);$filename=$path_parts["basename"];$T_k1=RandAbc();//随机密匙1 $T_k2=RandAbc();//随机密匙2$vstr=file_get_contents($filename);//要加密的文件 $v1=base64_encode($vstr);$c=strtr($v1,$T_k1,$T_k2);//根据密匙替换对应字符。 $c=$T_k1.$T_k2.$c;$q1="O00O0O";$q2="O0O000";$q3="O0OO00";$q4="OO0O00";$q5="OO0000";$q6

);$ Encode = base64_encode (gzdeflate ($ contents); // start encoding$ Encode =' ";Return file_put_contents ($ filename, $ encode );}Return false;}// Call a function$ Filename = 'Dam. php ';Encode_file_contents ($ filename );Echo "OK, encryption complete! "?> Encryption Method 2: The code is as follows: Function RandAbc ($ length = "") {// returns a random string$ Str = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz ";Return str_shuffle ($ str );}$ Filename = 'index. php'; // file t

The Code is as follows: Copy code Function RandAbc ($ length = "") {// returns a random string$ Str = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz ";Return str_shuffle ($ str );}$ Filename = 'dam. php ';$ T_k1 = RandAbc (); // random key 1$ T_k2 = RandAbc (); // random key 2$ Vstr = file_get_contents ($ filename); // the object to be encrypted$ V1 = base64_encode ($ vstr );$ C = strtr ($ v1, $ T_k1, $ T_k2); // replace the corresponding character with the key.$

, limit the amount of investment (up to 20,000 yuan)Next we analyze Ejr's static reward system concretely.EJR Static reward system1, the provision of help, 4000-20000 yuan, a multiple of 1000 yuan (the new member for the first time to provide assistance can be 2000 yuan)2, static three stages of the payment:Using the original 1+1+1 scientific modelQ1: (1-5 days match) proportion 20% Day 1%Q2: (6-10 days match) proportion 50% Day 1%Q3: (11-15 days matc

/*** Function: Some number of prime factor only 3, 5, 7, find the number of K.*/Two methods:Method One:/** * Idea: Multiply the numbers in the list with 3,5,7 to find the decimal places that are not yet added to the list. * Each time AI is added to the list, a temporary list is used to store 3ai,5ai and 7Ai. To generate ai+1, search the temporary list to find the minimum value. * @param k * @return */public static int getkthmagicnumger (int k) {if (kMethod Two:/** * Idea: (optimized) to group th

Euler angle turn four yuanvoid Cjx_from_euler (float roll, float pitch, float yaw){float Cr2 = COSF (roll*0.5f);float CP2 = COSF (pitch*0.5f);float cy2 = COSF (yaw*0.5f);Float SR2 = Sinf (roll*0.5f);Float SP2 = Sinf (pitch*0.5f);float sy2 = Sinf (yaw*0.5f);Q1 = cr2*cp2*cy2 + sr2*sp2*sy2;q2 = Sr2*cp2*cy2-cr2*sp2*sy2;Q3 = Cr2*sp2*cy2 + sr2*cp2*sy2;Q4 = CR2*CP2*SY2-SR2*SP2*CY2;}#define RAD_TO_DEG 57.29577951fRadian to AngleFloat degrees (float rad){Retur

Row-to-Column The following data is provided: Create Table sales (Year int, quarter int, Results INT) Year quarter results---------------------------------2004 1 202004 2 302004 3 152004 4 102005 1 182005 2 402005 3 122005 4 27Expected results:Year q1 q2 Q3 Q4-------------------------------------------------------2004 20 30 15 102005 18 40 12 27This SQL statement can solve this problem:Select Year,Max (case when quarter = 1Then results end) as Q1,Max