Db2+hadr+tsa High Availability Test--DB2HAICU Configure TSA for automatic failover of faults
Network architecture
Must be configured on the standby node first
[Root@db2-node02 ~]# Su-db2inst2
[Db2inst2@db2-node02 ~]$ DB2 "Get snapshot for database on GHAN"
HADR status
Role = Standby
Status = Peer
Synchronous mode = Synchronous
Connection status = Connected, 2015-12-24 08:32:52.872408
.x64_x86_64.bin.The program runs in the same Windows environment.* The program automatically decompress the package to the/tmp/lenovotools Directory. The generated collection result is searched based on the prompts of the program running.Program Collection content declaration:This program only collects technical information such as Lenovo series server hardware configuration and operating system logs, and does not collect any sensitive information such as customer data.Note:Version: 1.0.2.62 (20
This text connection: http://blog.csdn.net/freewebsys/article/details/45830613 reprint Please specify the source!1, About time seriesTime series analysis is a statistical method of dynamic Data processing. Based on stochastic process theory and mathematical statistics, this method is used to study the statistical laws of random data sequences to solve practical problems.About R Environment Building reference I wrote the article before:http://blog.csdn.net/freewebsys/article/details/45825267Refer
In signing the generated apk, jdk1.6 upgrade to jdk1.7 will have the following issues:1. Clearly signed, and the signature check apk also has signed files, but the installation is to prompt installation failure, no signature, the solutionAdd a message to the signature command:-digestalg sha1-sigalg md5withrsa Plus, you can.Old: Jarsigner-keystore test.keystore-storepass test123-signedjar signed_client.apk client.apk testNEW: Jarsigner-digestalg sha1-sigalg md5withrsa-keystore test.keystore-store
This period of time, has been trying to ionic2, play re-pick up the process of ionic found a lot of processes have been and before the process there is a great difference in the signature encountered errors, collective error is as follows:According to the online search data, said the firewall can be closed, after the experiment can not be.Commands to executeJarsigner-verbose-digestalg sha1-sigalg Md5withrsa-tsa Https://timestamp.geotrust.com/
Tags: table registration replace restore localhost has an operation log persistence1. IntroductionThe terracotta server provides a distributed data platform for terracotta products. The terracotta server cluster is known as the Terracotta Server array (TSA). The Terracotta server array can range from a single server to a basic dual-server concatenation for high availability (HA), to a multi-server array that provides configurable scale, high performan
Test instructionsGiven a string $S $.In some way, the string $S $ into no more than $K $ segment $S _1, S_2, ..., s_k$.Each $S _i$ has the largest substring $C _i$ in the dictionary order.Minimizes the maximum value $C _i$.$N \le 200000$.AnalysisThrough the suffix array, the first dichotomy suffix, and then the two-minute length, the realization of the two-point all the strings.The decision can be greedy, using the information of the suffix array, record v[i] means position I cannot be with posi
SUPERASYNC mode, the state of the standby database will be the remotecatchupshown in Figure 3.Figure 3. The status of the standby database is Remote catchupWhen the standby database is unavailable, the status of the primary database will be disconnected, as shown in 4.Figure 4. The state of the primary database is disconnected when the standby database is unavailableWhen the standby database disconnects from the primary database, the state of the standby database is remotecatchuppending, 5.Figu
http://www.tsinsen.com/A1484The inline insertion is not good, we take all the operations offline and become the delete operation.Each time you ask, for the current B-string where the starting position and its length up and down two points, and then query the interval within the valid current a string within the match point. Maintained in a tree-like array.#include using namespacestd;Const intmaxlen=200015, maxm=200015, maxk= -;intTMP,STA,EDA,STB,EDB,LEN,M,W[MAXM];Chara[maxlen*2],b[maxlen*2],s[ma
subject (MA): connects to the database on the same host as the database and CGI programs running on the WEB server of the local machine through socket, and accesses the database at the same time, communicate with each TSA through socket. Receive configuration modifications sent by CGI, distribute the modified configuration files in the database to TSA, receive data, data requests, and alarms sent by
Evaluation Address: https://cn.vjudge.net/problem/CSU-1632Descriptionin the string, all occurrences of at least 2 number of sub-strings of the secondInputfirst act an integer T (t represents the number of use case groups, with each group of use cases occupying a length of 100000 the stringOutputFor each set of use cases, output the number of substrings that appear at least two times in the stringSample Input3AabaabAaaaaAaAaASample Output545SolutionAns=sum ( max (height (i)-height (i-1), 0) )#inc
Ideas:First questionBuilt suffix array after prefix and pitch n-sa[i]-ht[i]+1 two pointsSecond questionTwo-point judgment is the number of repetitionsHow to judge, find it, sweep ht down, sum+= it with K.Attention is equal to plus one kind of various pits dad detailsDie..//by Siriusren#include using namespacestd;Const intn=1000050;intn,cnta[n],cntb[n],a[n],b[n],rk[n],sa[n],tsa[n],ht[n],t,k;Long LongSum[n],sum1[n];CharS[n];voidSA () { for(intI=1; i; f
OutputI0O7SJHINTThe length of the data string for 100% does not exceed 100000.The first twice times and then constructs the suffix array,those that meet the conditions are those +n-1 points in SA that are 1#include 2#include 3#include 4#include 5#include 6 7 #defineN 2000078 using namespacestd;9InlineintRead ()Ten { One intx=0, f=1;CharCh=GetChar (); A while(ch'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} - while(ch>='0'ch'9') {x= (x3) + (x1) +ch-'0'; ch=GetChar ();} - retur
all the same: take the small side of the same, all the same will be taken at random.The process of comparison can be violent, or it can be a suffix array.Common Greedy Code:#include #include#include#includeusing namespacestd;Const intmaxn= .;CharC[MAXN];BOOLLeft (intLintR) { while(l1) { if(c[l]!=C[r])returnc[l]C[r]; L++; r--; } return true;}intMain () {intn,cnt; scanf ("%d",N); for(intI=1; iC[i]; intL=1, R=n; Cnt=0; while(lR) { if(Left (l,r)) cout]; Elsecout]; CNT++; if(c
bit of attention, the dictionary ordering note the starting position of the same substring order, its order is the reverse of the enumeration order. In other words, we avoid falling into another hole when we are bypassing a pit.Finally, HBW mentions a method of optimizing the random string suffix array to O (n), and when the rank array has a maximum value of n, it simply break off, seemingly a simple and useful optimization#include #include#include#include#includeusing namespacestd;#defineMAXN
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