http://acm.hdu.edu.cn/showproblem.php?pid=1421
Chinese questions
Idea: First to find out how to combine all the items into a pair of, the problem requires the smallest fatigue, that is, a pair of two items in the weight of the smallest difference. Then you need to use the sorting, the items from small to large, from traversing the items until the second to the last, each item and the next item is combined into a pair, it will be found that if we first selected this pair, then the next pair can n
In an XML layout file, we can set either PX or a DP (or dip). In general, we would choose to use a DP, which would ensure a consistent layout on a machine with different screen resolutions. But in the code, how do you handle it? Many control methods provide only methods for setting PX, such as setpadding, and do not provide a way to set up a DP. At this point, if
bearing C1,C2, asking how many times it will take to carry the furniture. Thinking of solving problems
Bundle n pieces of furniture, use 1,0 to indicate whether the current state chooses this furniture, carries on the state compression;Then the total number of binding methods that is the total number of States is (1In the mark[] in the selection of independent (does not contain the same furniture) bundle status of 01 backpack, each bundle state I is equivalent to an item, its volume is mark[i],
Division DP The second problem, Wikioi 1039, and the first question product The biggest idea is different.
Title requirements:Divide an integer n into the K section and ask how many different divisions there are.true and thought :In fact, with some of the primary school Olympic Games a bit like, we first look at an example:7 divided into 3 parts, there are four ways:1,1,5;1,2,4;1,3,3;2,2,3.How do we think when we think about things in our brains? Obvi
. The second line contains n integers pi (1≤pi≤i). Each pi denotes the number of the "the", that someone can reach, if he'll use the second portal in the i-th.
OutputPrint a single number-the number of portals moves the boy needs to go out of the maze. As the number can be rather large, print it modulo 1000000007 (109 + 7).
Sample InputInput21 2Output4Input41 1 2 3Output20Input51 1 1) 1 1Output62
1, to go forward only through the first way (the number of markers is even), that is, the first time
Question:
Given N deep
1. Construct a weighted tree with N nodes with a maximum depth of deep. Each node can have up to two sons.
2. The value of each node is 2 ^ 0, 2 ^ 1 · 2 ^ (n-1). Any two node values cannot be the same.
3. For a node, if he has a left and right son, then the sum of the Left subtree and the sum of the right subtree
Q:
Number of constructor methods.
Ideas:
DP
#include
HDU 4359 easy tree
DP big combat-combination backpack and dp big combat backpackDescription
Combination backpack: Some items can be taken only once (01 backpack), some items can be taken unlimited times (full backpack), and some items can be taken up to a maximum of times (multiple backpacks ).
DD Daniel's pseudocode for I = 1 to N if item I belongs to 01 backpack ZeroOnePack (F, Ci, Wi) else if item I belongs to complete bac
Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 2242
Given a graph, each vertex has a weight and may have a duplicate edge. You need to delete an edge to divide the graph into two parts, find the difference between the minimum weight and the two parts. If there is no way to divide them into two parts, output impossible.
Solution: Graph Theory and tree DP. If the given graph is a tree, you can use the tree
1 (longest public substrings (note the difference between the longest public substrings ))
The two strings str1 and str2 have the following lengths: (L1, L2)
DP [I] [J] represents the length of the common subsequence that can be reached by two strings ending with the I and J, respectively, because the following involves I-1 and J-1, in this case, we generally start from I = 1 and j = 1 to I J
If (STR [I-1] = STR [J-1])
Title Link: Bzoj Valley\ (O (n^2) \) DP is very good to write, for the current I from before satisfy the condition of J Select a maximum value,\ (dp[i]=d[j]+1\)for(int j=1; jif(a[j]//序列只会变换一次 dp[i]=max{dp[j]+1};Transfer to meet two conditions:\ (a[j]A two-dimensional partial order problem, CDQ, tree set tree ca
Topic Link: [POJ 3666] Making the GRADE[DP]The analysis:A sequence of n numbers that allows any number of numbers to be added or reduced in a sequence, asking the minimum number of changes to allow the original sequence to become monotonically increasing or monotonically decreasing.Ideas for solving problems:For a number modification, we modify it to be the best choice for some of the numbers in the sequence (I can't understand it by the counter examp
.
Each case contains a string of lowercase letters denoting the string for which we want to generate a palindrome. Safely assume that the length of the string would be positive and no more than. Output
For each case, print the case number and the minimum number of characters required to make string to a palindrome.
Sample Input
Output for Sample Input
6AbcdAaaaAbcAaBAbababaabababaPqrsabcdpqrs
Case 1:3Case 2:0Case 3:2Case 4:1Case 5:0Case 6:9
Problem SETT
Treats for the Cows
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 4375
Accepted: 2226
Description FJ have purchased N (1 The treats is interesting for many reasons:the treats is numbered 1..N and stored sequentially in single file in a long Box that's open at both ends. On any day, the FJ can retrieve one treat from either end of the stash. Like fine wines and delicious cheeses, the treats improve with age and command greater pri
Test instructions: Give a string, you want to put him into a palindrome, ask the minimum cost.
Solution: Initially thought only on both sides to add the letter, and then always WA. Later took someone else's program found can be in the middle of the letter.
DP, DP[I][J] represents the minimum cost of i-j string into palindrome strings.
Transfer equation: If the characters of I and J are the same, then the mi
http://poj.org/problem?id=2342
http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=17663
Test instructions
A company will hold a party, but in order to make the party more active, each party will not want to see his direct boss at the party, now known to everyone's active index and boss relationship (of course, there is no link), ask who (how many people) to invite who can make the total activity of the party is the largest.
States are the trade-offs of each point.
can be used
Test instructions
Learning sister very much like the string, so the learning brother gave her two strings as a gift.Two strings are x, Y, respectively. She is very happy, but she also wants to test Kaoxue younger brother in happy.She defines the length of the longest common subsequence of the x and Y (the subsequence is not necessarily contiguous within the string, and a string with a length of L has a 2L subsequence, including the empty empty sequence).Now, my sister took out all of X's subsequ
after playing this game optimally.Sample Input44-10-20 741 2 3 40Sample Output710
Parsing: Classic Interval DP
Same HDU 4597 Play game (game + interval DP)
DP[L][R] Indicates the maximum value that can be reached when the interval is left L~r
Sum[i] represents all numbers from the range start point to the current point and
There are four cases of each fetch:
Test instructions: 2*n Square, known 1*2,2*1 Domino arrangement, now has 3 colors, ask the adjacent domino color to different dyeing scheme? n
The x is vertical and the y is horizontal. The former I-1 group staining scheme is res
Last group: Xi-1,xi XI There are two options, the last is two horizontal with two horizontal, then any one of the previous scheme, and finally the two transverse have 3 kinds of dyeing program. Other similar
#include
Test instructions: Given the string s, if the stri
Bar Code problem dp + Method for Finding the serial number of a sequence in a certain arrangement, bar code dp
Question
A Bar code is a symbol that appears alternately between a Light Bar and a Dark Bar and starts with a Dark Bar. Each Bar occupies several units of width. Figure 33-1 shows a bar code containing four lines, extending the width of 1 + 2 + 3 + 1 = 7 units.In general, BC (N, K, M) is a program
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