toy maven

Descriptionjasio is a three-year-old boy, he likes to play toys, he has n different toys, they are placed on a very high shelf so jasio can't get them. In order to have enough space in his room, there will be no more than K toys on the floor at any moment. Jasio playing with toys on the floor. Jasio's mother stayed with his son in the room. When Jasio wants to play with the other toys on the floor, he will take it himself, if he wants to play the toy

[bzoj]1010 Test Instructions: Professor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to pressIt can turn any item into a pile and then into a special one-dimensional container. Professor P has an N-N toy numbered 1...N 1...N, and the first toy passesAfter compression becomes a one-dimensional ci ci. For ease of

1010: [HNOI2008] Toy boxing toy time limit:1 Sec Memory limit:162 MBsubmit:7537 solved:2888[Submit] [Status] [Discuss] DescriptionProfessor P was going to see the Olympics, but he couldn't give up his toys, so he decided to ship all the toys to Beijing. He uses his own compressor to compress, which can turn any item into a pile and put it into a special one-dimensional container. Professor P has th

negative sign ;The question starts with int, WA.1#include 2#include 3 #defineRep (i,j,k) for (int i = j; I 4 #defineDown (i,j,k) for (int i = j; I >= K; i--)5 #defineSqr (i) (i) * (i)6 #defineMAXN 500107 #defineLL Long Long8 using namespacestd;9 Ten LL SUM[MAXN], C[MAXN], DEP[MAXN], DP[MAXN]; One DoubleSlopeintIintj) { A return 1.0* (DP[I]+SQR (sum[i])-DP[J]-SQR (Sum[j])/(sum[i]-sum[j]); - } - the intMain () - { - LL N, l, X; -scanf"%lld%lld", n,l); +c[0] =0; -Rep (I,1, N) { +scanf"%lld

Outputstandard output On Children's Day, the child got a toy from delayyy as a present. However, the child is so naughty that he can't wait to destroy the toy. The toy consistsNParts andMRopes. each rope links two parts, but every pair of parts is linked by at most one rope. to split the toy, the child must remove all

Codeforces Round #250 (Div. 2) C. The Child and Toy details,Outputstandard output On Children's Day, the child got a toy from Delayyy as a present. However, the child is so naughty that he can't wait to destroy the toy. The toy consistsNParts andMRopes. each rope links two parts, but every pair of parts is linked by at

1055: [HAOI2008] Toy name time limit:10 Sec Memory limit:162 MBsubmit:1119 solved:653[Submit] [Status] [Discuss] DescriptionSomeone has a set of toys and wants to name the toys. First he chooses any one of the four letters of wing as the basic name of the toy. Then he will, according to his preference, use any of the letters in the name "WING" to replace any of the two letters, so that his name can

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2556. [NOIP2016] toy puzzle, 2556noip2016[Description] Xiaonan has a set of cute little toys, which have different occupations. One day, these little toys hid Nan's glasses. Xiaonan found that the toys and children were circled in a circle, and some of them looked inside and outside China. For example: At this time, singer told Xiaonan a puzzle: "glasses are hidden in the left of the first 3rd toy peop

instances. the first line consists of six integers n, m, X1, Y1, X2, y2. the number of cardboards to form the partitions is n (0 Coordinates of the upper-left corner and the lower-right corner of the box are (x1, Y1) and (X2, Y2), respectively. the following n lines each consists of two integers UI Li, indicating that the ends of the ith cardboard is at the coordinates (ui, Y1) and (Li, Y2 ). you may assume that the cardboards do not intersect with each other. the next M lines each consists of

In Ubuntu, configure fitx-Fun Input Toy for Linux (the default language is English). You know that the sogou PinYin Input Method and Google Pinyin Input method are also very useful in Windows, but the built-in Chinese Input Method in Ubuntu is not flattering, fortunately with Fun Input Toy for Linux, very easy to use, is a Google Code Project, specific features and see [url] http://code.google.com/p/fitx/ [