triplehead2go dp

+ 3/8 + 5/8 + 4/8 + 4/8 + 8/4 = 6.00"Scoring method" is not part of the subject, your program output only and the answer to the gap of not more than 0.01 when the ability to obtain the test of the full score, otherwise do not score."Data size and convention" for 100% of data, 1 Test pilot number N m remark1 n=10 m = n-1 Guarantee Diagram is chain-like2 n=100 only has node 1 in degrees greater than 23 n=1000/4 n=100000/5 n=100000/6 n=10 m = n/7 Number of nodes in n=100 ring 8 Number of nodes in

", stdin); Freopen ("Thd.out","W", stdout); scanf ("%d%d%d",p,q,N); for(intI=1; i) Soldier[i].read (); for(intI=0; i) for(intj=0;j1; j + +) F[i][j]=-inf;//the visiting following, but also the possible to visited!!!f[0][1]=0;//given one chance at first!! for(intI=1; i) for(intj=0; j) { if(J >= Tour (i) +1) Smax (F[i][j], f[i-1][j-(Tour (i) +1)]); if(J >= Tour (i)-Homme (i)) Smax (F[i][j], f[i-1][j-(Tour (i)-Homme (i))] +Cost (i)); } printf ("%d", *max_eleme

Test instructions[topic link] Copyright reason is not issued.Give a tree to find the maximum value of the desired distance between any two pointsSolA more halal question.Set \ (f[x]\) indicates the desired number of steps from \ (x\) to the father of \ (x\)\ (g[x]\) indicates the desired number of steps coming from the father\ (d[x]\) indicates the degree of the \ (x\) nodeNot difficult to get the equation \ (f[x] = \sum_{to \in son[x]} F[to] + d[x]\)\ (G[x] = g[fa[x]] + \sum_{to \in son[fa[x]]

Reprint Please specify source: http://blog.csdn.net/vmurder/article/details/42879121Test instructions: After I have entered, I have the correct options for AI, and there are ai-1 options that someone might choose and how many questions to expect.The expectation of the problem is irrelevant to the two questions.Only need to discuss each question separatelyA correct option, b possible optionFor some of the right options, someone has a 1/b probability of doing the right thing.Total odds: 1/b/a.The

Game (range dp) with a 10891 sum (range dp), 10891dpZookeeper Given n numbers, A and B can select any number from both ends of the number, and can only be selected from one end at A time. And a B tries its best to make the result of his choice the largest. It can be understood that each step of a B is the best. If A is selected first, the maximum difference between A and B is. Train of Thought: use d [I] [j

The Ghost Blows light Time Limit: 2000/1000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)Total submission (s): 2240 accepted submission (s): 688 Problem description My name is Hu Bayi, robing an existing ent tomb in Tibet. the tomb consists of N rooms (numbered from 1 to n) which are connected by some roads (pass each road shocould cost some time ). there is exactly one route between any two rooms, and each room contains some treasures. now I am located at the 1st room and the exit

Test instructions: A large rectangle of H * W, in which some of the squares have trees. Now you need to find a small rectangle of H * W so that the number of trees in the tree is the most, ask how many treesis a two-dimensional tree array base usage, the edge input edge updates the point of the tree, after the completion of the tree you can query each (x, y) to the vertex of the rectangle of how many persimmon trees.Algorithmic complexity O (H*W*LGH*LGW)However, since the Persimmon tree is not

The problem is described in a straight line there are n heap of stones, each heap has a certain number, each can be two piles of adjacent stones merged, merged and placed in two piles in the middle position, the combined cost of the sum of two piles of stones. To combine all the stones into a pile of minimum costs. Input format input The first line contains an integer n, which represents the number of heaps of pebbles.The next line, containing n integers, gives the size of each heap in order. Th

10739-string to Palindrome Time limit:3.000 seconds Http://uva.onlinejudge.org/index.php?option=com_onlinejudgeItemid=8category=114page=show_ problemproblem=1680 Idea: For each interval [I, J]: If str[i] = = Str[j],dp[i][j] = dp[i + 1][j-1]; If Str[i]!= str[j], dp[i][j] = min (dp[i + 1][j],

From the start of the Android program, I was told that the common sense 1. Length width of the value to use the DP as a unit into the Dimens.xml file 2. The value of the font size to use the SP as a unit, also into the Dimens.xml file Then, there is no then, as if the subtext is that, you remember to use on the line. One day, when we accidentally put the font into a DP, it can work, and the effect of th

character. Output Line 1: "A single" with "a single" is the minimum of the given name tag. Sample Input 3 4 ABCB A 1000 1100 B-M C- Sample Output 900 Hint If We insert an ' a ' on the ' end of ' to get ' ABCBA ', the cost would is 1000. If we delete the "a" on the "BCB" of "beginning", the cost would is 1100. If we insert "BCB" at the begining of the string and the cost would to be--+ + = 900, which is the minimum. Source Usaco 2007 Open Gold The main effect of the topic:A string

"URAL 1900" brainwashing Device (preprocessing interval and +DP) Main topic:N Cities 1~n, Block I city and I+1 have a road.The first city to i+1~n each city has passenger traffic, if everyone from i->j, to go through I and J each edge once.The government decided to shorten the distance of K-roads (1 For everyone, from I to J, if any road in the middle is shortened, he will be happy.Ask how many people are happy and then output the shortened road numb

Title Description DescriptionSet A and B are 2 strings. To convert string A to string B with a minimum of character manipulation. The character operations described here include:(1) Delete a character;(2) inserting a character;(3) Change one character to another character.The minimum character operand used to transform string A into string B is called the editing distance of the string A through B, which is recorded as D (A, A, a). Try to write the program, on the given 2 strings A and B, calcul

"URAL 1244" gentlemen (dp+ record Path) Main topic:n cards, each with value. Given a value of V, ask if there is a unique combination of combinations of V.Some words output is not in the combination of card number, no words output 0, multi-Solution output-1. 01 Backpack + Record the path. One corner to turn is that for the current value, only the item number of the first arrival is recorded.After that, the multiple solutions are no longer recorded. Si

This topic just began to think for a while, because it is a tree-like DP topic, so did not see it is 01 backpack (the focus is to reverse), reverse this point has not been thought out why, because the treasure only one, and 01 backpack is the same meaning (actually I now I do not want to understand that since it is already two-dimensional, And why to reverse it), the state transfer equation is Dp[u][j]=max

is very big, output the answer modulo 109 + 7. Input The only line contains-integers n and K (1≤n, k≤106), separated by a space-the length of the permutations and th e parameter K. Output Output the answer to the problem modulo 109 + 7. Examples input 5 2 Output 22 Input 5 3 Output 6 Input 6 3 Output 84 Note Permutations from second example: [4, 1, 2, 3, 5], [4, 1, 3, 2, 5], [4, 2, 1, 3, 5], [4, 2, 3, 1, 5], [4, 3, 1, 2, 5], [4, 3, 2, 1, 5]. Set Dp

integers indicating whether a square are fertile (1 for Fertile, 0 for infertile) Output Line 1:one integer:the number of ways that FJ can choose the squares modulo 100,000,000. Sample Input 2 3 1 1 1 0 1 0 Sample Output 9 Hint number the squares as follows: 1 2 3 4 There is four ways to plant only on one squares (1, 2, 3, or 4), three ways to plant on both squares (, or), 1 WA Y to plant on three squares (134), and one-to-plant on no squares. 4+3+1+1=9. The main topic: to give you a pie

Polygon game (DP), game dpDescription A polygon game is a single player game.NPolygon composed of vertices. Each vertex is assigned an integer, and each edge is assigned an operator "+" or "*". All edges are sequentially rounded up from 1NId. In step 2 of the game, delete an edge. SubsequentN-Perform the following operations in Step 1: (1) Select an edgeEAndETwo Connected verticesV1AndV2; (2) Replacing edges with a new vertexEAnd the two vertices conn

to run 1 meters to spend v) output Description One row, n-1 number, representing 2 to N city information to the shortest time data range of Orzboshi city 3≤n≤105 3≤n≤10^5, 0≤si≤109, 0≤si≤10^9, 1≤vi≤109 1≤vi≤10^9 topic Analysis The first look may feel like a bit of water DP, presumably F[i]=min (f[j]+v[i]* (Dis[i]-dis[j]) +s[i]), Dis[i] represents the distance from 1 to I, and then J is the ancestor node of I.Then look to the data range ... I'm sure i

Test instructions: Give a matrix, (max) to (N,n) two paths (not intersect), the maximum value to be obtainedData range: 2 Ideas: Remember in the Kuangbin the most short-circuit topic there is a requirement of the same question, when it is not written out, check the solution is the biggest flow????Then asked the big guy, said the problem can also be network flow to do, but ... And then I learned about this thing called multi-threaded DP.Multithreading..???? It's not the C-language thing. It? It l