topcoder wipro

[j]*x[K] + b[j]*y[K] + c)sQ (d)* (sQ (a[j])+sQ (b[j]))) ans2++; } ans = max (ans, ans2); } } for(inti =0; I x. Size (); i++) { for(intj = i +1; J x. Size (); J + +) {Double X1 = (x[I] +x[j]) *0.5, y1 = (y[I] +y[j]) *0.5; for(intK =0; K 4; k++) {Double c =-(a[k] * x1 + b[k] * y1);intAns2 =0; for(intL =0; L x. Size (); l++) {if(sQ (a[k]*x[l] + b[k]*y[l] + c)sQ (d)* (sQ (a[k])+sQ (b[k]))) ans2++; } ans = max (ans, ans2); } } }returnAns }}tt; Copyri

Topcoder srm 623 solution report We recommend that you use the plug-in greed 2.0, which is very useful. But I don't know how to add test data by myself. I will study it next time.Greed 2.0 https://github.com/shivawu/topcoder-greed250ptThere are n trees on the ring runway, marked as 1 -- n. Some trees are recorded when Alice is running. The number is used to calculate the minimum number of laps.Question: If

I wrote a topcoder exercise question a few days ago. +Code+ CommentsArticleNow, I will write the second article in this series.Note: There will be three articles in this series, a complete set of SRM questions I have done before, with 250, 500, and 1000 points, this article will introduce the 500 points. afterwards, I will occasionally take the time to participate in the latest SRM, and then offer the questions and answers to them :) Source: srm250 d

Topcoder srm287 div2 report Match Date: Saturday, February 4, 2006REPORT Date: Thursday, February 09,200 6 Preface:This is the first time to participate in topcoder. Although the three questions were submitted before the conclusion, but the accuracy was very low, so not only gave another person a challenge, but also left only one question after system test. However, we are lucky because problem-600 is a tou

[ -][ -][ -][ -];intMain () {FO (RPS); N=gi; for(intI=0; i) {R[i]=gi; R[i]/= -; P[i]=gi; P[i]/= -; S[i]=gi; S[i]/= -; } for(intA=0; a) {dp[a][0][0][0]=1.0; for(intI=0; i) for(intj=i;j+1; j--) for(intk=i-j;k+1; k--) for(ints=i-j-k;s+1; s--) { if(i!=a) {Dp[a][j+1][k][s]=dp[a][j+1][k][s]+1.0* (j+k+s+1)/(i+1) *r[i]*Dp[a][j][k][s]; Dp[a][j][k+1][s]=dp[a][j][k+1][s]+1.0* (j+k+s+1)/(i+1) *p[i]*Dp[a][j][k][s]; Dp[a][j][k][s+1]=

)==0) ans =ABS(x) +ABS(y);ElseAns =ABS(x) +ABS(y) +2; }Else if(x 0 y 0) {if((x1)==1|| (y1)==1) ans =ABS(x) +ABS(y) +2;ElseAns =ABS(x) +ABS(y) +4; }Else if(X >0 y 0) {if((x1)==1|| (y1)==0) ans =ABS(x) +ABS(y);ElseAns =ABS(x) +ABS(y) +2; }Else if(X 0 y >0) {if((x1)==0|| (y1)==1) ans =ABS(x) +ABS(y);ElseAns =ABS(x) +ABS(y) +2; }returnAns }};The first method of code#include #include #include #include using namespace STD;structdata{intx, y;intIdintD;} d[100010];intnd queueQintTin

, found that there is a better wording, do not need to pre-processing what, direct O (n) sweep, with two variables sentenced to the line.Best Code#include using namespace STD;classniceorugly{ Public:BOOLIsvol (Charc) {returnc = =' A '|| c = =' E '|| c = =' I '|| c = =' O '|| c = =' U '; }stringDescribestrings) {BOOLCan1 =0;intNV, NC; NV = NC =0; for(inti =0; I 0; i++) {if(S[i] = ='? ') nv++, nc++;Else if(Isvol (S[i])) nv++, NC =0;ElseNV =0, nc++;if(NV >=3|| NC >=5) Can1 =1; }BOOLCan2 =1; NV = NC

{7} {2} Returns:2 There is three teams. Your team have 1 point and each of the other teams have 7 points. With three teams, the remaining matches is determined Uniquely:each pair of teams must play a single match against each Other. The best possible final result for your team was

Give you a 01 matrix, find the largest of the 01 alternating matricesBecause n Max is only 100, so direct violent promiscuityFirst, the line I, all columns up the legal length, and then enumerate the column J as the leftmost columns, calculate the maximum matrix can be obtained/************************************************************************* > File name:2.cpp > Author:al ex > Mail: [email protected] > Created time:2015 May 07 Thursday 15:07 58 seconds ***********************************

", 27) returns 411787 1000 question: This is the Super simplified version of the "Gemma Maze". Given a board, I would like to ask how many moves are possible, A move operation exchanges an element with the eight elements around it (if the eight elements exist ), it is required that three consecutive lines or columns of characters can be generated after the exchange. You can simulate it and implement three functions by yourself: The exchange function to determine whether the current exchange take

A: eliminate two adjacent equal characters. I really don't like STL .. #include B: Give a tree with N nodes, and find the maximum m value (n First, Floyd finds the distance between all vertices. Then, the solution is enumerated in a way similar to the State compressed DP. Then compare the maximum value. #include C: Exercise your thinking. Reference others' practices: Use an array similar to a suffix. It's just that the array sets are really drunk. My solution is to find the minimum string that

. However, if Java is not downloaded, You have to download the Java Plug-in and install it, the first interface in the exercise will appear, so there is nothing to say about it. Another point in the exercise is that when the compiler is added, it is not mentioned in the exercise. Although it is very easy to explain, after clicking Add, a dialog box will pop up, including name entrypoint and class path. You need to fill in this item by yourself, you can't just fill it out one by one as shown in t

Topcoder srm305 div1 report Match date:Wednesday, May 31,200 6 REPORT Date:Sunday, June 4, 2006 Preface: The questions are not carefully read, and the algorithms are not solid. In short, you still need to learn and learn with an open mind. Contents Preface: Contents: Problem 250-unfairdivision: Problem 500-interleavepal: Problem 900-powercollector: Links: Problem 250-unfairdivision: For a simulation question with a small trap, a B C

Topcoder srm294 div2 report Match date:Saturday, March 25,200 6 REPORT Date:Tuesday, March 28,200 6 Preface: It is a pity that this competition was offered with a bonus, but I did not have the first two in the first two places. I am doing this with Xiao cross and I feel that he is very impetuous. If I don't cooperate with me, it will always affect me. Finally, his second question failed to pass, and his ranking was not high. The challenge stage i

Topcoder SRM 638 DIV 2 (great miracle), topcodersrm Water is a brute force attack. A great miracle. Problem Statement There is a narrow passage. Inside the passage there are some wolves. You are given a vector SizeThat contains the sizes of those wolves, from left to right.The passage is so narrow that some pairs of wolves cannot pass by each other. More precisely, two adjacent wolves may swap places if and only if the sum of th

TopCoder SAM 632 DIV2, topcoderdiv2 250: simple question class RunningAroundPark {public:int numberOfLap(int N, vector 500: Find the rule, simple question class PotentialGeometricSequence {public:int numberOfSubsequences(vector 1000: backpack typedef long long int LL;const LL mod=1000000007LL;class GoodSubset {public:int numberOfSubsets(int goodValue, vector

Why do I feel pretty good when I click it? I can only make one question = during the competition. =250 points: Big Water question, according to the question rules to translate a string into numbers, direct code: GitHubBy traversing the numbers, I can see that the solution of the great god is to separate the characters with the '-' symbol, and then accumulate the length of each segment.500 points: Given a string of numbers and 1 ~ 9 calculate the probability of each number, and then output the fi

250: the grid has two colors. The maximum value of the longest continuous color in a column in the grid is the same. Solution: violence. Solution code: // BEGIN CUT HERE/**/// END CUT HERE#line 7 "TaroGrid.cpp"#include View code 500, ask if you can make each location have at most one cat. Solution: sort the vertices of a cat and put all the cats on the left as much as possible. If the cat cannot be placed on the left or there is no repeating interval, it is impossible. Solution code: 1 // BEGIN

Problem Statement You are a goblin miner. Your job is to mine gold. Picture yourself located in a mine. the mine can be seen as a rectangular grid of (n + 1) times (m + 1) cells. rows are numbered 0 through N, columns 0 through M. You will work in the mine for several days. you can choose the cell where you will work today (on day 0 ). on each of the next days, you can either stay in the cell where you were on the previous day, or you can move to any other cell in the same row or in the same col

The brain hole is too big. Simple things are complicated and deserve div2; A: water, basic judgment a [I] B: I don't know how others do it. My number is 100 * n. I can't think too much. I forget that it is a continuous series. We can enumerate the tolerances and find the number of tolerances. C: I think of map, but I am too confused to write it in just a few minutes .. But it is not necessarily written .. It feels good to come in to DP .. We can find that the product is actually less .. Then, j