toy maven

Title DescriptionSmall South has a cute toy villain, and they have different occupations.One day, the dolls hid the little South's glasses. Small South found that the toys were surrounded by small people, some facing the inner circle, and some facing outside. Such as:Then singer told Little South a puzzle: "The glasses hidden in my left number 3rd toy villain right number 1th

BZOJ1010 Toy Box Toy Description Professor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to pressIt can turn any item into a pile and then into a special one-dimensional container. Professor P has the number 1..N 1. N-N Toys, Part I I toys after compression into a one-dimensional length of Ci c_i. For ease of fi

Factory is a design pattern in common usage. Implement a toyfactory which can generate proper toy based on the given type.ExampleToyfactory tf = Toyfactory ();Toy Toy = Tf.gettoy (' Dog ');Toy.talk ();>> WowToy = Tf.gettoy (' Cat ');Toy.talk ();>> MeowThe problem is still to examine the factory pattern factory pattern, with the previous shape Factory no differenc

This article is copyright ljh2000 and Blog Park is shared, welcome reprint, but must retain this statement, and give the original link, thank you for your cooperation.this article ljh2000Author Blog: http://www.cnblogs.com/ljh2000-jump/Reprint please specify the source, infringement must investigate, retain the final interpretation right! DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compress

1010: [HNOI2008] Toy boxing toy time limit: 1 Sec Memory Limit: 162 MB Submit: 8678 Solved: 3456 [Submit] [Status] [Discuss] DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to pressIt can turn any item into a pile and then into a special one-dimensional container. Prof

"The main topic"Professor P has the number 1 ... N Toys, Part I toy length is ci. For ease of finishing, Professor P requires that the number of toys in a one-dimensional container be continuous. If the toy I toys to the J toy into a container, then the length of the container will be X=j-i+sigma (Ck) iIdeasToo lazy to say, the WC Song Nio Teacher's courseware to

1010: [HNOI2008] Toy boxing toy time limit:1 Sec Memory limit:162 MBsubmit:7874 solved:3047[Submit] [Status] [Discuss] DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to compress, which can turn any item into a pile and put it into a special one-dimensional container. Professor P has th

1010: [HNOI2008] Toy packing toyTime Limit: 1 Sec Memory Limit: 162 MBSubmit: 7449 Solved: 2854DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to compress, which can turn any item into a pile and put it into a special one-dimensional container. Professor P has the number 1 ... N Toys, Part I toys after compression into a one-dimensional

Test instructionsThere are n toys, to be divided into groups, toys with the same width, but the length of C may be different . Give the order of n toys, any number of consecutive toys can become a group. The cost of the interval [i,j] becomes a group of cost= (J-i+sigma (Ck)-L) 2 and I. Given N and L and the length of each toy, what is the sum of the costs after the question is grouped? (nIdeas:Note: The cost is not a straight line function, the total

1010: [HNOI2008] Toy boxing toy time limit:1 Sec Memory limit:162 MBsubmit:9812 solved:3978[Submit] [Status] [Discuss] DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to pressIt can turn any item into a pile and then into a special one-dimensional container. Professor P has the number 1

1010: [HNOI2008] Toy packing toy DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to pressIt can turn any item into a pile and then into a special one-dimensional container. Professor P has the number 1 ... n Toys, item I ToysAfter compression becomes a one-dimensional length of ci. For

Slope optimization. The first time to write ... Copy from Proverbs ...#include 　　 1010: [HNOI2008] Toy boxing toy time limit:1 Sec Memory limit:162 MBsubmit:8943 solved:3554[Submit] [Status] [Discuss] DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to pressIt can turn any item i

The first time to write the slope optimization of the problem is good ah = =But the question seems to be a dumb tat,And then this is the article ... http://wenku.baidu.com/link?url= Uqoesurresum4nve5zachn8kak5hgztj5umfmzegjfqs6uvehq2s8zh7iitt7din47sfxztvy041l5tzdvltl1wsua35umiwfp8gqnpnuesS[i] is the prefix of c[i] and, F[i] represents the minimum cost of a 1th item to the first item.The easy-to-get DP equation is f[i]=min (f[j]+ (s[i]-s[j]+i-j+1-l) ^2).Set T[i]=s[i]+i, then F[i]=min (f[j]+ (t[i]

i=j;i - #defineD (i,j,n) for (int i=j;i>=n;--i) + #definePB Push_back A using namespacestd; at intGetint () { - intv=0, sign=1;CharCh=GetChar (); - while(ch'0'|| Ch>'9'){if(ch=='-') sign=-1; Ch=GetChar ();} - while(ch>='0'ch'9') {v=v*Ten+ch-'0'; Ch=GetChar ();} - returnv*=Sign ; - } in Const intn=50010; -typedefLong LongLL; to /******************tamplate*********************/ + LL C[n],s[n],f[n]; - intQ[n],l,r; the DoubleSlopintKintj) { * return Double(F[j]+s[j]*s[j]-f[k]-

The main topic: The n number is divided into groups, and the number of each group in the original array should be continuous, each group will incur the cost of sum (i)-sum (j) +i-j-1-m,m is known constant. Minimum cost.Topic Analysis: The definition of DP (i) represents the minimum cost of grouping the first I elements, and the state transition equation is obvious:DP (i) =min (DP (j) +[sum (i)-sum (j) +i-j-1-m)]^2). Another f (i) =sum (i) +i, and the other G (i) =f (i) -1-m, the DP (i) can be or

Compare the base slope optimization DP See the following 2 blog postsHttp://www.cnblogs.com/proverbs/archive/2012/10/06/2713109.htmlhttp://blog.163.com/myq_952/blog/static/863906320112711750378/Main summary of slope optimization steps1. Demonstrate the persistence of better decision points for subsequent state impact2. Slope equation: Generalized to the left is the j,k, the right is the form of I3. Rules governing the maintenance of queues4. See if the decision is monotonous, if not, how to main

Label: bzoj1010 slope optimization dynamic Gauge The solution to the first slope optimization question is still not very thorough. I can recommend a blog here. Http://blog.sina.com.cn/s/blog_5f5353cc0100jx41.html Well written, but it may not be clear in some places. Let me explain my understanding of slope optimization: It is an optimization that finds a dynamic planning question, TLE, and then it happens to be in line with some crazy nature. In essence, it is limited to create

Toy Puzzle (Toy) "Problem description" Small South has a cute toy villain, and they have different occupations.One day, the dolls hid the little South's glasses. Small South found that the toys were surrounded by small people, some facing the inner circle, and some facing outside. The following figure: At this time singer told small South a puzzle: "The glasses h

simulation has always been the NOIP must test a type of question is also the most simple type of questions generally speaking, this problem takes the least time and should try to take the most points, so as my "Noip real Problem" series of the first article on first say a simulation problem Topics① Toy Puzzle "Noip Improvement Group" 2016d1t1 [difficulty]0.8 [tag]② Magical Magic Square "Noip raise Group" 2015d1t1 [difficulty]0.9 [tag]

Beijing Hui Tianwei Technology Co., Ltd. with the industry mission, with its Hori brand high-end industrial 3D printer Z300, Z500, Z600 debut CTE Asia's largest toy exhibition (Booth number: W3A50). 2018CTE Asia's largest toy baby industry trade show, the first to invite Hong Rui as the only 3D printing company to participate in this exhibition, has contributed to the 3D printing technology and the